5.1.2 How Far? Flashcards

1
Q

What is Kc

A

Equilibrium constant

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2
Q

Kc equation

A

mA + nB -> pC + qD

Kc = ([C]^p x [D]^q) all divided by ([A]^m x [B]^n)
Products/ reactants

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3
Q

How do you work out units for Kc?

A

Place units for each reactant/product into the equation and cancel out

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4
Q

Calculating moles at equilibrium

A

Moles of reactant= initial - moles reacted

Moles of products = initial moles + moles formed

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5
Q

Calculating Kc

A
Use MICE
moles
Initial 
change
Equilibrium
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6
Q

Practical to work out equilibrium constant Kc

A

Ethanoic acid and ethanol reacted with sulfuric acid catalyst to make ethyl ethanoate

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7
Q

Stages to work out Kc in the practical

A

Work out initial amount of moles using mass density volume and then moles mass mr
Work out equilibrium moles of acid present from titre
Work out all equilibrium moles
Calculate Kc

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8
Q

Partial pressure definition

A

Pressure a gas would have alone if it occupied the volume occupied by the whole mixture

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9
Q

how do tou calculate partial pressure of a gas

A

Mole fraction x total pressure of gas

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10
Q

Mole fraction equation

A

number of moles of a gas divided by total number of moles of all gases

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11
Q

All partial pressures added together should equal what

A

Total pressure of gases

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12
Q

Kp

A

Equilibrium constant for gases
Using partial pressures
Products/ reactants

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13
Q

Kp expressions only contain what

A

Gaseous substances

Heterogeneous equilibria

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14
Q

What do Kc anx Kp change with

A

Temperature

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15
Q

Effect of temperature on Kc and Kp

A

Position of equilibria will change
Temp increased reaction favours endothermic
Shifts left
Kc decreases

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16
Q

Effect of concentration on Kc and Kp

A

Shift equilibrium but values dont change
Increases concentration moves equilibrium to right and increases other concentration
Restores equilibrium

17
Q

Effect of catalysts on Kc and Kp

A

No effect

Speeds forwards and backwards reactions at same rate

18
Q

Effect of pressure on Kc

A

Increased pressure reaction will shift to side with fewer moles of gas
Shifts right
Kc stays same
Increases conc on bottom of equation so top increases and bottom decreases to restore values

19
Q

Effect of pressure on Kp

A

Kp stays constant
Increases pressure on bottom of equation so shifts right to increase mole fraction of products to decrease mole fraction of reactants
Kp is restored