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ABELE ABELE SEXY > AREA 2 > Flashcards

AREA 2 Flashcards

IDE, SWCE

1
Q

PAES: 615
In effective size, particle diameter corresponding to a ___ sieve passing
a. 5%
b. 10%
c. 15%
d.20%

A

b. 5%

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2
Q

PAES: 615
Another term for BORED WELL
a. Augered well
b. Vadous well
c. Macro well
d. Unconfined well

A

a. Augered well

  • used in formations with very shallow water
    depths
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3
Q

The hydraulic radius of a pipe with a diameter of 12mm is
a. 113 mm
b. 6 mm
c. 4 mm
d. 3 mm

A

d. 3 mm

Solution:
R = d/4 = 12mm/4 = 3mm

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4
Q

If the theoretical flow of velocity in an orifice is 4 m/s, what is the height of water flowing above the center of the orifice?
a. 0.61 m
b. 0.71 m
c. 0.81 m
d. 0.91 m

A

c. 0.81 m

h= v^2/2g=(4ms)2^/2(9.81ms)=0.81m

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5
Q

The net peak crop water requirement for a scheme is 6.0 mm/day. The available moisture for the clay loam is 130mm/m and depletion is allowed up to around 46%. The root zone depth is 0.70 m. After how many days should irrigation take place to replenish the soil moisture?
a. 5
b. 6
c. 7
d. 8

A

c. 7

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6
Q

At Nabusenga surface irrigation schemes, it is assumed that conveyance efficiency and field canal efficiency both are 90% for concrete-lined canals continuous flow and that application efficiency is 50%. What is the overall irrigation efficiency?
a. 45%
b. 40.5%
c. 81%
d. 50.5%

A

b. 40.5%

Et=(0.9)(0.9)(0.5)=40.5%

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7
Q

A 21.6mm/day water requirement is equivalent to ___lps/ha

A

2.5lps/ha

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8
Q

The recent monsoon rain have posted a nearly uniform rainfall intensity of 30mm/hr. over a 1500ha watershed area in central Luzon. If the runoff coefficient is 0.15, what is the runoff in m3/sec?
a. 40.3 m^3/s
b. 23.5 m^3/s
c. 18.8 m^3/s
d. 11. 6 m^3/s

A

c. 18.8 m^3/s

Q=CIA=(0.15)(0.030m/hr)(1500ha (10,000m/23,600s)
=18.75m^/s

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9
Q

Three tanks are installed side by side in a field to measure the evapotranspiration of rice. Tank A is bottomless and is cropped. Tank B is bottomless but is uncropped. Tank C has bottom and is uncropped. If the water losses after 2 rainless days are as follows
Tank A – 15mm
Tank B – 9mm
Tank C – 5mm
The actual evapotranspiration is
a. 9.7 mm/day
b. 7.3 mm/day
c. 6.1 mm/day
d. 5.5 mm/day

A

ETa=(A−B+C)/2
=(15−9+5)/2
=5.5mmday

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10
Q

The farm water requirement is 2lps/ha, application efficiency is 75% and the conveyance efficiency is 80%. If the dependable flow is 2.5m3/s, the irrigable area is
a. 100 ha
b. 80 ha
c. 70 ha
d. 60 ha

A

a. 100 ha

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11
Q

What is the bottom width for the best hydraulic cross-section (best proportion) of concrete open channel if design depth is 5 meters and side slope is 45º?
A3 m B. 4m C. 5 m D. 6 m

A

Solution:
b = 2 d tan (Ө/2)
= 2 (5) tan (45/2)
= 2 (5) tan (22.5)
= 2 (5) (0.41)
= 4.1 m

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12
Q

What is the bottom width for best hydraulic cross-section of unlined open channel for minimum seepage if design depth is 5 meters and side slope is 45º?
A3.15 m B. 4.15 m C. 8.15 m D. 6.15 m

A

Answer: C
Solution:

b = 4 d tan (Ө/2)
= 4 (5) tan (22.5)
= 8.2 m

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13
Q

What is the bottom width for best hydraulic cross-section of unlined open channel with minimum seepage if design depth is 5 meters and side slope is 2:1?

A. 4.72 m B. 7. 42 m C. 2.47 m D. 7.24 m

A

Answer: A
Solution:

Ө = arctan (rise /run)
= arctan (1/2)
= 26.6º

b = 4 d tan (Ө/2)
= 4 (5) tan (26.6/2)
= 4 (5) tan (13.3)
= 4 (5) (0.236)
= 4.72 m

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14
Q

A trapezoidal canal has a bottom width of 2.5 m and its sides are inclined 60o with horizontal. It can carry water up to a depth of 3 m. S = 0.0008 and n = 0.03. Find the discharge in m3/s when flowing full. Use the Manning’s equation.
Given:
Base = 2.5m
z = 1√3=0.577
y = 3m
S = 0.0008
n = 0.03

A

14.60 m^3/s

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15
Q

A concrete lined canal is to convey water over a distance of 250 m from the well to a tomato farm. Drop in elevation is 0.5 m over the 250 m canal length and roughness coefficient, n, is 0.018.

a. Estimate the bottom width of a rectangular canal with a depth of flowing water of 0.25 m if the hydraulic radius is equal to the area of flow.

