4 - Metals and Alloys Flashcards

1
Q
  1. 7 - When heating up a metal alloy and then rapidly cooling it, what occurs to:
    - The number of nuclei per unit volume?
    - Grain size?
A

Rapid cooling forms more nuclei per unit volume and decreases the grain size

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2
Q

4.7 What is grain refining?

A

Adding very fine, high melting metal (Ir) or oxide powder to the melt as seeds of nucleation. Produces smaller grains.

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3
Q
  1. 10 What is the relationship between finer grain size and:
    - Yield strength?
    - Ductility?
    - Ultimate strength?

Changes in these properties with grain size are related to what kind of deformation and fracture?

A

Finer grain size raises yield strength, increases ductility, and raises the ultimate strength.

Changes in these properties are related to plastic deformation and fracture

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4
Q

4.14 What will happen to a material when a crack opens up on a grain boundary?

In what size grain metals will this be more likely to occur?

A

A material will fracture.

This is more likely to occur in large grain metals when the planes can not be slipped into the adjacent grains. (The plastic deformation cannot be accommodated.)

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5
Q

4.19 What kind of deformation is caused with cold working (wrought)?

A

Plastic deformation is caused by hammering, drawing, cold forging, cold rolling, or bending.

Produces many dislocations that cannot slip easily through each other as the lattice becomes more distorted.

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6
Q

4.24 Do alloys have a melting point or a melting range?

A

A melting range

Per the phase diagram, above ACB, all liquid
Below ADB, all solid
Between is a mix of both

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7
Q

4.25 As metals are mixed together in a molten state and cooled, the resulting chemical phase depends on the solubility of the metals in each other. If the metals are soluble, what results?

A

A solid solution results.

If not soluble - eutectic system results

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8
Q
  1. 26 Au and Cu are compatible in each other at any combination
    - When they are rapidly cooled, what kind of solution do they form?
A

A solid solution with random distribution of Au and Cu atoms in the F-C cubic array

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9
Q
  1. 26 For Au and Cu - at a certain % of Au they form a ________ solution.
    - These kinds of solutions tend to have higher or lower levels of hardness and strength?
A

They form an ordered solution. Au and Cu occupy specific positions in the F-C cubic.

Ordered solutions impart higher hardness and strength to alloys.

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10
Q

4.27 When does a eutectic alloy occur?

Do pure eutectics have a melting point or a melting range? How does this point/range compare to either of the pure components individually?

A

Occurs when two metals are soluble as liquids but nearly insoluble as solids

Pure eutectics have a melting point that is lower than either of the pure components

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11
Q

4.29 The ADA uses what composition classification for noble alloys?

A

In order to be classified as a noble alloy, the alloy must have a lower limit of 25% by weight of noble metal content

(Noble metal at least 25% and no gold stipulation)

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12
Q

4.34 Pure cast gold (100% gold) is not practical for dental restoration because it lacks strength and hardness. What can we do to resolve this?

A
  1. Solid solution -
    We can mix two elements in the crystal lattice randomly and significantly increase the force needed to distort the lattice - a noble alloy

Ex. Add 10% Cu to Au
Increases tensile strength from 105 to 395
Increase BHN from 28 to 85 (Brinell Hardness Number test)

  1. Ordered solution - result depends on % content of metals and rate of cooling - specific positions occupied by specific metals

Ex. Hardness can increase by 10%, elongation decrease 30% - 12%, and yield strength increase by 25%

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13
Q

4.37 What are the composition requirements for a high noble metal?

A

Noble metal at least 60% and gold content at least 40%

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