Acids And Bases Flashcards

1
Q

What is a Bronsted-Lowry acid

A

A proton donor

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2
Q

What is a bronsted-lowery base

A

A proton acceptor

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3
Q

What does bronsted Lowry refer to

A

Exchange of protons

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4
Q

What is pH

A

-log10 /H+/

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5
Q

What is a strong acid

A

Strong acids fully dissociate in water

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6
Q

What assumption can be made when calculating pH of a strong acid

A

The concentration of hydrogen ions in a MONOPROTIC acid is the SAME as the concentration of the acid

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7
Q

How many decimal places is pH measured to

A

2 d.p.

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8
Q

How do you find /H+/ from pH

A

/H+/ = 1 x 10^-pH

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9
Q

What is equilibrium for water

A

H2O <=> H+ (aq) + OH- (aq)

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10
Q

What is the equilibrium expression for water

A

Kc = /H+/ /OH-/
/H2O/

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11
Q

What can the equilibrium expressions for water be simplified to

A

Kw = /H+/ /OH-/

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12
Q

Why can the equilibrium expression for water be simplied

A

Pure water doesn’t dissociate much so we assume the concentrations stays constant, so isn’t included in Kw expression

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13
Q

What is the kw for water

A

At 25 degrees c, Kw = 1 x 10^-14 mol2dm-6

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14
Q

What can we assume for pure water or neutral solutions

A

/H+/ = /OH-/

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15
Q

What can the equilibrium expression be simplified to when solution is neutral

A

Kw = /H+/^2

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16
Q

When does Kw change

A

At different temperatures

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17
Q

Why does Kw change with temperature

A

Position of equilibrium changes, so /H+/ changes, so pH changes

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18
Q

What is the concentration of a strong base equal to

A

/OH-/

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19
Q

What are the steps to calculating the pH of a strong base

A

1) Find /H+/ using the Kw expression
2) pH = -log10 /H+/

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20
Q

Describe a weak acid

A

An acid that doesn’t fully dissociate

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21
Q

What is the equilibrium equation for weak acids

A

HA + H2O <=> H3O + A-

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22
Q

What does the equilibrium equation for weak acids simplify to

A

HA <=> H+ + A-

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23
Q

What is the weak acids dissociation expression

A

Ka = /H+/ /A- /
/HA/

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24
Q

What does a larger Ka value mean

A

Stronger acid

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25
Q

What can the weak acid equilibrium expression be simplified to

A

Ka = /H+/^2
/HA/inital

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26
Q

What are the assumptions made to simplify the weak acids equilibrium expression

A

1) /H+/ = /A-/ as they dissociate in a 1:1 ration

2) amount of dissociation is small, so assume that initial concentration of undissociated acid remains constant

27
Q

How do you work out pH of a weak acid

A

PKa = -log10 (Ka)

28
Q

How do you work out Ka from pKa

A

Ka = 1 x10^ -pKa

29
Q

What are the steps to work out a strong acid + strong base neutralisation

A

1) work out the moles of acid and base

2) work out which (acid or base) is in excess

30
Q

What is the next step of strong acid + strong base neutralisation if ACID IS IN EXCESS

A

3) /H+/ = moles excess H+ / total volume

4) pH = -log10 /H+/

31
Q

What is the next step of strong acid + strong base neutralisation IF BASE IS IN EXCESS

A

3) /OH-/ = moles excess OH- / total volume

4) /H+/ = Kw / /OH-/

5) pH = -log10 /H+/

32
Q

What do you do in a neutralisation calculation if a diprotic acid is used

A

Multiply moles x 2

33
Q

What are the steps for a weak acid, strong base neutralisation calculation

A

1) work out moles of acid and base

2) If excess acid, work out new concentration of HA

3) work out concentration of salt /A-/ formed

4) rearrange Ka expression for /H+/

5) pH = -log10 /H+/

34
Q

How to work out new concentration of HA if excess acid
(Weak acid, strong base neutralisation)

A

/HA/ = inital moles HA - moles OH- / total volume

35
Q

How to work out concentration of salt /A-/ formed
(Weak acid, strong base neutralisation)

A

/A-/ = moles OH- added / total volume

36
Q

When can Ka expression simplify further

A

Weak acid reacts with exactly half the neutralisation volume of alkali

37
Q

What is assumed when Ka is simplified at half neutralisation

A

/HA/ = /A-/

38
Q

What does the Ka expression simplify to at half neutralisation

39
Q

What does pH equal at half neutralisation

40
Q

In questions, what is the volume of alkali equal to

A

Half acid volume

41
Q

How to calculate pH of a diluted strong acid

A

/H+/ = /H+/old x old volume
New volume

42
Q

How to calculate pH of a diluted base

A

/OH-/ = /OH-/old x Old volume
New volume

/H+/ = Kw
/OH-/

43
Q

On a titration curve, where is the buffer region

A

When the graph horizontally plateaus

44
Q

Define a buffer solution

A

One where the pH does not change significantly when small amounts of acid o alkali are added to it

45
Q

How to make a basic buffer

A

Weak base and a salt of that weak base

46
Q

How do you make the salt of a weak base

A

React weak base with strong acid

47
Q

How do you make an acidic buffer

A

Weak acid and a salt of that weak acid

48
Q

How do you make the salt of a weak acid

A

React weak acid with strong base

49
Q

Give an example of components of an acidic buffer

A

Ethanoic acid and sodium ethanoate

50
Q

Give an example of components of a basic buffer

A

Ammonia and ammonium chloride

51
Q

What does a buffer contain a reservoir of

A

Reservoir of HA and A- ions

52
Q

What is the equilibrium equation for an acidic buffer

A

Acid <=> conjugate base + /H+/

53
Q

What happens to equilibrium if small amounts of acid are added to an acidic buffer

A

Equilibrium shifts to the left, removing nearly all H+ ions added

54
Q

Why does pH stay constant when acid is added to acidic buffer

A

There’s a large concentration of the salt ion in the buffer, so ratio of acid to conjugate base remain constant

55
Q

What forms when small amounts of alkali are added to an acidic buffer

A

The OH- ions react with H+ ions to form water

56
Q

What happens to the position of equilibrium when alkali is added to acidic buffer

A

Equilibrium shifts right to produce more H+ ions

57
Q

Suggest a way salt content can be added to a buffer

A

Solid salt or salt solution could be added

58
Q

What values can you use instead of concentration when making a buffer by adding solid salt

A

The mole values of HA and A- as they have the same new final volume

59
Q

How does adding a small amount of alkali to buffer affect moles

A

Increase moles of alkali by number added
Decrease moles of acid by number added
Find new concentrations using these new values for moles

60
Q

What happens to moles when small amount of acid is added to buffer

A

Increase moles of acid by number added
Decrease moles of alkali by number added
Find new concentrations using these new values for moles

61
Q

How will diluting a buffer solution affect pH

A

Diluting with water wont change the ph

62
Q

Why does diluting buffer with water not change its pH

A

The ratio of HA to A- stays constant as both diluted by same proportion