Algebra 2C Flashcards

1
Q

What does the spectral theorem state

A

Spectral theorem states that :

Linear operator phi is orthogonally diag iff phi is normal (field =C)

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2
Q

If V is an I.P space and linear operator phi is self-adjoint, then what are properties of phi

A

If V is an I.P space and linear operator phi is self-adjoint, then what are properties of phi are:
Any eigenvalue of phi is real
If v,w in V are eigenvalues then v is perp to w I.e inner(v,w) = 0

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3
Q

If V is a real I.P and phi is self adjoint, what does phi have

A

If V is a real I.P and phi is self adjoint then phi has a real eigenvalue

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4
Q

What is spectral thm for symmetric and hermitan matrices

A

Spectral thm for symmetric matrices is:
If matrix A is symmetric, then E orthogonal matrix P s.t P^-1AP is diagonal
If A is a hermitian, then E unitary matrix P s.t P^-1AP is diag

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5
Q

What is the singular value decomposition

A

Singular value decomposition is:
If phi is self adjoint this implies E an orthonormal eigenbasis implying that for all v in V can be written as a linear combination.

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6
Q

What is singular value decomposition for matrices

A

Singular value decomposition for matrices is:

E unitary matrix P s.t P^-1AP= diagonal matrix

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7
Q

What are singular values of phi

A

Singular values of phi are sigma1 … sigma n where sigma i = root(mu i) and mu i are eigenvalues of phi* o phi

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8
Q

What is singular value decomposition thm

A

Singular value decomposition thm is:
If phi has singular values sigma1 … sigma n. Then E orth.normal bases u1,…un and w1,…,wn of C such that phi(v) = sum 1 to n sigma i (inner product of ui,v) wi

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9
Q

How can any n x n matrix be written

A

Any matrix can be written by a 1 x n matrix multiplied by an n x 1 matrix

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10
Q

What does spectral thm state for real self-adjoint operators in V real I.P space

A

For real self-adjoint operators, spectral thm states :

Phi is orthogonally diagonalisable iff phi is self-adjoint

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