6-Structure Determination (1H NMR, IR) Flashcards

1
Q

what is molecular spectroscopy

A

The study of the interaction between matter and the electromagnetic radiation (absorption, emission or transmission of radiative energy).

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2
Q

what are the two ways to determine the molecular structure of a molecule

A

Nuclear Magnetic Resonance (NMR): connectivity, structure. (main one for organic molecules)
InfraRed (IR, FTIR): functional groups

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3
Q

what are the two three types of ground and excited states?

A

vibrational, rotational, electronic states

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4
Q

discuss radio waves with respect to nuclear spin transitions, NMR spectroscopy, and MRI

A
  • Nuclear spin transitions
    • nucleus matters here
    • specific to the isotope, not the element
  • NMR spectroscopy: safe method of analysis
    • low frequency is not harmful
  • MRI: same technique used in hospitals
    • instead of a spectra, you get an image
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5
Q

how is a spectrum obtained from a sample in 1H NMR?

A
  • NMR tubes are glass
  • put sample into NMR tubes, then you put your tube into the NMR instrument
  • because protons are very abundant, the spectra can be created very fast
  • analyze the protons that exist in your molecule → able to connect the structure
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6
Q

why is deuterium used during proton nuclear magnetic resonance

A

deuterium is a H isotope that you use because it does affect the analysis of your structure and makes it easier to read your results, and identify your unknown

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7
Q

what is a spin in a nuclei and what do they generate?

A
  • All atomic nuclei possess a spin (quantum mechanical property).
  • Nuclei with spin and charge generate a magnetic moment (µ)
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8
Q

what is resonance frequency

A

the frequency at which a spin-flip occurs at the β state

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9
Q

describe free induction decay and how this leads to the NMR signal

A
  • having different spin states will create different energy states
  • When EM radiation is of the same frequency of ∆E, some nuclei are excited from α to β state.
  • have an excess at the bottom, apply the magnetic field, an electromagnetic pulse with a radio frequency will move the population from the bottom to the top when the deltaE threshold is passed
    • push the excess from alpha to beta, but then these will relax and go back to alpha
      • when they relax, the send a radio frequency of emission = that is the signal that gets picked up
  • Relaxation with reorientation occurs in a process called free induction decay.
  • This decay is the origin of the NMR signal.
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10
Q

what are the 4 characteristics of 1H NMR

A
  • Number of signals
  • Chemical shifts (δ in ppm)
  • Integration of signal peaks
  • Multiplicity/Spin-spin splitting
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11
Q

define chemical equivalence: number of signals

A
  • Number of signals: number of chemically distinct protons.

- Chemically equivalent protons: protons found in chemically identical environment - same chemical shift.

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12
Q

explain symmetry and its relation to chemical equivalence

A
  • If protons are related by symmetry (e.g. axis of symmetry), they will be chemically equivalent.
  • if there is symmetry in your molecule, they can appear under one signal
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13
Q

what are protons are shielded by

A

electrons that surround them

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14
Q

what factors account for the variation in chemical shifts

A

Slight differences in the chemical environment and electron density of the protons result in variation in the shielding degree - variation in chemical shifts (δ)

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15
Q

describe the relationship between electron density and shielding/deshielding

A
  • Shielding causes the signal to shift right (lower δ)
    • increasing electron density
  • Deshielding causes the signal to shift left (higher δ)
    • decreasing electron density
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16
Q

why is chemical shift in ppm and not Hz

A
  • To have values independent of the spectrometer intensity.
  • have to eliminate the Hz using ppm → creates a unitless value
  • can compare two spectra even if you are not using the same magnets
17
Q

what are 6 chemicals that affect the chemical shift δ

A
  • Electronegativity
  • Hybridization
  • Resonance
  • Substituents effect (in aromatic)
  • Magnetic anisotropy
  • Hydrogen bonding and exchange
18
Q

when electronegativity increases, what happens to the electron density, shielding, and chemical shift

A
  • As electronegativity increases, the electron density at the proton decreases (less shielded, resonance moves downfield): the chemical shift increases
  • More electronegative substituents, the stronger the effect.
  • chemical shift increases when there is less distance between the substituents and the proton
19
Q

when electronegativity decreases, what happens to the electron density, shielding, and chemical shift

A
  • As electronegativity decreases, the electron density at the proton increases (more shielded, resonance moves downfield): the chemical shift decreases
  • Less electronegative substituents, the weaker the effect.
  • chemical shift decreases when there is further distance between the substituents and the proton
20
Q

describe the effect of hybridization on chemical shift

A
  • As s-character increases [sp3 (25%), sp2 (33%), sp (50%)], the valence electrons will be closer to the nucleus.
  • They are held more tightly - expect deshielding - higher chemical shift.
  • the s orbital is spherical - the nucleus has a strong hold on its electrons (better retained)
    • more s character = electrons more retained by the nucleus
  • if you increase electron density, you remove that shield = higher values of chemical shift
21
Q

what is the difference between the actual and expected order with hybridization in chemical shifts

