5. RNA synthesis Flashcards
Describe the human genome (3 pts)
- Humans have 3.2 x 10’9 nucleotides in human cells.
- The human genome is made up of 22 pairs of autosomal homologous chromosomes which are arranged in order of size- 1 is the biggest whilst 22 is the smallest.
- Humans have 1 pair of sex chromosomes which determine the sex of the individual-
xx= females xy= males
Describe the structure of a chromosome (3pts)
- Chromosome= Is a linear double stranded molecule of DNA. It carries genes.
- Telomere= Is the end of a chromosome. It protects the end of the chromosome.
- Centromere= Primary constriction. It is made up of lots of repeats of DNA known as megabases and it keeps the chromosomes attached to the mitotic spindle during mitosis.
Describe genes (4pts)
- Gene= A gene is a DNA segment containing instructions for making a particular protein including regulatory elements.
- Gene is a unit of hereditary which contains instructions for an organisms phenotype.
- The chromosome consists of an intregenic region which consists of 98% of the genome.
- Genes:
- Differ in size- e.g the histone genes are the smallest
- Differ in numbers of exons and introns
- Cluster into families
Describe the structure of a gene ( 5 pts)
- Promoter= Determines whether a gene is switched on and off. It is important in the regulation of gene expression.
- 5 UTR= Untranslated region. It is part of the first exon
- Exon= expressed sequences which code for the proteins
- Introns= spliced.
- 3 UTR= untranslated region. Part of the last exon.
What is Transcription (1pt)
Synthesis of MRNA from DNA
What is translation (2pts)
- Produced proteins from MRNA transcript
2. Nucleic acid to protein
Describe Human RNA polymerase (3pts)
- RNA polymerase I= ribosomal RNA
- RNA polymerase II= Protein-coding
- RNA polymerase III= Transfer RNA
Describe transcription factors (3 pts)
- Transcription factors= Proteins required to initiate or regulate transcription in eukaryotes.
- They assemble on the promoter to position RNA pol II.
- Pull apart DNA helix and expose template strand.
Describe the steps of Transcription (5 pts)
- TATA box is recognised by TATA-binding protein subunit of TFID.
- TFIIA and TFIIB bind. The TFIIA stabilises the complex.
- Other general transcription factors bind, then RNA polymerase II assembles at the promoter forming the transcription initiation complex.
- TFIIH pulls apart the DNA helix and phosphorylates RNA poll II.
- Phosphorylated RNA poll II is released from the complex and begins transcription.
Describe UTRS (3 pts)
UTR’s are transcribed but not translated
- 5 UTR= Regulation of translation
- 3 UTR= MRNA stability and MiRNA binding.
Describe RNA processing (3pts)
The primary transcript is processed in 3 steps: (CPS)
- Capping
- Polyadenylation
- Splicing
Describe capping (2pts)
- Capping occurs at the 5 prime end of the molecule.
- The cap acts as a marker of RNA polymerase to transcribed RNA. It stimulates splicing and is used for the recognition of MRNA by the protein translation machinery in the cytoplasm of the cell.
Describe Polyadenylation (4 pts)
Polyadenylation= Is the addition of a poly A tail to the end of the primary transcript.
- The DNA strand has been transcribed into the RNA molecule
- The 5 prime cap has been added at the beginning of transcription
- The cleavage signal is within the RNA molecule transcript and is recognised and cleaned by specific endonucleases.
- Then the addition of a poly A tail by the enzyme polymerase occurs.
Why is capping and Polyadenylation used (3pts)
- For stability- nucleus contains many nucleases enzymes to degrade RNA. The poly A tail prevents this degradation.
- important for transport to cytoplasm- RNA must be fully formed before it leaves the nucleus which is ensured by processing steps.
- Integrity prior to translation- cell does not want to waste energy and resources in translating a mrna molecule that is incomplete or incorrect. checks if the processing steps have been done correctly before translation can take place.
Describe Splicing (3pts)
Splicing= Removal of introns and joining of exons
- The splicesome first cleaves at the 5 prime splice site (sequence GU)
- It forms a lariat intermediate with the UG binding to the branch point.
- Cleavage then occurs again at the 3 prime site and the two exons either side of the intron are then ligated.