Assignment Questions Flashcards
in the troposphere, the average temperature drop is __C per km
6.5
What is the pressure (kPa), temperature (0C) and density (kg/m3) of the “standard atmosphere” at sea level?
Pressure = 101.325 kPa
temperature = 15C
density = 1.2 kg/m3
how can liquid water exist above 100C deep in the ocean?
100C is the boiling point of water at sea level.
The boiling point temperature decreases as pressure decreases, and it increases as pressure increases.
So, under this high-pressure environment, the
boiling point of water is higher than what it is at sea level.
You climb into a hot-air balloon in Edmonton and before you get in you note that the
temperature on the ground is 24C. You ascended 2.5 kilometers.
You descend to the exact place where you launched. You notice no
precipitation/ clouds/ evaporation. What temperature do you measure?
The dry adiabatic process is reversible, so without precipitation, cloud formation or
evaporation, the temperature after you descend will be the same as the initial
temperature, i.e., 24C
describe the importance of droplet radius in terms of whether a
small liquid cloud droplet (a radius of ≈ 0.1 μm) grows or evaporates:
The smaller the droplet radius the greater the evaporation (the Curvature Effect) and so the higher the RH of the cloud would have to be in order for this drop to grow. So this droplet would likely evaporate if not for the solute effect.
describe the importance of solutes in the droplet in terms of whether a
small liquid cloud droplet (a radius of ≈ 0.1 μm) grows or evaporates:
Solutes reduce the evaporation from the droplet and allow it to grow by
condensation from water vapour in the cloud. The higher the solute content
the easier it is to grow the droplet (and hence the lower the RH needs to be
within the cloud).
describe the importance of relative humidity in the cloud in terms of whether a
small liquid cloud droplet (a radius of ≈ 0.1 μm) grows or evaporates:
The higher the RH the easier it is to grow a droplet, but it must make it to
the peak of its Kohler curve in order to reach activation. Beyond the peak
of the Kohler curve the necessary RH for growth is less than that at the
peak, so the droplet will grow rapidly without bounds.
which of the following are not important to the growth of ice particles
- solutes
- relative humidity in the cloud
- droplet radius
solutes
You measure the surface temperature to be T= 22°C and the surface dew point
temperature to be Td = 12°C.
What’s the height of the cloud base (in m)?
LCL= 125(T-Td)
LCL= 125(22-12)
LCL= 1250m
Describe how long wave radiation processes can lead to the eventual breakup
and demise of this cloud
The base of a cloud absorbs long wave radiation coming up from the
surface below (warming) whereas the cloud top radiates long wave up to space (cooling). So clouds cool on top and warm on the bottom, meaning
they become convectively unstable and overturn, which mixes them with
the drier environment, which means they will evaporate/dissipate.
You observed the surface winds have been blowing parallel to the coast of
Eastern Canada from south to north for days, but then they suddenly become
easterly.
Would you predict fog in your forecast? And if so, what type, why and in which direction
would predict it to travel?
Yes, you should predict an advection fog in your forecast. As the winds shift to
the Easterly, from ocean currents it flows over the relatively warm Gulf Stream
and then the cold Labrador Current. This change in temperature creates
advection fog, which blows towards the East Coast with the wind direction.
Wind speed in Edmonton is 22.5m/s.
If the same gradients existed over Calgary, would the winds be stronger or
weaker (and explain why)?
Calgary is further south than Edmonton, so the coriolis force would be smaller
there. From our equation, we can see that means our winds would be faster.
How would a higher tilt of earth (eccentricity) affect the strength of the westerly jet streams?
A higher tilt means greater seasonality. The strength of the jet stream is
dependent on the meridional temperature gradient: the greater the gradient is the
stronger the jet stream will be. With a higher tilt, the higher latitudes have the
greatest change, getting colder in the winter and warmer in the summer. So the
jets will be stronger.
How would a higher tilt of earth (eccentricity) affect the cyclones produced by the jet streams?
The stronger the jets, the more cyclones they produce. So there would be more
cyclones at midlatitudes.
It’s a nice sunny afternoon and you notice some fair-weather cumulus clouds moving toward the east. You also note some
alto-cumulus clouds traveling towards the northeast.
Should you bring a light or a heavy jacket if you go for a hike?
take a heavier jacket. The directional difference between the cloud levels (fair weather cumulus being low clouds and
alto-cumulus clouds being mid-level clouds), indicate that the winds are backing
with height, which is an indication of cold air advection, so you know the temperature is going to fall soon.