6.2.4 Formation of Coloured Ions Flashcards
What does ‘degenerate’ mean in terms of electron promotion?
- In a transition metal ion
- The 3d orbitals are equal in energy
What are non-generate orbitals?
- When ligands attach to central metal ion
- Orbitals split into 2 sets of non-degenerate orbitals
What happens regarding ΔE when light shines on a transition metal element complex?
- ΔE is the difference in energy between the 2 sets of non-degenerate orbitals
- When light shines on this solution, an electron absorbs exactly that amount of energy (ΔE)
- This electron uses ΔE to excite it from a 3d orbital of lower energy to a 3d orbital of higher energy
- Electron promotion
- Other frequencies of light not absorbed are used to make the complementary colour
What is Planck’s equation?
How is the complementary colour of a complex ion formed?
- Transition metal ion absorbs the frequency of light corresponding to the exact energy difference ΔE between the 2 non-degenerate orbitals
- The frequencies of light that are not absorbed combine to form the complementary colour of the complex
What factors affect ΔE?
- Type of ligand
- Coordination number
- Oxidation state of transition metal ion
How do different types of ligands affect ΔE and the complementary colour of a complex?
- Different ligand split the d orbital by different amounts of energy
- Due to the repulsion the d orbital experience from these ligands
- So size of ΔE and frequency of light absorbed by electrons is different for each ligand
- So complementary colours observed are different for each complex, even with the same transition metal ion
Eg.
[Cu(H2O)6]2+ complex has a light blue colour
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[Cu(NH3)4 (H2O)2]2+ has a dark blue colour
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Evidence that ligands surrounding complex ions affect the colour of the complex
How does the coordination number influence ΔE and the complementary colours of complexes?
- Strength of metal ion - ligand interactions is influenced
- Usually involves a change in ligand too, so a combination of these factors alters the strength of the interactions
How does Oxidation state influence ΔE and the complementary colours of complexes?
- The higher the oxidation state
- The stronger the interaction with the ligands
- So absorbs light in the bluer (higher energy) end of the spectrum, thus appearing more orange/red in colour
Eg. [Mn(H2O)6]2+ appears pink because it absorbs in the green region of the spectrum
But [Fe(H2O)6]3+ absorbs light in the blue end of the spectrum, this appearing orange in colour
Same with Fe2+ and Fe3+ complexes
How can the colour of complex ions be determined?
- Spectroscopy
- A colorimeter measures the concentration of coloured transition metal ions in solution
- Filter chosen matching complementary colour on spectrum which the complex absorbs
- So if it appears blue, it absorbs red light, so a red filter is chosen
- Some light is absorbed, the rest is passed through to the detector
- Calibration curve of absorbance against concentration is plotted (using known standard concentrations)
What are some limitations with using visible light spectrscopy?
- Darkly coloured solutions may be hard for colorimeter to read accurately
- Colorimeter may not be sensitive enough to read pale solutions (ligand exchange can be used to convert complexes into a more strongly coloured one)