Atomic Structure, Quantum #'s, and configuration Flashcards

1
Q

What is Planck’s constant in joules?

A

Planck’s constant is represented as the letter ‘h’ and has a value h=6.626x10^-34 J*s

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2
Q

What is planck’s equation?

A

E=hf where E is energy, h is planck’s constant, and f is frequency

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3
Q

Fe2+

A

Ferrous ion

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4
Q

Fe3+

A

Ferric ion

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5
Q

1amu= ____Da

A

1 Da=1.66x10^-27kg

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6
Q

The closer an electron is the the nucleus, the _______ energy it has, and the _______stable it is.

A

less energy, more stable

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7
Q

What is the Rydberg equation and what is it used for?

A

Rydberg- calculate amount of energy emitted or absorbed by an electron.

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8
Q

Describe the differences between shell, subshell, and orbital.

A

The shell corresponds to the princial quantum number (n). It describes the energy level an electron may be found in. Subshell refers to the angular momentum (l) which gives the designations s, p, d, f. The subshells have specific shapes and orientations. The orbital corresponds to the magnetic quantum number which is the orientation in space. The s subshell only has one orbital. The p has 3 orbitals. A single orbital can only hold a max of two electrons.

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9
Q

Alkali metals bind to H to form hydrides. These compounds are acidic or basic?

A

Basic

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10
Q

What is the trend of Zeff?

A

Zeff increases across a period and up a group. When you move across a period, atomic number goes up, which means that the number of protons in the nucleus goes up, increasing Zeff. When you move down a period, however, the shielding effect goes up because there is another electron shell in the way, causing the force on the valence electrons to go down. For this reason, Zeff actually goes down as you move down the periodic table, despite the increasing charge of the nuclei.

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11
Q

How would you increase the Zeff of an atom?

A

More protons in nucleus OR fewer valence electrons. Zeff, or effective nuclear charge, increases when there are fewer non-valence electrons because there will be less shielding.

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12
Q

What is the trend for atomic radius

A

Atomic radius decreases across a period and increases down a group, so larger atomic radii are found in the bottom left and the smaller atomic radii are found in the top right. Thus, the correct order in terms of increasing atomic radius is fluorine, then nitrogen, then boron, then sodium, and finally potassium.

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13
Q

What is Ionization Energy?

A

Ionization energy refers to the energy required to free a valence electron from an element.

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14
Q

Pauli Exclusion Principle

A

Orbitals can only have max of 2 e- per orb w/opposite spins

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15
Q

Why is electron affinity exothermic for bromine but endothermic for potassium?

A

To establish a complete octet, bromine needs only one additional electron. Therefore, when bromine gains an electron, it will become more stable and release energy. Potassium, in contrast, prefers to lose an electron to have a full octet. For this element, adding another electron is unfavorable and will require energy, making it an endothermic process.

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16
Q

Heisenberg Uncertainty Principle

A

you cannot predict the exact location of where an electron will be…According to the Heisenberg uncertainty principle, it is impossible to precisely know both the exact location and the exact momentum of an electron at any given moment in time.

17
Q

What is the trend for electronegativity?

A

Electronegativity increases from left to right across a period and decreases down a group; an easy way to remember this trend is to commit to memory that fluorine, near the top right of the table, is the most electronegative element. Therefore, the correct order is sodium, then lithium, then carbon, then oxygen, and finally fluorine.

18
Q

Hund’s Rule

A

For valence subshells will fill with 1 electron each BEFORE they begin to pair

19
Q

What would the configuration of Cr be?

A

[Ar}4s13d5

20
Q

Why is Cr’s configuration [Ar]4s13d5?

A

Because electrons are removed from subshells with the highest principal quantum number FIRST and when it comes to the d-block, Cr and Cu are so close to being d5 and d10 that they take electrons from the s subshell

21
Q
A

h=6.626x10^-34 J=

22
Q

What is the Rydberg Constant?

A

2.18x10^-18 J

23
Q

Why are halides w/Alkali metals (eg NaH) good reducing agents?

A

The Alkali metal only needs to lose one electron to get a noble gas configuration so it will readily lose the H and act as a reducing agent

24
Q

The heme molecule is a porphyrin with a coordinated iron atom at the center. The heme molecule has all of the following hybrid orbitals EXCEPT:

sp.

sp2.

sp3

sp3d2.

A

sp

There are no triple bonds in the heme molecule, which would be indicative of sp orbitals.

25
Q

A new element (“L”) is discovered and found to contain 240 protons and 120 neutrons. What is the correct atomic notation for this element?

A

In standard atomic notation, the mass number (or total number of nucleons) is written above the atomic number (or number of protons). Since this element has 240 protons and 120 neutrons, it must have a mass number of 360 and an atomic number of 240.

26
Q

What is the ratio of neutrons in radon-202 to that in radon-206?

A

29:30

The number of neutrons for each isotope can be found by subtracting the atomic number of radon (86) from the relevant mass number. For example, radon-202 contains (202 - 86) or 116 neutrons. This gives us a ratio of 116:120, which simplifies to 29:30.

27
Q

What is the electronic configuration of the Co(II) center found in vitamin B12?

A

[Ar]3d7

This is a General Chemistry question that falls under the content category “Atoms, nuclear decay, electronic structure, and atomic chemical behavior.” The answer to this question is A. Co(II) is a dication and is formed from the atomic element by the loss of two 4s electrons. As a consequence, only seven 3d electrons remain in the valence shell. It is a Scientific Reasoning and Problem Solving question because you are asked to bring together theory and evidence to draw a conclusion.