6.5 Compensating for Respiratory and Metabolic Disturbances Flashcards

1
Q

Two rules for compensation?

A

Compensation will never get me back exactly to normal

compensation must be made by other system

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2
Q

Why is the distal convoluted tubule and collecting duct important for respiratory acid/alkalosis?

A

Cells here are able to secrete HCO3 or H+ as conditions demand

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3
Q

If acidotic the DCT/CD cells will do what?

A

Move H+ ion to urine and take HCO3 and move it back to the blood, compensating for respiratory acidosis (plasma HCO3 levels will increase)

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4
Q

If respiratory alkalosis the DCT/CD cells will do what?

A

HCO3 will go to the urine and the H+ will go to the blood, so the HCO3 plasma levels will be lower and the pH will become more acidic

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5
Q

What is the equation for acute respiratory acidosis to calculate the expected [HCO3]?

A

Expected [HCO3] = 24 + ((PaCO2-40)/10)

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6
Q

What is the equation for chronic respiratory acidosis to calculate the expected HCO3 that will be compensating?

A

Expected [HCO3] = 24 + 4x((PaCO2-40)/10)

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7
Q

What is the equation for acute respiratory alkalosis to calculate the expected HCO3 (will decrease)?

A

Expected HCO3 = 24 - 2((40 - PaCO2)/10)

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8
Q

What is the equation for CHRONIC respiratory alkalosis to calculate the expected HCO3?

A

HCO3= 24- 5((40-PaCO2)/10)

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9
Q

What is the equation for metabolic acidosis to calculate expected PaCO2?

A

(1.5[HCO3]+8) +/- 2

if between the certain range, the determine the compensation is adequate

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10
Q

What is the equation for metabolic alkalosis to calculate expected change PaCO2 to determine if respiratory compensation is adequate?

A

(0.5 to 1.0) x changeHCO3

if between this range, compensation is adequate

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11
Q

The anion gap equation is base on the rule that positive and negatively charged anions balance themselves out. What is the equation?

A

Anion gap= [Na+] - ([Cl-]+[HCO3-])

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12
Q

What is the normal anion gap?

A

equal to or less than 16

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13
Q

Osmolarity of blood can be measured how?

Remember normal osmolarity is 290mOsmoles/L

A

Osmolarity = (2xserumNa) + (BUN/2.8) + (glucose/18)

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