8P- Thermodynamics Flashcards

1
Q

What are the two types of lattice enthalpy

A

Enthalpy of lattice dissociation
Enthalpy of lattice formation

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2
Q

Define enthalpy of lattice formation

A

Enthalpy change when 1 mol of a solid ionic compound is formed its constituent ions in the gas phase

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3
Q

Define enthalpy of lattice dissociation

A

Enthalpy change when 1mol of solid ionic compound is broken up into its constituent ions in the gas phase

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4
Q

Define enthalpy of formation

A

Enthalpy change when 1 mol of substance is formed from its constituent elements with all substances in their standard states

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5
Q

Define 1st ionisation energy/enthalpy

A

Enthalpy change when 1mol of electrons is removed from 1mol of gaseous atoms to form 1mol of gaseous ions

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6
Q

Define 2nd ionisation energy/enthalpy

A

Enthalpy change when 1mol of electrons is removed from 1mol of gaseous 1+ ions to form 1 mol of gaseous 2+ ions

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7
Q

Define enthalpy of atomisation

A

Enthalpy change when 1mol of gaseous atoms is produced from an element in its standard state

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8
Q

What’s mean bond enthalpy

A

Enthalpy change when 1mol of gaseous molecules each breaks a covalent bond forming 2 free radicals, averaged over a range of compounds

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9
Q

What’s first electron affinity

A

Enthalpy change when 1mol of gaseous atoms is converted to 1mol of gaseous ions with a -ve charge
Eg O + e- —> O-

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10
Q

Define second electron affinity

A

Enthalpy change when 1mol of electrons is added to 1mol of gaseous ions with a -ve charge to form ions with a 2- charge
Eg O- + e- —> O 2-

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11
Q

Define enthalpy of solution

A

Enthalpy change when 1mol of solute dissolves completely in sufficient solvent to form a solution where ions are separated and thus do not interact with each other

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12
Q

Define enthalpy of hydration

A

Enthalpy change when 1 mol of gaseous ions are converted into aqueous ions

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13
Q

What’s a theoretical lattice enthalpy

A

An enthalpy calculated from the charge in an ion and their distance apart

(Fake value)

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14
Q

What’s a born haber lattice enthalpy
(Real/experimental value)

A

Experimental value calculated from a born haber cycle

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15
Q

What’s a perfect ionic model

A

Ions are 100% ionic and spherical, the interaction is purely electrostatic

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16
Q

What’s covalent character

A

A compound tends towards a giant covalent structure, the electron cloud is distorted (becomes polarised), the lattice is therefore stronger than a 100% ionic structure
Born haber value is larger than the theoretical (fake) value
The more covalent character a structure shows the larger the difference in the two enthalpy values

17
Q

What’s a feasible/spontaneous process

A

A reaction which will occur on its own without any external influence (eg diffusion)

18
Q

Why is enthalpy change ^H not sufficient to explain feasible change

A

Exothermic reactions (-ve ^H) result in products which are more thermodynamically stable than reactants
This is a factor as to why reactions can be spontaneous
Endothermic (+ve ^H) reactions can also be spontaneous but there is no explanation for this (in terms of ^H)

19
Q

What’s entropy change

A

The randomness of a system

Products more disordered than reactants, +ve entropy

^S

20
Q

Why is ^S better to explain feasible change than ^H

A

^S takes into account physical and chemical changes

21
Q

What has 0 entropy

A

Perfect crystals at absolute zero (0K)

22
Q

How to find entropy qualitatively

A

Use balanced chemical equations
Entropy will increase (+ve ^S) if
Solid reactant turn to liquid/gaseous products
There are more mol of products than mol of reactants

The opposite occurs for entropy (-ve^S) to decrease

23
Q

How to calculate entropy change from absolute entropy values (quantitatively)

A

^S = sum of ^S products - sum of ^S reactants

Use values given
Units J/K/mol

24
Q

What’s gibbs free energy change
Give the equation

A

Combines enthalpy and entropy to determine the feasibility of a reaction

^G (gibbs free energy) = ^H (enthalpy) - T(temp)x^S(entropy)

Reactions with +ve entropy and -ve enthalpy make ^G -ve or 0 making the reaction feasible
But reactions with -ve ^G and a high activation energy may not occur

25
Q

How to calculate ^S and ^H for use in the gibbs eq

Check if enthalpy is always formation

A

^S
^S of products - ^S of reactants
Measured in J/K
Convert to Kj by dividing by 1000

^H formation
^H products - ^H reactants

26
Q

What’s ^G for changes of state

A

0
At melting point equal existence of solid and liquid, there is equilibrium
^H= T^S

27
Q

Effects of T on ^G

A

If ^S is +ve increasing temp makes ^G more -ve, more feasible reaction

If ^S if -ve increasing temp makes ^G more +ve, less feasible reaction

If ^S is close to 0, -T^S will be the same, no change to ^G

28
Q

How to calculate ^S and ^H from a graph of ^G and T

A

^G = ^H -T^S
Y= mx + c

Gradient = -^S (-ve entropy don’t forget)
Y intercept = ^H