b. The velocity of the canal

A

a. 0.5

b. 0.62 m/s

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16
Q

What is the depth of flowing water in a trapezoidal canal with a side slope of 1:1 and base of 1.0 m if the stream velocity is 1m/s and the average discharge is 6m3/s.
Solution:
Area of trapezoidal canal is:

A

2 m

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17
Q

What is the water depth for a trapezoidal canal with the following known parameters:
Q = 0.09m3/sec
S = 0.001
b = y
n = 55
Side slope (z) = 1
Allowable Velocity = <0.75m/sec

A

0.30 m

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18
Q

Given bed slope=0.0003; Manning’s coefficient, n=0.03; b/d ratio=3.5; wetted perimeter, p=14; z=0.5. The velocity of flow along a trapezoidal canal is:

A

0.82 m/s

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19
Q

A rectangular lined canal will be used to irrigate 60 has. If a Francis weir of 0.4m crest will be used to control the flow, what would be the depth of water over the crest in order to supply 2lps/ha?

A

0.3 m

20
Q

A farmer collected a soil sample 2 days after irrigation. The sample has a diameter of 5 in., height of 8 in. and the sample weighed 3000 g before drying and 2340 after drying. Bulk density is g/cc.

A

0.909 g/cm^3

21
Q

the ratio of the void volume to the total soil volume (unitless)

A

porosity

22
Q

the ratio of the dry weight of the soil to the total soil volume

A

bulk density

23
Q

the ratio of the dry weight of the soil to the volume of the
soil particles

A

particle density

24
Q

ratio of the bulk density of the soil with the
density of water; it is the ratio of the weight of soil to the weight of water with
volume equal to the total soil volume

A

Apparent Specific Gravity (As)

25
Q

ratio of the particle density of the soil with the
density of water; it is the ratio of the weight of soil to the weight of water with
volume equal to the volume of the soil particles alone

A

Real Specific Gravity (Rs)

26
Q

the rate of infiltration from a furrow into the soil.

A

intake rate

27
Q

the velocity of flow into the soil caused by a unit hydraulic gradient
in which the driving force is one kilogram per kilogram of water.

A

permeability

28
Q

the amount of water the soil profile will hold when all its pore
spaces are filled up with water

A

saturation point

29
Q

the amount of water a soil profile will hold against drainage by
gravity at a specified time (usually from 24 to 48 hours) after a thorough wetting.

the moisture content of the soil when gravitational water has been removed (after
irrigation by flooding). It is usually determined few days after irrigation. The soil
moisture tension at this point is normally between 1/10 to 1/3 atmosphere.

A

field capacity

30
Q

the soil moisture content
when plants permanently wilt. The soil moisture tension at this point is about 15
atmospheres. Permanent wilting percentage can be estimated by dividing the field
capacity by a factor ranging form 2.0 top 2.4, with the value higher for soils with
higher silt content.

A

Permanent Wilting Point (or wilting coefficient)

31
Q

the difference in moisture content of the soil between
field capacity and the permanent wilting point.

A

Available Moisture (AM)

32
Q

that portion of the available moisture that is
most easily extracted by plants; this is approximately 75% of the available moisture.

A

Readily Available Moisture (RAM)

33
Q

the ratio between the water delivered to the farm and
the water diverted from a river or reservoir expressed in percent.

A

Water Conveyance Efficiency

34
Q

the ratio between water stored in the soil root zone during irrigation and the water delivered to the farm expressed in percent.

A

Water Application Efficiency

35
Q

the ratio of water beneficially used on the project, farm or field to the amount of water delivered to the farm expressed in percent.

A

Water-use Efficiency

36
Q

the ratio of water stored in the root zone during the
irrigation to the water needed in the root zone prior to irrigation, expressed in percent.

A

Water Storage Efficiency

37
Q

the ratio of the normal consumptive use of water to the
net amount of water depleted from the root zone soil.

A

Consumptive Use Efficiency

38
Q

the power theoretically required to lift a given quantity of water
each second to specified height.

A

Water horsepower

39
Q

water horsepower divided by pump efficiency, in decimal.

A

Brake Horsepower

40
Q

the difference in elevation of the water surface in a pond, lake, or river
from which pumped water is taken, and the water surface of the discharge canal into
which the water flows from a submerged discharged pipe. In pumping from groundwater
source, static head is the difference in elevation between the water surface in the well
and the water surface of the discharged canal.

A

Static Head

41
Q

the sum of total static head, pressure head, velocity head and
friction head.

A

Total Dynamic Head

42
Q

(in a well) is the difference in elevation between the groundwater table
and the water surface at the well when pumping.

A

Drawdown

43
Q

graphs that show interrelations between speed, head discharge,
and horsepower of a pump.

A

Characteristic Curve

44
Q

expresses the relationship between speed in rpm, discharge in gpm,
and head in feet.

A

Specific Speed

45
Q

irrigation systems that have relatively large service
areas and are managed by government agencies

A

National Irrigation Systems (NIS)

46
Q

managed and operated by farmers’ or irrigators’
associations

A

Communal Irrigation Systems (CIS)

47
Q

pipes vertically set into the ground that
abstract groundwater to be used for irrigation, usually owned and operated by individual
farmers

A

Shallow Tubewell Irrigation Systems (STW)

ABELE ABELE SEXY (5 decks)

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