atomic and electron structure: content Flashcards

1
Q

how is relative atomic mass Aᵣ found

A

mass spectrometry

[detail not needed for OCR]
1) sample ionised (remove an e⁻)
2) ions fragment and are accelerated by a magnetic field
3) travel a distance dependent on the ratio (m/z) of their mass (m) and charge (z) and are detected
4) charge tends to equal +1 so mass can be easily calculated

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2
Q

resolution of Mᵣ/Aᵣ

A

1 decimal place (same as periodic table)

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3
Q

isotope masses should be given to

A

the nearest whole number (can’t have half a [proton])

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4
Q

how to calculate Aᵣ from a mass spectrum

A

Aᵣ = ∑(isotopic mass * relative abundance) ÷ total relative abundance

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5
Q

sub-shells

A

s: alkali and alkaline earth metals
p: post-transition metals, metalloids, nonmetals, halogens, noble gases
d: transition metals
f: lanthanides, actinides

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6
Q

order of increasing energy (electron structure)

A

1s 2s 2p 3s 3p 4s 3d 4p 5s 4d 5p …

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7
Q

how many orbitals in the s sub-level?
shape?

A

one orbital (two electrons)
spherical

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8
Q

how many orbitals in the p sub-level?
shape?

A

three orbitals (six electrons)
dumbbell shaped

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9
Q

how many orbitals in the d sub-level?
shape?

A

five orbitals (max ten electrons)
spherical

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10
Q

electron configuration exceptions?

A

chromium
- 1s² 2s² 2p⁶ 3s² 3p⁶ 4s¹ 3d⁵

copper
- 1s² 2s² 2p⁶ 3s² 3p⁶ 4s¹ 3d¹⁰

[one 4s electron goes to a new 3d orbital to minimise repulsion]

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11
Q

electron configuration of ions?

A

cations: e⁻ removed from highest energy orbital from the highest principal energy level
anions: e⁻ added to highest energy orbital from the highest principal energy level

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12
Q

which two subshells are closest in energy and what does this mean

A

3d and 4s
lead to anomalies: sometimes the lower energy (most stable) arrangement involves rearranging electrons within these levels
- one 4s electron goes to a new 3d orbital to minimise repulsion

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13
Q

how do electrons occupy orbitals

A

orbitals shown as boxes/lines and electrons as arrows

two electrons per orbital
electrons must have OPPOSITE SPINS

obey Hund’s Law

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14
Q

Hund’s Law

A

wherever possible, electrons occupy orbitals singly due to like charge repulsion
they only pair up when forced to (more e⁻ present than can be held individually)
SPIN PAIRING: electrons in the same orbital have opposite spins

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15
Q

maximum number of electrons in an energy level
why is this relevant

A

2n²
where n=principal energy level

it means some period three (/4/5/6) elements can ‘expand the octet’ to fit more electrons

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