6.2.1 amines Flashcards

1
Q

naming amines

A

end in -amine e.g. propylamine

if amine is secondary and has 2 akyl groups attached to nitrogen, then each chain is named and smaller akyl group is preceded by an -N
e.g. N-methylpropylamine
- H3CH2CH2NHCH3

tertiary amine - similar rules, each alkyl side group given an N
e.g. N,N-dimethylpropylamine
- CH3CH2CH2-N-CH3
CH3

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2
Q

properties

A

primary aliphatic amines act as bases as the lone pair of electrons on nitrogen is readily available for forming a dative covalent bond with H+ and so accepts a proton

stronger bases than ammonia as akyl groups are electron releasing and push electrons towards the nitrogen atom and so make it a stronger base

NH3 + H2O > NH4+ + OH-

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3
Q

strength of aromatic amines

A

primary aromatic amines e.g. phenylamine, don’t form basic solutions as the lone pair of electrons on nitrogen delocalise with the ring of electrons in benzene ring

N is less able to accept protons

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4
Q

amine + acid

A

act as base to form ammonium salts

CH3NH2 + HCl > CH3NH3+Cl-

addition of NaOH will convert back to amine
- ionic salts will be solid crystals if water is evaporated due to strong ionic interactions
- ionic salts formed means compounds are soluble in acid

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5
Q

primary amine

A

can be formed by nucleophilic substitution reaction between haloalkanes and ammonia

reagent: excess ammonia (limits further substitution and maximises amount of primary amine formed) dissolved in ethanol

in 2nd step, second ammonia removes a proton from the intermediate (acts as a base) to form amine

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6
Q

reacting primary amines with haloalkanes

A

forms secondary amine

same nucleophilic substitution as primary amine

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7
Q

reacting secondary amine with haloalkanes

A

forms tertiary amine

same mechanism as other amine

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8
Q

reducing nitroarenes to aromatic amines

A

reagent: Sn and conc HCl

conditions: heating

mechanism: reduction

e.g. nitrobenzene + 6[H] > phenylamine + 2H2O

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