8 Acids & Bases Flashcards

1
Q

different types of acid-bases [2]

A

bronsted-lowry
lewis

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2
Q

what defines a bronsted-lowry (B-L) acid-base

A

b-l acid donates proton, b-l base accepts protons

HCl (g) + H₂O (l) ⇌ H₃O⁺ (aq) + Cl⁻ (aq)
-> from the eqn above:
- HCl (g) and H₃O⁺ (aq) are b-l acids as both can donate protons
- H₂O (l) and Cl⁻ (aq) are b-l bases as they can accept protons
- Cl⁻ is said to be the conjugate base of HCl,, H₂O is said is the conjugate base of H₃O⁺
- conjugate base/acid are the species formed from an acid/base losing/gaining a proton

certain substances can act both as a b-l acid and base – described as amphiprotic

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3
Q

what is pH, Kw and how to calculate it

A

power of hydrogen (pH) = -log₁₀ [H⁺]

dissociation constant of water / equilibrium constant (Kw) = [H⁺][OH⁻] = 1.0 x 10⁻¹⁴

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4
Q

define the following:
strong
weak
concentrated
corrosive
dilute

A

strong: completely disassociated into ions

weak: slightly disassociated into ions

concentrated: high number of mols of solute per dm³ of solution

dilute: low number of mols of solute per dm³ of solution

corrosive: chemically reactive

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5
Q

what defines a lewis acid-base

A

lewis acid accepts electrons, lewis bases donates electrons

in this process, a coordinate covalent bond is formed between lewis acid and base, reacting to form product of acid-base reactions

lewis acid is essentially a normal acid or base, and is only identified openly for substances which are not also b-l

  • for organic chem
  • used to identify reacting species through the use of curly arrows to explain electron movement in mechanisms
  • base of arrow always begins from lewis base and points towards lewis acid
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6
Q

pH v pOH v pKw for strong acid/bases

how to use the following variables and their respective eqns to solve determine neutrality of substance

A

pH = -log₁₀ [H⁺]
pOH = -log₁₀ [OH⁻]
pKw = -log₁₀ [Kw]
Kw = [H⁺] [OH⁻]

pKw = pH + pOH = 14

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7
Q

for weak acid/bases
Ka v Kb v Kw

A

let weak acid be HA:
dissociation of HA in water:
- HA (aq) ⇌ H⁺ (aq) + A⁻ (aq)
equilibrium expression for above is Ka = [H⁺] [A⁻] / [HA]
- where Ka is acid dissociation constant

if acids are quite weak, equilibrium concentration is assumed to equal initial concentration

dissociation of weak base:
- B (aq) + H₂O (l) ⇌ BH⁺ (aq) + OH⁻ (aq)
equilibrium expression above is Kb = [BH⁺] [OH⁻] / [B]
- where Kb is base dissociation constant
if reverse reaction where BH⁺ acts as acid, then:
Ka = [B] [H⁺] / [BH⁺]

Ka x Kb = Kw = [H⁺] [OH⁻]

pKa = pKb = 14

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8
Q

what are buffer solutions
what it does, how its created,

A

buffer solutions resists changes in pH when small amounts of acid or alkali are added to it
- i.e. to keep the pH unchanged

acidic buffer created by mixing a weak acid together with the salt of that acid and a strong base
alkali buffers created by mixing a weak base together with the salt of that base and a strong acid
- i.e. created by mixing a weak acid/base together with its conjugate

this works as the weak acid/base only slightly dissociates in solution, but the salt fully dissociates into ions
- on addition of acid/base, H⁺/OH⁻ will be removed by neutralised by ions, forming either undissociated acid (for basic buffer) or water (for acidic buffer)

*eqns need to learn

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9
Q

titration and equivalence points depending on strength of acid/base

A

strong acid - strong base: long inflexion point – strong acid is 1-3, strong base is 12-14, therefore inflexion point lasts from minimum 3-12

weak acid/base - strong acid/base: shorter inflexion point

  • inflexion point depends on strength of acid and base
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