Amount of substance Flashcards
Relative atomic mass (Ar)
The weighed average mass of an atom, taking into account its naturally occurring isotopes, relative to 1/12 the RAM of carbon-12
Ar=(average mass of one atom of an element)/(1/12 mass of one atom of C-12)
Relative molecular mass (Mr)
(of a molecule) is the mass of that molecule compared to 1/12 the RAM of C-12
Mr=(average mass of one molecule)/(1/12 mass of one atom of C-12)
Also calculated by adding up the relative atomic masses of all atoms present in the molecule
Avogardo constant
Number of atoms in 12g of carbon-12 is 6.022*10^23
Mole
amount of substance that contains 6.022*10^23 particles (entities)
Mole equation
mass (g) = Mr * no. of moles
Limiting reactant
The reactant in a chemical reaction that determines the amount of product produced during the reaction. Not in excess
Ideal gas equation
pV=nRT p= pressure (Pa) V= volume (m^3) n= number of moles R= gas constant ( 8.31Jk^-1mol^-1) T= temperature (K)
Atom economy
measure of the amount of starting materials that end up as useful products. Important for sustainable development and for economic reasons reactions with higher AE are used
AE(%)=(total Mr of desired product)/(total Mr of reactants) *100
Mr= including multipliers
AE doesn’t change with mass
Percentage yodel
mass of product obtained compared to the theoretical maximum mass calculated from a balanced equation.
% yield= (mass of product actually made)/(maximum theoretical mass of product) *100
Empirical formula
simplest whole number ratio of atoms of each element in a compound. 1) Find masses of each of the elements in a compound (mass or %). 2) Calc. no. of moles by dividing mass or % by Ar of element 3) Find simplest whole number ratio by dividing by smallest no. then multiplying to get a whole number
Molecular formula
actual no. of atoms of each element in one molecule of a compound. 1) Calculate Mr of empirical formula 2) Divide given Mr by Mr of empirical formula 3) Use this number to multiply by EF to get MF