AP Calculus Formulas Flashcards
VOLUME of a PYRAMID
V=1/3Bh
Area of a square
A=s²
Area of a parallelogram
A=lw
Area of an equilateral triangle
A=(s²√3)/4
Volume of a cone
V=1/3πr²h
Volume of a sphere
V=4/3πr³
Surface area of a cylinder
SA=2πr²+2πrh
Surface area of a sphere
SA=4πr²
Pythagorean Theorem
a²+b²=c²
Distance between two points
d = √(x2-x1)² + (y2-y1)²
Slope of a line
m=y2-y1/x2-x1
Point-slope form of a line
y-y1=m(x-x1)
Quadratic formula
x = -b ± √(b² - 4ac)/2a
Area of a rectangle
A=lw
Area of a triangle
A=1/2bh
Area of a trapezoid
A=1/2(b1+b2)h
Area of a circle
A=πr²
Circumference of a circle
C=2πr or C=πd
Volume of a cylinder
V=πr²h
Volume of a rectangular prism
V=lwh
x^m (x^n) = ?
x^m+n
x^m/x^n = ?
x^m-n
(x^m)^n = ?
x^mn
(xy)^m = ?
x^m(y^m)
(x/y)^m = ?
(x^m)/(y^m)
x^-m = ?
1/(x^m)
x^(1/m) = ?
m root x
Rewrite y = b^x into an equivalent logarithmic equation.
x = log_b(y)
Rewrite y = log_b(x) into an equivalent exponential equation
x = b^y
log_b(x) + log_b(y) = ?
log_b(xy)
log_b(x) - log_b(y) = ?
log_b(x/y)
log_b(x^y) = ?
ylog_b(x)
One degree equals
π/180 radians
One radian equals
80/π degrees
csc(theta) = ?
1/sin(theta)
When π/2 < theta < π
sin (theta) > 0, cos (theta) < 0, and tan (theta) < 0
When π < theta < (3π/2)
sin (theta) < 0, cos (theta) < 0, and tan (theta) > 0
When (3π/2) < theta < 2π
sin (theta) < 0, cos (theta) > 0, and tan (theta) < 0
tan (theta) = ?
sin (theta)/cos(theta)
cot(theta) = ?
cos (theta)/sin (theta)
sec (theta) = ?
1/cos(theta)
Name one Pythagorean identity
sin²(theta) + cos²(theta) = 1
Name another Pythagorean identity
1 + tan²(theta) = sec²(theta)
Name the last (of three) Pythagorean identities
1 + cot²(theta) = csc²(theta)
sin(a ± b) = ?
sin(a)cos(b) ± cos(a)sin(b)
cos(a ± b) = ?
cos(a)cos(b) ± sin(a)sin(b)
tan(a ± b) = ?
[tan(a) ± tan(b)] / [1 ± tan(a)tan(b)]
sin(2theta) = ?
2sin(theta)cos(theta)
cos(2theta) = ?
cos²(theta) - sin²(theta) OR 2cos²(theta) - 1 OR 1 - 2sin²(theta)
tan(2theta) = ?
[2tan(theta) ]/ [1 - tan²(theta)]
sin²(theta) = ?
[1 -cos(2theta)]/ 2
cos²(theta) = ?
[1 + cos(2theta)]/ 2
tan²(theta) = ?
[1 -cos (2theta)] / [1 + cos(2theta)]