Amplitude modulation Flashcards

1
Q

power content of the analog signal denoted by m(t) which is lowpass signal with bandwidth W -> M(f)=0 for |f| > W

A

Pm = lim (as T goes to inf) 1/T * ∫ from -T/2 to T/2 of |m(t)|^2 dt

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2
Q

how the message signal m(t) is transmitted through the channel

A

it is impressed on a carrier signal of the form c(t) = Accos(2pift + fi)

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3
Q

amplitude modulation

A

the message signal is impressed on the amplitude of the carrier signal - this results in a sinusoidal signal whose amplitude is a function of the message signal m(t)

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4
Q

double sideband surpassed carrier AM

A

DSB-SC AM is obtained by multiplying the message signal m(t) with the carrier signal -> u(t) = m(t)*u(t)

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5
Q

spectrum of DSB-SC AM

A

is obtained by taking Fourier transform of u(t) -> U(f) = Ac/2*[M(f - fc) + M(f + fc)]

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6
Q

upper and lower sideband of U(f)

A

upper sideband is in the f band |f| > fc and lower for |f| < fc

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7
Q

why it is called DSB-SC am

A

it is called double-sideband since it contains upper and lower sidebands, it also doesn’t contain a carrier component -> all transmitted power is in modulating signal that’s why is called suppressed carrier signal

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8
Q

power content of DSB-SC AM signal

A

Pu = lim T->INF ∫ u^2(t) dt = lim T -> inf ∫ Ac^2m^2(t)cos^2(2pifc*t)dt = Ac^2 / 2 * Pm

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9
Q

conventional amplitude modulation

A

it consists of a large carrier component in addition to the DSB am signal -> u(t) = Ac[1+m(t)]cos(2pifct)

sometimes m(t) is expressed as:
m(t) = a*mn(t) where
mn(t) = m(t)/max|m(t)|

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10
Q

spectrum of conventional am signal

A

U(f) = Ac*a/2 [Mn(f-fc) + Mn(f+fc)] + Ac/2[δ(f-fc) + δ(f+fc)]

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11
Q

power for the conventional am signal

A

power of message signal: Pm= lim integral [1+amn(t)]dt
Pm = 1 + a^2Pmn
Pu = Ac^2/2 + Ac^2/2
a^2*Pmn

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12
Q

envelope detector

A

the combination of rectifier and the lowpass filter

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