5. Irrotational Flow - Complex Potential and Aerofoils Flashcards

velocity potential, planar potential flows, the complex derivative, the complex potential, imposing boundary conditions, forces on streamlined bodies, origins of circulation around a wing, three-dimensional aerofoils

1
Q

High Reynolds Number Flows Past a Streamlined Object

Summary

A
  • vorticity is only generated at the object’s surface
  • it is therefore confined to a thin boundary layer around the surface of the object and to a narrow wake behind it
  • consequentially, outside these boundary layers the flow has no vorticity and is described as being irrotational
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2
Q

Velocity Potential

Definition

A
-if ∇xu_=0, we can write:
u = ∂φ/∂x
v = ∂φ/∂y
w =∂φ/∂z
-i.e. u_= ∇φ
-note that we can add any arbitrary function of t to φ
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3
Q

Incompressible and Irrotational Flows

A
- if a flow is also incompressible then:
∇.u_ = 0 
=>
∇.(∇φ)=0
=>
∇²φ = 0
-i.e. φ satisfies the Laplace equation
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4
Q

Neumann Boundary Conditions

A

-since we are now considering the edge of the boundary layer as the boundary. we can no longer impose the u_=U_ condition for a rigid boundary
-however since the volume of the boundary layers is small we can assume mass is conserved:
u_ . n_ = U_ . n_
-thus, the boundary condition on the velocity potential is:
n_ . ∇φ = φ/n_ = U_.n_
-this a Neumann boundary condition

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5
Q

The Euler Equation

A

-since we neglect the effect of viscosity, the Navier-Stokes equation reduces to the Euler equation:
ρ Du_/Dt = ρg_ - ∇P

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6
Q

The Bernoulli Equation Derivation

A

-starting with the Euler equation
-use the vector identity:
u_x(∇xu_) = 1/2∇(u_.u_) - (u_.∇)u_
-for a potential flow, u_=∇φ and ω_=0

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7
Q

Dynamic Pressure

Definition

A

p = P - ρg_.x_

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8
Q

The Bernoulli Equation

A

∇(∂φ/∂t+P/ρ + 1/2 u_.u_ - g_.x_) = F(t)
=>
∂φ/∂t+P/ρ + 1/2 u_.u_ - g_.x_ = F(t)
OR
∂φ/∂t+p/ρ + 1/2 u_.u_=F(t)
-i.e. for a steady irrotational flow, p+1/2u_.u_ is a constant
-the pressure is lower in regions of higher flow speed

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9
Q

What is the relationship between pressure and flow speed?

A

-the pressure is lower in regions of higher flow speed

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10
Q

Planar Potential Flows

A
-for planar flow:
u_ = (u(x,y),v(x,y),0)
-if the flow is incompressible:
u=∂ψ/∂y , v= - ∂ψ/∂x
-if the flow is also irrotational:
ω = 0 = ∂v/∂x - ∂u/∂y
=>
0 = -∂²ψ/∂x² - ∂²ψ/∂y²
-i.e. the streamfunction, ψ, satisfies the Laplace equation
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11
Q

Cauchy-Riemann Equations

A
∂φ/∂x = ∂ψ/∂y
∂φ/∂y = - ∂ψ/∂x
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12
Q

Laplace Equation from the Cauchy-Riemann Equations

A
  • sum the x derivative of the first Cauchy-Riemann equation with the y derivative of the second to show that φ satisfies the Laplace equation
  • sum the y derivative of the first and x derivative of the second to show ψ satisfies the Laplace equation
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13
Q

The Complex Derivative

Definition

A

-let f be a complex function of z where z=x+iy
-the derivative of f with respect to z is defined:
df/dz = lim f(z+δz)-f(z) / δz
-where the limit is taken as δz->0
-note that this definition requires that the limit is the same for all increments δz which could be in any direction in the complex plane
-thus differentiability of a complex function imposes restrictions on its real and imaginary parts

