Aggregate XS Loss Cost Estimation (Fisher) Flashcards
Contrast vertical and horizontal slices approaches
Vertical approach is:
+ more intuitive
+ quicker if just 1 entry ratio
- deals with each risk individually
But horizontal approach is:
+ faster if we need to calculate for multiple limits.
Define entry ratios
If risks we are pricing are not exactly the same as underlying distribution, we need to make an adjustment otherwise dollars of expected losses will be off.
To deal with this, we simply rescale vertical axis by dividing actual losses by expected losses.
r = A/E
Without rescaling, tot area under curve = ?
E(Loss)
Once we use r instead, tot area under curve = ?
1
Explain insurance charge
E(XS)/E = E(Losses above LG)/E
Area between curve and rG
Explain insurance savings
E(shortfall)/E = E(shortfall below LH)/E
Area between rH and curve
Calculate Net Insurance Charge
Insurance charge - Insurance savings = phi(rG) - psi(rH)
Define Table M
Collection of related aggregate XS loss factors and related savings.
It ignores the impact of per-occurrence limit.
Explain how to create a Table M
- Calculate r for each claim
- Create one row for each ri and one for r=0
- Add a column for # risks at each ri
- Add a column for # risks above ri
- Add a column for % risks above ri
- Add a column for Charge(ri)
Charge(rmax) = 0
Charge(ri) = Charge(ri+1)+(ri+1 - ri)*(% risks above ri) - Make sure Charge(r0) = 1, o/w rescale
How to get savings from charge
Savings = Charge + r - 1
Why tables defined in terms of r and phi are more desirable
Tables are less vulnerable to inflation since as risk increases due to inflation, you can simply map to different existing Table M charge column instead of recalculating.
What are the 4 properties of insurance charge
- charge(0) = 1
- charge(inf) = 0
- First derivative is negative (charge decreases as r increases)
- Second derivative is positive (charge decreases at an increasing rate)
What are the 4 properties of insurance savings
- savings(0) = 0
- savings(inf) = inf
- First derivative is positive (savings increase as r increases)
- Second derivative is positive (savings increase at an increasing rate)
Discuss what happens to insurance charge when changing r and risk size
As risk size increases, var(r) decreases so charge curve flatten
As risk size decreases, charge goes to 1
As r increases, charge decreases
Discuss what happens to insurance savings when changing r and risk size
As risk size decreases, savings go to r (since savings = charge + r - 1 = 1 + r - 1 = r)
As r increases, savings increase