A
  • expected order: sp > sp2 > sp3
  • actual order: sp > sp3 > sp2
    • to explain this order we will have to refer to magnetic anisotropy later on
22
Q

describe the effect of resonance /conjugation on chemical shift

A
  • negative charge = increased electron density = more shielded = lower value of chemical shift
  • positive charge = decreased electron density = less shielded = higher value of chemical shift
23
Q

what happens to the chemical shift when a EWG is added to your molecule + explain the example with NO2

A

An electron-withdrawing substituent has a deshielding effect (higher δ)

  • NO2 is an electron withdrawing group
    • draw a resonance form to generate a positive charge in the ortho position and para position
    • ortho and para are the most deshielded compared to meta which is the most shielded
      • ortho and para experience the most decrease in electron density because the take on a positive charge
    • higher chemical shift → electron density is increased
24
Q

what happens to the chemical shift when a EDG is added to your molecule + explain the example with OMe

A

An electron-donating substituent (by resonance form or by inductive effect) has a shielding effect (lower δ).

  • OMe is an electron donating group
    • draw a resonance form to generate a negative charge in the ortho position and para position
      • ortho and para have the most electron density compared to meta
    • ortho and para are the most shielded compared to meta which is the most deshielded
    • lower chemical shift → electron density decreased
25
Q

when do we talk about magnetic anisotropy

A

when we have pi bonds we talk about magnetic anisotropy

26
Q

where is magnetic field found and where is ring current found

A

linear: electrons in pi bonds create two induced magnetic fields
aromatic rings: Electrons in an aromatic ring system are induced to circulate around the ring: RING CURRENT

27
Q

explain the difference in magnetic fields on top of aromatic rings vs outside of aromatic rings

A
  • On top of the benzene (interior), the induced magnetic field opposes the applied field - area of shielding
  • Outside of the aromatic ring, the induced field aligns with the applied field - area of deshielding
28
Q

describe the effects of the magnetic field when the proton is aligned with the field vs when the proton is outside of the field

A
  • if the proton is the field that aligns with the applied field
    - makes it feel even a stronger magnetic field
  • if the proton is in the field that opposes the applied area
    - makes it feel a weaker magnetic field
29
Q

describe the pattern of shielding for alkynes and alkenes

A
  • π bonds of alkenes and carbonyls: The hydrogens at the periphery are deshielded.
  • outside of cone = desheilded = higher value chemical shift
  • inside of cone = shielded = lower value chemical shift
  • whenever we have an alkyne, the H of the alkyne exists in the cone = lower chemical shift
  • whenever we have an alkene, the H of the alkenes exist outside the cone = higher chemical shift
  • benzene follows the alkene rules
30
Q

describe the effect of H-bonding and exchange on the chemical shift in OHs and amines

A
  • with an OH or NHR, we should see the protons attached to these atoms
    • have the possibility of doing H-bonding in an intermolecular way
    • if you have a low [], you are preventing H bonding = more shielded
    • if you have a high [], you encourage H bonding = more deshielded
  • instead of appearing as sharp signals, they will appear as broad signals
31
Q

what is an issue with chemical shifts? how can you distinguish protons on OH/NH from the protons on C?

A
  • Hydrogen atoms capable of hydrogen bonding may also exchange with other hydrogens.
  • Signals from exchangeable hydrogens can be identified by adding a drop of D2O
  • protons that are attached to OH or NHR will quickly changed to OD or NDR, the signal will disappear
32
Q

define what integration is and what do you need to find in order to determine the number of H’s under each peak

A
  • Integral: the area under the NMR peak that is indicative of the relative number of protons at that signal.
    • ratio
  • NMR spectrometers integrate the signals to display the relative intensities.
33
Q

how do you determine the number of protons for each signal after measuring

A
  • Add the integral heights.
  • With the molecular formula given, divide the total integral heights by # of hydrogens in the molecule.

C5H10O

  • # H’s per signal = integral height ÷ height per H
34
Q

what is multiplicity and how does spin-spin coupling relate to it

A
  • The multiplicity (number of spikes) is significant of the number of adjacent hydrogens (three bonds away from each other).
  • Origin of multiplicity: spin-spin coupling Weak magnetic fields by nearby nuclei
35
Q

what rule is used to explain spin-spin coupling

A
  • The spin-spin splitting is explained empirically by (n+1) Rule where n = # of H’s neighbors.
  • n+1 rule represents the multiplicity youre seeing
  • n being the number of neighbouring chemically non-equivalent protons
36
Q

list the multiplet, abbreviation, # of adjacent H (n), and intensity ratio

A
  • singlet, s, 0, 1
  • doublet, d, 1, 1:1
  • triple, t, 2, 1:2:1
  • quartet, q, 3, 1:3:3:1
  • anything 5 > , multiplet
37
Q

what is a diastereptopic hydrogen

A

hydrogens that are not equivalent and will appear at different chemical shifts. because they have different chemical shifts, they can undergo spin-spin coupling to each other