Aromatic Chemistry Flashcards

1
Q

Describe the structure of benzene

A

Benzene is a cyclic, planar molecule with the formula C6H6;
Carbon has 4 valent electrons;
Each carbon is bonded to 2 other carbons and 1 hydrogen atom;
The final lone electron is in a p-orbital which sticks out above and below the planar ring

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
2
Q

What do the lone pair of electrons in benzene combine into to form?

A

A delocalised ring of electrons.

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
3
Q

Why do all the C-C bonds in benzene have the same bond length?

A

Due to the delocalised electron structure

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
4
Q

Describe Kekule’s benzene structure.

A

Alternating double and single bonds

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
5
Q

Why is Kekule’s structure not used?

A

Because we know electrons are delocalised;
There are no alternating double and single bonds

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
6
Q

How do we measure the stability of benzene?

A

By comparing the enthalpy change of hydrogenation in benzene and cyclohexane-1,3,5-triene

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
7
Q

Explain how benzene is more stable than cyclohexa-1,3,5-triene.

A

The hydrogenation of cyclohexene has an enthalpy chnage of -120kJmol-1;
Cyclohexene has 1 double bond;
If benzene has 3 double bonds, we would expect an enthalpy of hydrogenation 3*120=-360kJmol-1;
However, the actual enthalpy change of hydrogenation for benzene is -208kJmol-1;
This suggests more energy is required to break bonds in benzene than cyclohexane-1,3,5-triene, thus more stable.

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
8
Q

What is the stability of benzene due to?

A

The delocalised electron structure.

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
9
Q

Outline the mechanism that arenes undergo.

A

Electrophilic substitution

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
10
Q

Why does benzene not undergo electrophilic addition reactions?

A

As this would disrupt the stable ring of electrons.

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
11
Q

Why are aromatic compounds attacked by electrophiles?

A

Because the aromatic ring is very electron rich due to cloud of electrons above and below the ring.

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
12
Q

Name the two types of electrophilic substitutions arenes undergo.

A
  1. Friedel-Crafts Acylation
  2. Nitration Reaction
How well did you know this?
1
Not at all
2
3
4
5
Perfectly
13
Q

Give the equation for the generation of electrophile in a nitration substitution.

A

HNO3 + 2H2SO4 –>NO2+ + 2HSO4- + H3O+

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
14
Q

Outline and draw the mechanism when methyl benzene undergoes electrophilic substitution to make 2-nitromethylbenzene.
State the reagents and condition.

A

Mechanism: Nitration.
1. Generation of electrophile: HNO3 +2H2SO4 –>
NO2+ + 2HSO4- + H3O+
2. First curly arrow from benzene ring to NO2+
3. Second curly arrow from c-H bond to positively charged ring.
Reagents: concentrated HNO3 & concentrated H2SO4
Conditions: 50 C

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
15
Q

What are the three stages when drawing a Friedel-Crafts acylation mechanism?

A
  1. Generation of electrophile
  2. Reaction of electrophile with benzene
  3. Regeneration of catalyst
How well did you know this?
1
Not at all
2
3
4
5
Perfectly
16
Q

How is an electrophile formed in a Friedel-Crafts acylation substitution?

A

Acyl chloride or acid anhydride reacts with AlCl3 to form RCO+ (electrophile)

17
Q

How is the catalyst regenerated in a Friedel-Crafts acylation substitution? (acyl chloride)

A

AlCl4- + H+ –> AlCl3 + HCl

18
Q

How is the catalyst regenerated in a Friedel-Crafts acylation substitution? (acid anhydride)

A

[ Cl3Al-O-C(=O)-R]- + H+ –> AlCl3 +
HO-C(=O)-R

19
Q

Draw and outline the mechanism methylbenzene reacts with ethanoic anhydride and AlCl3 to make 2-methylphenylethanone.

A

Mechanism: Friedel-Crafts acylation
1. Generation of electrophile:
H3C - C(=O) - O - C(=O) - CH3 + AlCl3 –> H3C - C+ =O + [Cl3Al-O - C(=O) - CH3]-
2. Electrophilic substitution:
- First curly arrow from benzene ring to positive carbocation
- Second curly arrow from C-H bond to positively charged ring.
Regeneration of catalyst:
[Cl3Al - O - C(=O) - CH3 + H+ –> AlCL3 + HO - C(=O) - CH3

20
Q

State the reagents and conditions for Friedel-Crafts acylation.

A

Reagents: Acyl Chloride or acid anhydride & AlCl3
Conditions: Anhydrous - to prevent reaction of AlCl3

21
Q

State some of the uses of nitrobenzene compounds.

A

To make aromatic amines which can be used to make dyes.
To make explosives e.g. TNT.