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14
Q

The Complex Derivative

Restrictions

A

-if f(z) = g(x,y) + ih(x,y) is complex differentiable, where g and h are both real functions, then we must get the same result for δz=δx as δz=iδy
=>
∂g/∂x = ∂h/∂y
∂g/∂y = - ∂h/∂x
-the Cauchy-Riemann equations, therefore both g and h must satisfy the two-dimensional Laplace equation
-i.e. the real and imaginary parts of any complex differentiable function f(z) are solutions of the Laplace equation

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15
Q

The Complex Potential

Definition

A

w(z) = φ(x,y) + iψ(x,y)

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16
Q

The Complex Potential

Fluid Velocity

A
dw/dz = ∂φ/∂x + i ∂ψ/∂x
= u - iv
-OR
u + iv = (dw/dz)*
-where * indicates complex conjugation
|u_| = √[u²+v²] = √[dw/dz {dw/dz)*]  = |dw/dz|
-and velocity direction:
α = arg((dw/dz)*) = -arg(dw/dz)
17
Q

Examples of Complex Potentials

Uniform Flow

A

-if u=Uo cosα, v=Uo sinα
-then:
dw/dz = Uo cosα - iUo sinα = Uo exp(-iα)
-and so the corresponding complex potential is:
w = Uo exp(-iα) z

18
Q

Examples of Complex Potentials

Saddle Point Flow

A

w = Az²

19
Q

Examples of Complex Potentials

Source/Sink

A

w = Alog(z) = Alog(r) + iθ

20
Q

Examples of Complex Potentials

Vortex

A

-complex potential for a vortex of circulation Γ at z=zo:

w(z) = - iΓ/2π log(z-zo)

21
Q

Examples of Complex Potentials

Dipole

A

w = m/z

22
Q

Imposing Boundary Conditions

A
  • we can only impose the continuity of the normal component of velocity for potential flows
  • in order to describe a fixed boundary, it is sufficient to impose that the streamfunction is constant along the boundary
  • we therefore need to ensure that the imaginary part of the complex potential is constant on the boundary
23
Q

Method of Images

A

-e.g. for a vortex, place an image vortex at the mirror image position on the otherside of the boundary with opposire strength
-more generally for any complex potential f(z):
w(z) = f(z) + f(z)

24
Q

Milne-Thompson Circle Theorem

A

-for the case where the boundary is a circle, |z|=a:
w(z) = f(z) + f(a²/z)*
-e.g. on the circle z=e^iθ:
w(ae^iθ) = f(ae^iθ) + f(ae^iθ)*

25
Q

Conformal Mapping

A
-using a transformation that maps the boundary onto that of a different problem for which we already know the solution
Z = g(z)
-so Z is the transformed problem
-the corresponding complex potential:
W(Z) = w(Z)
=>
W(Z) = w(g^(-1)(Z))
26
Q

The Joukowski Transformation

A

Z = z + c²/z

-maps a circle, |z|=a, onto an ellipse with semi-axes (a+c²\a) and (a-c²\a)

27
Q

Flow Past a Finite Flat Plate

A

dw/dz = dW/dZ dZ/dz
-the velocity components u and v are given by:
U - iV = dW/dZ = dw/dz (dZ/dz)^(-1)

28
Q

The Joukowski Aerofoil

A

-we can generate a symmetric aerofoil of this kind by moving the circle centre along the x-axis to z=-b before applying the Joukowski transformation
-the result is an aerofoil whose shape is given by:
Z = -b + (a+b) exp(iθ) + a²/[-b+(a+b)exp(iθ)]

29
Q

Forces on Streamlined Bodies

A

-to calculate the force exerted by the flow on the aerofoil, we only need to consider fluid pressure since we are ignoring viscous effects
-the force from the fluid pressure is given by:
F = -∫ pn_ ds
-where n_ is normal to the surface