Anti-derivatives & Integration Formulas (initial version) Flashcards

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12
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How can we integrate this problem?

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By using the power rule. ln x + C only works when the power of x is equal to 1 (x1)

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15
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Write the general formula used in integration by parts

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  • Here, you want to find two things: u and dv
  • After identifying those two elements, you need to find du by differentiating u and you need to find v by integrating dv
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16
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Decode the acronym LIATE (for identifying the ‘u’ value)

A

Logs > Inverse trigs > Algebraic > Trigs > Exponential

  • Logs: things like “ln” and “log”
  • Inverse trigs: things like “cos-1” or “tan-1“…etc
  • Algebraic: things like “x” or “x2” or “x3” or polynomials
  • Trigs: things like “sin” or “tan” …etc
  • Exponential: things like “ex” and “ax
17
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What are the two main techniques used in solving integration by parts problems?

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1- The LIATE rule (helps with identifying the ‘u’ term, then you should proceed with the original by parts formula)

2- The tabular method

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19
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Can I use the tabular method for solving all integration by parts problems?

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Yes!

You can use it for all IBP problems

20
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How to know if I chose the correct u and dv terms?

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Choose your u and dv based on the LIATE rule (should work perfectly for most problems):

1- If your problem is getting simpler, then your choice was correct

2- If the problem is getting more complicated (especially at the ∫ v du part), then you probably have to go back and switch the values of those two (u and dv) and try again

21
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When to use the u-substitution technique?

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When the anti-derivative and the derivative of a given function are available in the same problem

22
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When to use the integration by parts technique?

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23
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How many possible scenarios we can expect while solving IBP problems with the tabular method?

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3 different cases:

  • case 1: when the nth derivative of u is equal to zero (after taking the derivative of u for an x number of times). Example: ∫ x2cosx dx
  • case 2: when the nth derivative of u will never be zero, but the function of the integral repeats itself in the table. We have to stop as soon as we see the first match (regardless of the sign and/or any multiplied constants). Example: ∫ ex sinx dx
  • case 3: when the nth derivative of u will never be zero, but the nth derivative of u keeps getting smaller and smaller. In this case, we have to stop right after finding the first derivative of 2 and consider the first two rows of the table in our final answer. Example: ∫ x3 lnx dx
24
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What is the purpose of using the u-substitution technique?

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The ultimate goal of using this technique is to cancel out all Xs in the problem and be left with Us only (hence the name)

25
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Trig integrals (section 8.3) depends on your knowledge in the following:

A

1- Knowing the required identities

2- Knowing the cases and what to do in each case (4 cases in total)

3- Applying u-substitution correctly right after using one of the Pythagorean identities (from #1)

4- Knowing the derivatives and anti-derivatives of all trigs

26
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How many different cases we have for trig integrals (section 8.3)?

A

Two different cases:

1- Integrals involving sin and cos

2- Integrals involving tan and sec

27
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What are the two cases or rules we have to know when we have sin and cos (section 8.3)?

A

CASE 1: When m (power of sin) AND/OR n (power of cos) is odd

  • If the power of sin is odd, keep one factor of sin factored out and use the Pythagorean identity to change sin2x = 1 - cos2x
  • We will do the same thing if the power of cos is odd, but we will be using cos2x = 1- sin2x instead
  • If both of m and n are odd, then pick the one with the smaller power and factor out one factor of it and use the corresponding Pythagorean identity

CASE 2: When m and n are both even

  • In this case, we have to use one of the half angle identites to solve the problem
28
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What are the two cases or rules we have to know when we have tan and sec (section 8.3)?

A

CASE 1: If the power of tan is odd

  • In this case, keep one factor of (sec x tan x) factored out and use the Pythagorean identity of tan2x = sec2x - 1

CASE 2: If the power of sec is even

  • In this case, keep one factor of sec2x factored out and use the Pythagorean identity of sec2x = tan2x + 1