Atomic Structure

Question 1

Radius of neucles

Answer 1

R= R not × (A)^1/3

Where R not = 1.33×10^-15 (10^-15= fermi meter)

(A)= atomic mass

Question 2

Energy of photon =?

Answer 2

E= hv
E= hc / lambda(wavelength)

Where h is Planck’s constant which,
= 6.626 × (10^ -34) Joule/sec
Or 6.62 × (10^ -34) Joule/sec

E= hc / lambda
= 1240 nanometer. Ev/ lambda (nanometer)

Question 3

1 nanometer in terms of armstrong

Answer 3

1 nanometer = 10 arm strong

Question 4

Conversions of:
Armstrong
Nanometer (nm)
Pico meter (pm)
Fermi meter (fm)

In meters

Answer 4

1 Armstrong = 10^-10 meter
1 nanometer (nm) = 10^-9 meter
1 pico meter (pm) = 10^-12 meter
1 fermi meter (fm) = 10^-15 meter

Question 5

For the energy of the photon (6.626× 3) / 1.6 then in terms of eV

Answer 5

E = (12400/λ) eV for λ in Å. E = (1240/λ) eV for λ in nm.