Area and the Definite Integral Flashcards
definite integral
the integral used to find the area between the curve, the x-axis and the given boundaries
area of a trapezium
1/2 h(a+b)
a and b are two parallel lengths
how to use the trapezoidal rule
b-a/2 (f(a) + f(b))
start by constructing a table of values of the intervals (x) and these plugged into equation (f(x))
plug into formula and add together
fundamental theorem of calculus
integral from a to b:
F(b) - F(a): top minus bottom
If the numerator of a given quotient is the derivative of the denominator…
the primitive is ln(f(x))
regions of curve above x-axis
assigned a + to the area
regions of curve below the x-axis
assigned a - to the area
If a curve is even, the integral is
2 x the integral from 0 to a point
(find 0–>a area and double it
If a curve is odd, the integral is
integral from a–>-a = 0
reversing the integral
switch the bounds and put a negative in front
area between curves=
integral of top curve minus integral of bottom curve
TOP MINUS BOTTOM
sums of areas that intersect=
integral of f(x) from a to intersection + integral of g(x) from intersection to b
if you get a negative integral
the area below the x-axis is greater than the area above