5 & 6 - HIV Protease Inhibitors Flashcards

1
Q

What class of viruses doe HIV belong to?

A

Retroviruses

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2
Q

How does HIV infect host T cells?

A

HIV infects host T cells that have the CD4 antigen on their surface

Viral DNA enters host cell nucleus
- it is integrated into the genetic material by an Integrase enzyme

Activation of host cell then results in transcription of viral DNA into messenger RNA
- which is then translated into viral proteins

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3
Q

What’re the steps of the HIV life cycle?

A
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4
Q

After HIV mRNA has been translated into viral proteins what key step happens next?

A

Viral proteins are cleaved to active forms by HIV PROTEASE
- crucial for virion development

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5
Q

What’s an issue when treating HIV proteases with inhibitors?

A

Like reverse transcriptase inhibitors, resistance is quickly developed to protease inhibitors

Requires combination therapy for treating HIV infections

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6
Q

What enzymes can be targeted by med chemists for HIV

A

Reverse transcriptase

Integrase

Transcriptase

HIV protease

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7
Q

How do protease inhibitors differ to reverse transcriptase inhibitors?

A

Protease inhibitors are not prodrugs and do not require activation

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8
Q

What family is the HIV protease enzyme a part of?

A

It is an example of an enzyme family called the:

Aspartyl proteases-enzymes
- they contain aspartic acid in the active site
- crucial for catalytic mechanism

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9
Q

What do apartyl protease-enzymes do?

A

They catalyse the cleavage of peptide bonds

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10
Q

What is the structure of the HIV protease enzyme?

A

It is a dimer made up of 2 identical protein units, each consisting of 99 amino acids

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11
Q

In the sense of assays and analysis, why is HIV protease a good drug target?

A

It is relatively small can can be obtained by synthesis

It’s can be cloned and expressed in fast-growing cells

It is easily crystallised with & without inhibitor bound

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12
Q

What amino acids lie on the floor of the active site of HIV protease?

A

Aspa-25

Thr-26

Gly-27

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13
Q

What makes the structure of HIV protease a good target?

A

The active site is at the interface between the protein units

This means that drugs can interact on all sides = very high affinities

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14
Q

How many binding sites are there in HIV protease enzyme?

A

8
- 4 on each protein unit located on either side of the catalytic region

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15
Q

What do the sub-sites accept for binding?

A

The sub-sites accept the amino acids residues of the substrate

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16
Q

What’re the key interactions seen in the HIV protease active site?

A

Asp-25 & Asp-25’ are involved in the catalytic mechanism with a bridging water molecule

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17
Q

What is the cleavage mechanism of HIV Protease?

A

Tetrahedral intermediate is key

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18
Q

How do HIV Protease-1 and HIV Protease-2 differ?

A

They share 50% sequence identity to each other
- greatest variation is seen outside of the active site

Inhibitors are found to bind similarly to both variants of HIV Protease

19
Q

What’s the advantage of designing transition state inhibitors?

A

The advantage is that the transition transition state is likely to be bound to the active site more strongly than either the substrate or the product

Hence, inhibitors mimicking this are also likely to bind more strongly

20
Q

What is an issue (& its solution) when designing TS inhibitors of HIV protease?

A

The intermediate is inherently unstable

Hence, an inhibitor must contain a TS isostere which has a tetrahedral centre to mimic the TS.
- it also must be stable to hydrolyis

21
Q

Which functional group shows the most success in mimicking the TS?

A
22
Q

What’s the problem with designing inhibitors based on the natural substrates of HIV Protease, fitting all 8 sub-sites?

A

It makes sense to deign inhibitors that bind to all 8 sub-sites, allowing stronger interactions

However, this gives structures with high MW and consequently poor real bioavailability

23
Q

What do early HIV Protease inhibitors, like saquinavir, suffer from?

A

They have amino acid residues at P2 and P2’ leading to high MW and high peptide character
- poor pharmacokinetic properties

24
Q

What is the best approach to designing transition inhibitors for HIV protease?

A

Begin with a core unit spanning S1 to S1’ sub-sites, then grow the molecule outwards (either end) to fit into S2/S3 and S2’/S3’ subsites.

25
Q

How did the design of saquinavir begin?

A

A pentapeptide sequence was identified and the amide link between Phe—Pro was replaced by the hydroxyethylamine isostere

26
Q

What is the key binding site in HIV protease, how was this found?

A

Inclusion of asparagine at P2 gave 40 fold increase in activity

Shows that S2/S2’ is key binding site

27
Q

Is the S3 site hydrophilic or hydrophobic?

A

Hydrophobic

28
Q

Why was the bicyclic ring system added?

A

Because it occupies the S1’ site more fully

The R-configuration is CRITICAL

29
Q

Why was the ester substituted with an amide?

A

Due to metabolic stability - amides are more stable than esters to metabolism

30
Q

What is the important about the placement of the carbonyl groups either side of the hydroxyethylamine?

A

The carbonyl groups can act as H-bond acceptors to the bridging water molecule found in the transition state in HIV Protease active site

31
Q

What amino acids does the bridging water molecule bind to int he flaps of the active site?

A

Isoleucine
- Ile-50 & Ile-50’

32
Q

Where does the OH of the isostere replacement bind to in the active site?

A

It forms hydrogen bonds to both aspartic acids in the floor of the active site
- Asp-25 & Asp-25’

33
Q

What the significance of the position of the t-Bu amine?

A

It allows for further substituents on N are capable of reaching S3’.

34
Q

What about the structure of HIV protease makes it an ideal target?

A

Because of its 2-fold (C2) symmetry

Gives rise to selectivity for viral protease over mammalian aspartate proteases
- as the latter do not have C2 symmetry

35
Q

What’s the point of adding Valine here?

A

It extends the molecules to S2 and S2’ pockets to be occupied

Gave large increase to inhibitory activity

36
Q

What’s the point of adding Z-protecting groups to valine’s amine?

A

Aside from a major increase in potency, it improved the drugs ability to cross membranes

37
Q

Why were polar groups introduced at the ends of the molecule here?

A

Because, it was found that the terminal portions fo the molecule were exposed to solvation

This meant that more polar groups could be added at those positions without affecting binding

38
Q

What’s a problem within the body with adding these polar groups?

A

The pyridine groups were extensively metabolised to N-oxides that are excreted into bile

39
Q

Why was the S-OH removed?

A

Because it only formed 1 H-bond

R-OH forms 2 H-bonds with enzyme

Removing it may enhance solubility?

40
Q

Why was the pyridine ring replaced with a thiazole ring system?

A

Done to improve pharmacokinetics
- replacement of pyridine with a more metabolically stable ring system

41
Q

Describe and explain the changes made to Ritonavir after resistance rose

A

The isopropyl group, at S3, made important hydrophobic interactions with enzyme
- resistant viral strains reduced this interaction

In Lopinavir, the S3 residue is removed and cyclic urea has been included to maximise interactions at S2 site

Lopinavir is active against ritonavir resistant viruses

42
Q

Why are Lopinavir and Ritonavir administered in combination?

A

200mg Lopinavir and 50mg ritonavir

Ritonavir acts as a CYP P450 inhibitor to increase the supply of Lopinavir in blood
- boosting activity

43
Q

Give the mechanism for the synthesis of 5

A