AQA-74011-JUN16 Flashcards

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1
Q

Which features are present in a bacterium compared to a HIV particle?

  • RNA
  • Cell Wall
  • Enzyme Molecules
  • Capsid = 2 marks
A

Bacterium:

  • RNA
  • Cell Wall
  • Enzyme molecules

HIV particle:

  • RNA
  • Enzyme molecules
  • Capsid
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2
Q

The complementary strand is made the same way as a new complementary strand is made during semi-conservative replication of human DNA

Describe how the complementary strand of HIV DNA is made. = 3 marks

A

1) Complementary nucleotides/bases pair: A to T and C to G
2) DNA Polymerase;
3) Nucleotides join together, forming a new strand between which phosphodiester bonds form.

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3
Q

Contrast the structures of DNA and mRNA molecules to give 3 differences. = 3 marks

A

1) DNA is double stranded/double helix and mRNA is single-stranded
2) DNA is very long and RNA is short
3) Thymine in DNA and Uracil in RNA
4) Deoxyribose in DNA and Ribose in RNA
5) DNA has base pairing and RNA doesn’t/ DNA has hydrogen bonds and RNA doesn’t
6) DNA has introns/non coding sequences and mRNA doesn’t

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4
Q

Describe the difference between the structure of a triglyceride molecule and the structure of a phospholipid molecule. = 1 mark

A

-In a Phospholipid, one fatty acid is replaced by a phosphate

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5
Q

Describe how you would test for the presence of a lipid in a food sample. = 1 mark

A

1) Add ethanol, than add water.

2) White emulsion shows positive for lipid

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6
Q

Describe how a saturated fatty acid is different from an unsaturated fatty acid. = 1 mark

A

-Saturated fatty acid has only single bonds/ no double bonds
OR
-Unsaturated fatty acids has (at least one) double carbon-carbon bond.

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7
Q

The structure of a fat substitute differs from that of a fat.
This fat substitute cannot be digested in the gut by lipase.

Suggest why. = 2 marks

A

1) The fat substitute is a different/wrong shape/not complementary
OR
Bond between glycerol/fatty acid and propylene glycol different (to that between glycerol and fatty acid)/ no ester bond

2) Unable to fit/bind to (active site of) lipase/ no stable ES complex formed.

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8
Q

A fat substitute is a lipid. Despite being a lipid, it cannot cross the cell-surface membranes of the cells lining the gut.

Suggest why it cannot cross cell-surface membranes = 1 mark

A
  • It is hydrophilic
  • It is polar
  • It is too large/big
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9
Q

Cells constantly hydrolyse ATP to provide energy.

Describe how ATP is resynthesized in cells. = 2 marks

A

1) From ADP and phosphate
2) By ATP synthase
3) During respiration/photosynthesis

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10
Q

Give 2 ways in which the hydrolysis if ATP is used in cells. = 2 marks

A

1) To provide energy for other reactions/named process

2) To add phosphate to other substances and make them more reactive/change their shape.

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11
Q

What evidence in a photo can suggest that a scanning electron microscope was used? = 1 mark

A

-Can see 3D image

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12
Q

The letters P,Q,R,S and T represent ways substances can move across membranes:
P - Diffusion through the phospholipid bilayer
Q - Facilitated diffusion
R - Active Transport
S - Co-Transport
T- Osmosis

Which letter represents the way these substances move across membranes?

1) Transport through a channel protein
2) Transport of small, non-polar molecules
3) Transport of glucose with sodium ions = 3 marks

A

1) Transport through a channel protein = Q
2) Transport of small, non-polar molecules = P
3) Transport of glucose with sodium ions = S

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13
Q

Y is a protein. One function of Y is to transport cellulose molecules across the phospholipid bilayer.
Substrate also enters at one end of the protein.
Using this information, describe the other function of Y.
= 2 marks

A

1) (Y is) and enzyme/has active site/forms stable ES complex
2) That makes cellulose/attaches substrate to cellulose/joins beta glucose
OR
3) Makes cellulose/forms glycosidic bonds
4) From beta glucose

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14
Q

In the cell wall, bonds hold the cellulose molecules together side by side.
Which bond describes the type of bond that holds the cellulose molecules together side by side?
- Ester
- Hydrogen
- Ionic
- Peptide = 1 mark

A

-Hydrogen

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15
Q

Name the products of the hydrolysis of sucrose. = 1 mark

A
  • glucose

- fructose

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16
Q

Describe the induced-fit model of enzyme action. = 2 marks.

A

1) (before reaction) active site NOT complementary to/does not fit substrate
2) Shape of active site changes as substrate binds/ as stable ES complex forms
3) Stressing/distorting/bending bonds (in substrate leading to reaction

17
Q

Human papilloma virus (HPV) is the main cause of cervical cancer. A vaccine had been developed to protect girls and women from HPV.

Describe how giving this vaccine leads to production of antibody against HPV. = 4 marks

A

1) Vaccine/it contains antigen (from HPV)
2) Displayed on antigen-presenting cells
3) Specific helper-T cell (detects antigen and) stimulates specific B cell
4) B cell divides/goes through mitosis/forms clone to give plasma cells
5) B cell/plasma cell produces antibody

18
Q

To determine antibody concentrations in the body in girls that had 2 doses of the vaccine compared to girls with 3 doses of the vaccine, what statistical test should the doctors have used? Give a reason for your choice. = 1 mark

A
  • T-test, because comparing two means
19
Q

There is genetic diversity within HPV.

Give two ways doctors could use base sequences to compare different types of HPV. = 2 marks

A

1) Compare (base sequences of) DNA
2) Look for mutations/names mutations (that change the base sequence)
3) Compare (base sequence of) (m)RNA

20
Q
In which stage of Mitosis do the chromosomes line up on the equator of the mitotic spindle?
A- anaphase
B- interphase
C- metaphase
D- prophases
E- telophase  = 1 mark
A
  • C
21
Q

A monopolar mitotic spindle has a singular pole.

Why would the development of a monopolar mitotic spindle prevent successful mitosis = 2 marks

A

1) No separation of chromatids/chromosomes/centromeres
2) Chromatids/chromosomes all go to one pole/end/side of cell/not pulled to opposite poles
3) Double chromosome number in cell/one daughter cell gets no chromosomes or chromatids

22
Q

At the start of an investigation, a scientist made a solution of kinesin inhibitor (KI) with a concentration of 10,000 nmol dm^-3. They used this to make the other concentrations by a series of dilutions with water

Describe how they made 100 cm^3 of 1000 nmol dm^-3 solution of kinesin inhibitor.

A

1) 10 cm^3 of 10,000 nmol dm^-3 /(original) solution

2) 90 cm^3 of water