78910SytemsofEquations Flashcards

1
Q

What is the solution to a system of equations?

A

An ordered pair that solves all equations.

This is where the lines intersect.

If there is no solution, they don’t intersect.

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2
Q

How do you solve a simple 2-equation system?

y = 2x - 5

y = x - 2

A

Set them equal to each other.

y = 2x - 5; y = x - 2

2x - 5 = x - 2

x = 3

:: y = 1 in both equations

(3, 1)

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3
Q

How many solutions can systems of linear equations have?

A

0 (if they don’t intersect) or 1.

They are straight lines and can only intersect once.

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4
Q

Solve:

3x + 2y = 5

6x + 4y = 19

A

3x + 2y = 5 →

y - -3/2x + 5

6x + 4y = 19 →

y = -3/2x + 19

No solution. They are parallel (same slope).

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5
Q

What else is the solution to a system of equations called?

A

An Independent Solution.

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6
Q

What is another way to solve systems of equations?

A

Substitution.

Solve for one of the variables in one of the equations and plug

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7
Q

Solve, using substitution:

2x + 3y = 4

-6x + y = -7

A

2x + 3y = 4

-6x + y = -7 → y = 6x - 7

2x + 3(6x - 7) = 4

20x = 25

x = 5/4

y = 6(5/4) - 7 = ½

(Check both equations)

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8
Q

What is another way to solve a system of equations?

A

Elimination.

You can eliminate a variable by addition, subtraction, multiplication or division.

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9
Q

Solve by elimination:

2x - 5y = 12

6x + 5y = 36

A

Use addition:

2x - 5y = 12

6x + 5y = 36

8x = 48

x = 6

:: y = 0 (check both equations)

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10
Q

Solve by elimination:

5s + 4t = 27

3s + 4t = 31

A

Use subtraction:

5s + 4t = 27

3s + 4t = 31

2s = -4 → s = -2

:: -10 + 4t = 27 → 4t = 37

t = 37/4

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11
Q

How do you solve a system of 3 linear equations with 3 variables?

A

Play with using 2 equations to eliminate a variable.

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12
Q

Solve:

#1: 2x + 3y - z = 15

#2: x - 3y + 3z = -4

#3: 4x - 3y - z = 19

A

#1: 2x + 3y - z = 15

#2: x - 3y + 3z = -4

#3: 4x - 3y - z = 19

add #1 and #2 to eliminate y:

#1+#2: 3x + 2z = 11

add #1 and #3 to eliminate y:

#1+#3: 6x - 2z = 34

Add these 2 to eliminate z:

9x = 45 → x = 5

Plug into one of the 2 equations:

3(5) + 2z = 11 → z = 2

:: y = 1

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13
Q

Use elimination by multiplication to solve:

#1: 8x + 2y - 4z = 0

#2: 2x - 3y + 3z = 9

#3: -6x -2y + z = 0

A

#1: 8x + 2y - 4z = 0

#2: 2x - 3y + 3z = 9

#3: -6x -2y + z = 0

Multiply #3 by 4 → -24x - 8y + 4z = 0 eliminate z

add to #1 → -16x -6y = 0

Multiply #3 by -3 → 18x + 6y - 3z = 0

add to #2 → 20x + 3y = 9 eliminate z

You now have 2 equations with 2 variables. Set them equal:

-16x -6y = 20x + 3y - 9 Solve for y: y = -4x + 1

Plug into 2-variable equation: x = ¾ y = -2

Plug into original equation: z = ½

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14
Q

How do you graph linear equalities?

A

Graph both lines and mark the side for the inequalities and see where they intersect.

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