AoS-01 Test Flashcards

1
Q

Calculate mass of 2 moles of Carbon Dioxide

Formula = CO₂

A

88.02 grams

Molecular mass = 12.0107+ 31.9988 = 44.0095 grams
Therefore 2 x 44.0095 = 88.019 grams

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2
Q

How many atoms of Carbon do you have in 12.0107 grams of the substance?

Formula = C

A

6.02 x 10²³ atoms of Carbon

Atomic mass = 12.0107 grams
Therefore (12.0107 ÷ 12.0107) x 6.02 x 10²³ = 6.02 x 10²³ atoms of Carbon

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3
Q

How many moles in 12.01 grams of Carbon

Formula = C

A

1.00 mol

Atomic mass = 12.0107 grams
Therefore 12.01 ÷ 12.0107 = 1.00 mol

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4
Q

Calculate mass of 1.5 moles of Carbon

Formula = C

A

18.02 grams

Atomic mass = 12.0107 grams
Therefore 1.5 x 12.0107 = 18.01605 grams

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5
Q

How many atoms of Iron do you have in 55.85 grams of the substance?

Formula = Fe

A

6.02 x 10²³ atoms of Iron

Atomic mass = 55.845 grams
Therefore (55.85 ÷ 55.845) x 6.02 x 10²³ = 6.02 x 10²³ atoms of Iron

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6
Q

How many atoms of Lime do you have in 1 grams of the substance?

Formula = CaO

A

1.07 x 10²² atoms of Lime

Molecular mass = 40.078+ 15.9994 = 56.0774 grams
Therefore (1 ÷ 56.0774) x 6.02 x 10²³ = 1.07 x 10²² atoms of Lime

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7
Q

Calculate mass of 2 moles of Silicon

Formula = S

A

64.13 grams

Atomic mass = 32.065 grams
Therefore 2 x 32.065 = 64.13 grams

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8
Q

How many atoms of Sulfuric acid do you have in 10 grams of the substance?

Formula = H₂SO₄

A

6.14 x 10²² atoms of Sulfuric acid

Molecular mass = 2.0158+ 32.065+ 63.9976 = 98.0784 grams
Therefore (10 ÷ 98.0784) x 6.02 x 10²³ = 6.14 x 10²² atoms of Sulfuric acid

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9
Q

How many moles in 27.9225 grams of Iron

Formula = Fe

A

0.50 mol

Atomic mass = 55.845 grams
Therefore 27.9225 ÷ 55.845 = 0.50 mol

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10
Q

Calculate mass of 1 mole of Iron

Formula = Fe

A

55.85 grams

Atomic mass = 55.845 grams

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11
Q

How many moles in 27 grams of Aluminium

Formula = Al

A

1.00 mol

Atomic mass = 26.9815 grams
Therefore 27 ÷ 26.9815 = 1.00 mol

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12
Q

How many moles in 74.44 grams of Sodium hypochlorite

Formula = NaClO

A

1.00 mol

Molecular mass = 22.9897+ 35.453 = 74.4421 grams
Therefore 74.44 ÷ 74.4421 = 1.00 mol

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13
Q

How many moles in 10.69 grams of Silicon

Formula = S

A

0.33 mol

Atomic mass = 32.065 grams
Therefore 10.69 ÷ 32.065 = 0.33 mol

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14
Q

Calculate mass of 1 mole of Carbon Monoxide

Formula = CO

A

28.01 grams

Molecular mass = 12.0107+ 15.9994 = 28.0101 grams

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15
Q

How many moles in 10 grams of Hydrogen peroxide

Formula = H₂O₂

A

0.29 mol

Molecular mass = 2.0158+ 31.9988 = 34.0146 grams
Therefore 10 ÷ 34.0146 = 0.29 mol

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