AAMC Test 5 Corrections Flashcards
Equation: Free energy change in a reaction
∆G(rxn) = ∆Gf(products) - ∆Gf(reactants)
∆Gf
free energy of formation
multiply ∆Gf for each species by the number of moles of that species in the net reaction
a rxn diagram will always show an initial ______ in energy as the activation energy is reached; E decreases as stable products are formed
increase
Equation: Hess’s Law (∆S)
S(rxn) = S(products) - S(reactants)
Absolute entropy values (S)
specific entropy value for a species
multiply by number of moles of that species present in net reaction to use in Hess’s law
Extensive quantity: depends on the amount of material (i.e. number of moles)
Formation of 3 moles of a simple gas from 2 moles of a complex gas causes S (entropy) to ______
Increase; 2 moles reacted to form 3 moles–increases randomness / disorder
Radicals are recycled, so they act as _______ and can be used in the next rxn to produce much product.
catalysts
One mole of Ideal Gas at STP will occupy _______ L.
22.4 Liters
Equation: Speed of a wave
v = frequency * wavelength
Equation: frequency (wave)
f = 1 / sec (1 / x seconds) (cycles / second)
wavelength is measured between adjacent
peak to peak or trough to trough; if measured peak-trough = 1/2 * wavelength
Equation: Circumference of a circle
C = 2 * pi * r
Equation: Equilibrium constant / Acid Dissociation constant (Ka)
Ka = [A-][H+] / [HA]
Note: Constant value, so ratio of conjugate base/ weak acid is FIXED
Equation: Acid dissociation constant (pKa)
pKa = -log10 * Ka
Equation: Henderson-Hasselback Equation to find pH
pH = pKa + log ([conjugate base] / [weak acid])
Find the number of atoms after (n) half lives
2^n (n = number of half lives) * current number of atoms in sample
Equation: Average Kinetic Energy
K.E.(avg) = m * v^2 / 2
Equation: Energy of a photon
E(photon) = h * c / wavelength
Do not expect a _______ rxn w/ neutral NaCl. Will likely be displacement rxn instead.
Redox
Oxidation state of Cd if it is reacted w/ S?
S is in the same column in the periodic table as Oxygen, so expect it to have oxidation state of -2. For CdS to be neutral, Cd must have 2+ oxidation state to balance out Sulfur.
Most likely gas to be let off when Cu placed in HNO3?
NO(g); Redox rxn where Cu is oxidized (loses electrons) and N is reduced (gains electrons).
In the reaction b/w HNO3 and Cu, nitric acid is the _____
oxidizing agent (and is reduced)
In the reaction b/w HNO3 and Cu, Cu is _______
reducing agent (and is oxidized)
A more electronegative atom will undergo ________ more readily.
Reduction (gain of electrons)
Boiling point is a _______, meaning it depends only on the number of solute particles, NOT the type of particles in the solute.
Colligative
When Cu is placed in AgNO3, a metal is formed on the copper b/c it is….
Oxidized and Ag+ is reduced. Cu is oxidized (loses electrons) to form Cu+2. Neutral Cu (a metal) won’t gain electrons (be reduced) bc it is more prone to lose electrons to form + cations
∆S for the sublimation of iodine: I2(s) —-> I2(g)
∆S > 0 (increase in entropy); gas is less ordered (more random) than a solid
phase change from solid to gas
Sublimation
measure of disorder
increases w/ value of S
entropy; ∆S
+∆S
increase in entropy / randomness
-∆S
decrease in entropy / randomness
map of pressure and temperature conditions under which individual phases are stable / where phase changes will occur
phase diagram