4.1 Energetics Solids And Solutions Flashcards
Lattice Enthalpy
The Enthalpy of one mole of a solid ionic compound is converted to gas phase of its ions
Lattice Enthalpy equations
Na2O (s) => 2Na+ (g) + O2- (g)
MgF2(s) => Mg2+(g) + 2F-(g)
Group I and Group II Lattice Enthalpies as you move down the group
Lattice enthalpies decrease as the metal ions get bigger and the distance between neighbouring ions increases down the group.
Group I and Group II differences
Group II have a significantly higher lattice enthalpy as the ions charge increases resulting is higher attractions between neighbouring ions
Standard enthalpy of formation
the enthalpy change when one mole of the compound is formed from its elements under standard condition
Formation equations
Mg(s)+ Cl2(g) => MgCl2
Formation Equations applying Hess’s law
ΔfHΘ = Δatoms + Δions - ΔlattH
ΔlattH has to be endothermic ?
To overcome the attractive forces between oppositely charged ions in the lattice
ΔatomH has to endothermic ?
Energy required to break bonds between the atoms
ΔionsH has to endothermic ?
Energy needed to ionise the metal atoms is greater than the energy released on adding electrons to the non-metal atoms
ΔfH has to move exothermic ?
As energy is released when ions bond to form the lattice is greater than the energy needed to break the bond within the element
Enthalpy of atomisation
The enthalpy change when one mole of gas phase atoms are formed from the element in its standard state
First electron affinity
The enthalpy change when one mole of electrons is added to one mole of gas phase ions with a charge 1-