Aromaticity Flashcards

1
Q

What are the three key structural features of an aromatic compound?

A

Planar (flat) structure
Cyclic (ring) structure
Delocalized π-system (a conjugated system where electrons are shared across the ring)

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2
Q

What is an example of an aromatic compound, and what is its bonding structure?

A

Benzene (C₆H₆)

  • Benzene has alternating double and single bonds.
  • Each carbon atom forms:
  • Three sigma bonds (one with a hydrogen and two with adjacent carbons)
  • One pi bond (formed through overlapping p orbitals)
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3
Q

What are the key properties of aromatic compounds?

A

Must have a p orbital on every atom in the ring, perpendicular to the plane.
These orbitals overlap to form a delocalized π-system, providing stability.

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4
Q

Why are aromatic compounds important?

A
  • Stability – Highly stable due to delocalized electrons.
  • Role in fragrances and flavors – Found in essential oils and perfumes.
  • Applications in synthetic drugs, materials, and industrial production.
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5
Q

Who discovered benzene, and what structures were proposed?

A
  • Discovered by Faraday in 1825 during the study of gas combustion products.
  • Molecular formula: C₆H₆
  • Proposed structures:
    1. Ladenburg structure
    2. Dewar structure
    3. Kekulé structure (alternating double bond resonance model)
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6
Q

How did diffraction studies confirm the structure of benzene?

A

All C–C bonds in benzene are equivalent.
Bond lengths:
- Single bond: 150 pm
- Double bond: 134 pm

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7
Q

What is the hybridization of benzene’s carbon atoms?

A
  • Each carbon in benzene is sp² hybridized.
  • Each forms three sigma bonds and has one unhybridized p orbital.
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8
Q

What forms the π-system in benzene?

A
  • Overlapping 2p orbitals form a delocalized π-system.
  • This delocalization stabilizes the molecule.
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9
Q

What are the two molecular orbital energy levels in benzene?

A
  • Bonding orbitals (Lower energy, stabilize the molecule)
  • Antibonding orbitals (Higher energy)
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10
Q

What are the computational models that explain benzene’s stability?

A
  • Wavefunctions: Molecular orbitals formed from atomic/hybrid orbitals.
  • Delocalization: Electron bonding influence extends over the entire molecule.
  • Resonance: Electrons are not confined to specific bonds but are delocalized over the entire ring.
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11
Q

What is Hückel’s Rule, and how is it used to determine aromaticity?

A
  • Hückel’s Rule: A compound is aromatic if it has 4n + 2 π-electrons (where n is an integer).
  • Acceptable π-electron counts: 2, 6, 10, 14, etc.

Benzene: (4×1) + 2 = 6
Naphthalene: (4×2) + 2 = 10
Anthracene: (4×3) + 2 = 14

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12
Q

What is the difference between aromatic, anti-aromatic, and non-aromatic compounds?

A
  • Aromatic: 4n + 2 π-electrons, planar, cyclic, delocalized π-electrons, stable.
  • Anti-aromatic: 4n π-electrons, planar, cyclic, delocalized π-electrons, highly reactive.
  • Non-aromatic: Either non-cyclic or non-planar.
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13
Q

What criteria define an aromatic ion?

A
  • Cyclic structure
  • Planar geometry
  • 4n + 2 π-electrons
  • Delocalization of π-electrons

Examples:

  • Cyclopropene: Aromatic as a cation (n=0 in Hückel’s Rule).
  • Cyclopentadienyl anion: Aromatic (6 π-electrons).
  • Cycloheptatrienyl cation: Aromatic (6 π-electrons).
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14
Q

What are heterocyclic aromatic compounds?

A
  • Aromatic compounds with heteroatoms (N, O, S) in the ring.
  • Pyridine (6 π-electrons)
  • Pyrrole (6 π-electrons, lone pair contributes)
  • Furan (6 π-electrons)
  • Thiophene (6 π-electrons)
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15
Q

What are the three key experimental proofs of aromaticity?

A

No addition reactions – Benzene does not react like alkenes.
Resistance to hydrogenation & oxidation – Difficult to hydrogenate or oxidize.
Dominance of substitution reactions – Electrophilic substitution instead of addition.

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16
Q

What does the heat of hydrogenation reveal about benzene’s stability?

A
  • Expected value for a cyclic triene: -360 kJ/mol
  • Observed value for benzene: -208 kJ/mol
  • Resonance energy: 151 kJ/mol (extra stability due to delocalization)
17
Q

How does NMR spectroscopy confirm aromaticity?

A

Delocalized electrons create a magnetic field.
Ring current causes a unique chemical shift.
NMR Peaks:
- ¹H NMR: All protons equivalent, single peak at 7.26 ppm
- ¹³C NMR: All carbons equivalent, single peak at 128 ppm