Atomic Structure + Mass Spec Flashcards
What are the four stages of TOF mass spectrometry?
Ionisation, acceleration, drift, detection, analysis
Name the 2 methods of ionisation
Electro spray and electron impact
Describe electro spray ionisation
- sample is dissolved in volatile solvent
- injected into chamber through a hypodermic needle
- needle is connected to high voltage power supply
- as sample is injected the atoms each gain a proton (H+)
Describe electron impact ionisation
- sample is vaporised
- high energy electrons are fired at sample from an electron gun
-> this electron gun is a hot wire filament which emits electrons as a current runs through it - as the sample is hit, an electron is knocked off each particles forming 1+ ions
Name and describe stage 2 of TOF mass spec
acceleration
- 1+ ions are accelerating using an electric field (a -vely charged plate)
- they are all accelerated to have the same kinetic energy
- since they all have the same kE their velocity will be dependent on their mass
-> lighter = quicker, heavier = slower
Name and describe stage 3
(ion) drift
- 1+ ions then pass through a hole in the -ve plate and enter the flight tube
- the TOF of each ion depends on their velocity
Name and describe stage 4
detection
- 1+ ions collide with the -ve detector plate
- as they hit the detector plate they gain an electron, this causes a current to be produced
- the size of this current is proportional to the abundance of the ions hitting the plate
- the detector is connected to a computer which produces a mass spectrum
Give the full electron configuration of Mg
1s 2 2s 2 2p 6 3s 2
Give the shorthand electron configuration of Cr
[Ar] 4s 1 4d 5
Define ionisation energy
The amount of energy required to remove one mole of electrons from one mole of gaseous atoms to form one mole of 1+ ions
What are the four factors that affect the size of the 1st I.E
- atomic radius
- nuclear charge
- shielding
- (spin pair) repulsion
General trend of I.E across a period + why
Increase; nuclear charge increases (this decreases atomic radius) but shielding + number of shells stays roughly the same ∴ energy required increases
Exceptions to the trend (eg of period 2 but applies to 3 also)
There is a dip in 1st I.E between beryllium and boron (boron is slightly lower) as boron’s outer electron is in the 2p sub shell which is at a higher energy level than beryllium’s 2s electron
- entered a higher energy level -> slight increase in atomic radius + shielding
Dip in I.E between nitrogen and oxygen, as oxygens outer electron is paired - nitrogen’s outer electron is 2p 3 whereas oxygens is 2p 4, meaning it has spin pair repulsion. This repulsion between the two electrons makes it easier for the outer electron to be removed
General trend of I.E down a group + why
Decrease; nuclear charge increases however number of shells increases meaning atomic radius increases , this results in increased shielding and it becomes easier to remove the outer electron