ATOMIC STRUCTURE

Question 1

Delta X into Delta p

Answer 1

h/4pie

Question 2

Delta p

Answer 2

M delta v

Question 3

h/ 4pie

Answer 3

Delta x * delta p = delta x * m delta v = 0.527 × 10^-34

Question 4

Ratio of change in position and change in momentum

Answer 4

Delta Xa / delta Xb = delta Pb/ delta Pa

Question 5

E2 - E1

Answer 5

10.2

Question 6

E3 - E2

Answer 6

1.89

Question 7

E4-E3

Answer 7

0.66

Question 8

E5- E4

Answer 8

0.31

Question 9

E6 - E5

Answer 9

0.16

Question 10

E7 - E6

Answer 10

0.1

Question 11

E3 - E1

Answer 11

12.09

Question 12

E4-E1

Answer 12

12.75

Question 13

E5 - E1

Answer 13

13.06

Question 14

E6 - E1

Answer 14

13.22

Question 15

E6 - E1

Answer 15

13.22

Question 16

Bohr atomic model

Angular momentum of an orbit

Answer 16

nh /2pie

Question 17

Ionization energy

Answer 17

Energy required to move an electron from ground state to infinity .

E 1 = - K.E = - I.E

Question 18

Excitation energy

Answer 18

Enery required to move an electron from groud state to any other excited state .

E .E = En - E1

Question 19

Separation energy

Answer 19

Amount of energy required to move sn electron from any excited state to infinity

S.E = - En

Question 20

Energy Difference

Answer 20

En2 - En1 = 13.6z² ( 1/n1² - 1/n2²

Question 21

Time & Frequency

Answer 21

T = d/s = 2pie r / v

Frequency = V / 2pier

Question 22

Total lines in emmision spectrum

Answer 22

[ (n2 - n1 )( n2 -n1 +1)] / 2

Question 23

Ryberg frequency

Answer 23

Freq . = CRz² ( 1 / n1² - 1/ n2²)

Question 24

DE Broglie concept

Answer 24

Wavelength is inversely proportion to momentum

● Wavelength = h /P = h / mv = h / underroot 2m K.E

Question 25

De broglie cpncept

When charge particle is accelerated the K.E

Answer 25

K.E = QV

WAVELENGTH = h/ underroot 2mQV

Question 26

De broglie concept

Wavelength for electron

Answer 26

= whole ubderroot 150 / v = 12.25/ v

Question 27

Circumference = n wavelength