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CH203 > Alkene Reactions > Flashcards

Alkene Reactions Flashcards

1
Q
  • Anti-addition X/OR - Add X to more subs. side, OR to less subs. side (Markovnikov product) + enantiomer
A

Add X-OR across an alkene (X = I, Br and Cl) (R = Carbon Chain)

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2
Q
  • Anti-addition X/OH - Add X to more subs. side, OH to less subs. side (Markovnikov product) + enantiomer
A

Add X-OH across an alkene (X = I, Br and Cl)

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3
Q

Which alkene reactions are two step reactions?

A

Oxymercuration / Reduction

Hydroboration

Dihydroxylation

Ozonolysis

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4
Q

Add 1) O₃ across an alkene. Then add 2) H₂O₂ to product.

A
  • Break molecule apart at the alkene (produce two new molecules) - Add carbonyl (C=O) to both new molecules where the alkene was - Add OH next to carbonyl (C=O) - Results in carboxylic acid
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5
Q

///// Add 1) BH₃ across an alkene. Then add 2) H₂O₂ and NaOH to product.

A
  • Syn-addition of H/OH - Add OH to less subs. side, H to more subs. side + enantiomer
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6
Q

An Anti-addition is:

A

Groups are added with opposite stereochemistry (one on a wedge, one on a dash)

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7
Q

///// - Syn-addition of H/OH - Add OH to less subs. side, H to more subs. side + enantiomer

A

Add 1) BH₃ across an alkene. Then add 2) H₂O₂ and NaOH to product.

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8
Q

Hydroboration is a ___ step reaction.

A

2

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9
Q

///// Add 1) OsO₄ across an alkene. Then add 2) NaHSO₃ and H2O to product.

A
  • Syn-addition of OH/OH
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10
Q

Add 1) O₃ across an alkene. Then add 2) Zn or PPh₃ to product.

A
  • Break molecule apart at the alkene (produce two new molecules) - Add carbonyl (C=O) to both new molecules where the alkene was - Add H next to carbonyl (C=O) - Results in aldehyde
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11
Q

///// - Syn-addition of OH/OH

A

Add 1) OsO₄ across an alkene. Then add 2) NaHSO₃ and H2O to product.

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12
Q

A Markovnikov product is:

A

A product where X (X = I, Br and Cl) is added to the more substituted side.

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13
Q

DO NOT

A

Benzene and other aromatic compounds ___ ___ react in any of the alkene reactions.

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14
Q

2

A

Hydroboration is a ___ step reaction.

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15
Q

2

A

Ozonolysis is a ___ step reaction.

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16
Q

Add H₂ with Pd/Pt across an alkene.

A
  • Syn-addition of H/H
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17
Q

Add X-OH across an alkene (X = I, Br and Cl)

A
  • Anti-addition X/OH - Add X to more subs. side, OH to less subs. side (Markovnikov product) + enantiomer
18
Q

///// - Anti-addition of H/OH - Add OH to more subs. side, H to less subs. side + enantiomer

A

Add 1) Hg(OAC)₂ and H₂O across an alkene. Then add 2) NaBH₄ to product.

19
Q

Groups are added with opposite stereochemistry (one on a wedge, one on a dash)

A

An Anti-addition is:

20
Q

Ozonolysis is a ___ step reaction.

A

2

21
Q
  • Syn-addition of H/H
A

Add H₂ with Pd/Pt across an alkene.

22
Q

A Syn-addition is:

A

Groups are added with same stereochemistry (both on wedge, or both on dash)

23
Q

Add X₂ across an alkene (X = I, Br and Cl)

A
  • Anti-addition of X/X + enantiomer
24
Q

Benzene and other aromatic compounds ___ ___ react in any of the alkene reactions.

A

DO NOT

25
Q
  • Break molecule apart at the alkene (produce two new molecules) - Add carbonyl (C=O) to both new molecules where the alkene was - Add H next to carbonyl (C=O) - Results in aldehyde
A

Add 1) O₃ across an alkene. Then add 2) Zn or PPh₃ to product.

26
Q
  • Anti-addition X/OH - Add X to more subs. side, OH to less subs. side (Markovnikov product) + enantiomer
A

Add X₂ and H₂O across an alkene (X = I, Br and Cl)

27
Q

Oxymercuration / Reduction is a ___ step reaction.

A

2

28
Q

2

A

Oxymercuration / Reduction is a ___ step reaction.

29
Q

breaks

A

Ozonolysis ___ apart the molecule.

30
Q

///// Add 1) Hg(OAC)₂ and H₂O across an alkene. Then add 2) NaBH₄ to product.

A
  • Anti-addition of H/OH - Add OH to more subs. side, H to less subs. side + enantiomer
31
Q

Add X₂ and ROH across an alkene (X = I, Br and Cl) (R = Carbon Chain)

A
  • Anti-addition X/OR - Add X to more subs. side, OR to less subs. side (Markovnikov product) + enantiomer
32
Q
  • Anti-addition X/OR - Add X to more subs. side, OR to less subs. side (Markovnikov product) + enantiomer
A

Add X₂ and ROH across an alkene (X = I, Br and Cl) (R = Carbon Chain)

33
Q
  • Anti-addition of X/X + enantiomer
A

Add X₂ across an alkene (X = I, Br and Cl)

34
Q

A product where X (X = I, Br and Cl) is added to the more substituted side.

A

A Markovnikov product is:

35
Q

Groups are added with same stereochemistry (both on wedge, or both on dash)

A

A Syn-addition is:

36
Q

Add X₂ and H₂O across an alkene (X = I, Br and Cl)

A
  • Anti-addition X/OH - Add X to more subs. side, OH to less subs. side (Markovnikov product) + enantiomer
37
Q

2

A

Dihydroxylation is a ___ step reaction.

38
Q

Add H/OH (water) across an alkene

A
39
Q

Add X-OR across an alkene (X = I, Br and Cl) (R = Carbon Chain)

A
  • Anti-addition X/OR - Add X to more subs. side, OR to less subs. side (Markovnikov product) + enantiomer
40
Q
  • Break molecule apart at the alkene (produce two new molecules) - Add carbonyl (C=O) to both new molecules where the alkene was - Add OH next to carbonyl (C=O) - Results in carboxylic acid
A

Add 1) O₃ across an alkene. Then add 2) H₂O₂ to product.

41
Q

Ozonolysis ___ apart the molecule.

A

breaks

42
Q

Dihydroxylation is a ___ step reaction.

A

2

CH203 (4 decks)

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