6.1.2, 3 Carbonyl compounds, Carboxylic Acids and esters Flashcards
What are carbonyls and how are they identified (5)
- Aldehydes and Ketones: CHO/ CO
- Test:
Brady’s reagent (2,4- DNP) which is an oxidising agent
When positive for carbonyls: orange crystals are formed which are hydrozones - To further detect what carbonyl, the crystals are filtered and dried, with its melting point detected.
- The melting point is compared to a database to identify the compound
Test to distinguish Aldehydes from Ketones? (3)
- Tollen’s reagent (oxidising agent) Silver nitrate is reacted with NaOH and dissolved with ammonia
The presence of silver mirrors indicate aldehyde whereas no mirrors will indicate a ketone
Ag+ ions are reduced to silver which forms the mirrors
Describe the reduction of a carbonyl with NaBH4 (6)
- Nucleophillic addition
- Reactant:
Warm and aqueous NaBH4 + carbonyl - Nucleophlie formed: Hydride ion H-
- Reduction of Aldehyde forms primary alcohol
- Reduction of Ketone forms secondary alcohol
- Overall reaction:
Carbonyl + NaBH4 = Primary/secondary alcohol + OH-
Describe the reduction of carbonyls using HCN (5)
- Nucleophillic addition
- HCN is very hazardous therefore NaCN and H2SO4 is used
- CN group extends the alkyl chain which is useful for fuels
- Nucleophile: CN-
- Overall reaction:
Carbonyl + HCN= hydroxynitriles + OH-
Describe the bonding in the carbonyl group (C=O) (4)
- The C=O bond is polar due to O being more electronegative
- The double bond has a sigma bond between C and O each orbital containing an electron
- Pi bonds due to the sideways overlapping of p orbitals above and below C and O atoms
- The shape of the C=O forms a trigonal planar with a greater angle between C and O (121) due to the repulsion of Oxygen’s lone pair of electrons
Describe the oxidation of carbonyls (4)
- Oxidising agent:
Acidified K2Cr2O7 and H2SO4 catalyst
(Cr2O72-, H+) - Aldehyde is oxidised to a carboxylic acid
Colour change of orange to green is observed - Ketone cannot be oxidised
How do you test for alkenes? (2)
- Bromine water is added which is originally orange.
- Alkene decolourises bromine as bromine is added across the double bond of the Alkene
How do you test for carboxylic acids?
- Add aqueous sodium carbonate or sodium hydrogencarbonate.
- Effervescence is observed in the presence of the acid.
- Blue litmus paper also turns red which indicates the pH is less than 7, therefore an acid.
Explain the solubility of alcohols and carbonyls compared to carboxylic acids.
- Carboxylic acids> Alcohols> Carbonyls
- Carboxylic acids can make the most H-bonds with water. It contains a polar O-H group AND a polar C=O group
- Alcohols are more soluble than carbonyls due to the polar OH group can make more H-Bonds than C=O in carbonyls
What is formed when a carboxylic acid reacts with:
- Metals
- Alkali
- Metal carbonate
- Metal: forms a salt and hydrogen gas
- Alkali: Forms a salt and water.
- Metal carbonate: Forms a salt, carbon dioxide and water.
What is a carboxylic acid derivative?
- Any compound that can be hydrolysed to form the parent carboxylic acid
All contain:
- An alkyl group/ H
- Bonded to C=O
- Bonded to another alkyl group
Includes: Esters Acyl chlorides Acid anhydrides Amides
What is an Acyl group?
Formed when a carboxylic acid reacts with thionyl chloride(SOCl2)
This reaction forms SO2 and HCl in gaseous form, which is dangerous, therefore the reaction has to be taken place in a fume cupboard.
Describe the reaction of Acyl chloride with alcohols.
Forms an ester and hydrogen chloride
Describe the reaction of Acyl chlorides and phenol.
Produces an a phenyl ester and hydrogen chloride
Describe the reaction between water and an Acyl chloride.
Forms a carboxylic acid and hydrogen chloride in a hydration reaction.
The reaction is very vigorous and produces very dense HCl fumes
Describe the reaction of an Acyl chloride and ammonia
Forms and amide and ammonium chloride
Ammonia acts as a Nucleophile by donating a lone pair from N to the electron deficient species.
Describe the reaction of an Acyl chloride and a primary amine
Forms a secondary amide where the N atom has 2 C atoms attached to it.
+ an alkyl ammonium chloride
Compare the reactivity of Acyl chlorides, acid anhydrides and Carboxylic acids.
Acyl chloride> acid anhydrides> Carboxylic acids
What are the two different ways of hydrolysing esters?
Acid hydrolysis: produces a carboxylic acid and an alcohol
Alkaline hydrolysis: produces a carboxylate salt and an alcohol
Describe acid hydrolysis. (4)
The ester is broken down in a reversible reaction:
- Under reflux
- Using dilute aqueous acid
The ester is hydrolysed by the water from the aqueous acid, the acid acts as a catalyst.
Products formed:
Parent carboxylic acid + parent alcohol.
eg Methyl butanoate will form:
Butanoic acid + methanol.
Describe alkaline hydrolysis (saponification). (4)
The ester is broken down in an irreversible reaction:
- Under reflux
- Aqueous hydroxide ions
Products formed:
Carboxylate salt + parent alcohol
eg Methyl butanoate with NaOH will form:
Sodium butanoate + Methanol
Describe 2 different esterification processes.
Condensation reaction:
- Carboxylic acid is warmed with an alcohol.
Catalyst: dilute H2SO4 - Acyl chloride and alcohol are heated together.
Describe the process of forming a carboxylic acid.
Acyl chloride + water
forms carboxylic acid + HCl in a violent, vigorous reaction.
Describe the reaction between an acid anhydride and an alcohol.
This is a form of esterification:
Acid anhydride reacts with an alcohol to form:
Ester + carboxylic acid.
No other products formed- It is not condensation
How are acid anhydride form?
The reaction between two carboxylic acids
Acid–> COOH
ANHYDride–> Without water.
Water is removed to form the acid anhydride.
Describe how an acyl chloride can be used to form:
primary amide
secondary amide
Primary amide:
R-COCl reacts with excess ammonia.
This forms a primary amide and ammonium chloride salt:
R-COCl + 2NH3 –> R-CONH2 + NH4+ Cl-
Secondary amide:
R-COCl reacts with an excess primary amide.
This forms a secondary amide and an ammonium salt with an alkyl chain:
R-COCl+ 2R-NH2 –> R-CONH-R + R-NH3+ + Cl-