[3.2.4] Properties of Period 3 Elements & their Oxides Flashcards
Describe the conditions/observations and the equation for the reaction between Na and water.
- Sodium reacts with cold water. It fizzes around on the surface.
- 2 Na (s) + 2 H₂O (l) -> 2 NaOH (aq) + H₂ (g)
Describe the conditions/observations and the equation for the reaction between Na and oxygen.
- Sodium burns with a yellow flame to produce a white solid.
- 4Na (s) + O₂ (g) -> 2Na₂O (s)
Describe the conditions/observations and the equation for the reaction between Mg and water.
- Magnesium reacts very slowly with cold water to form the hydroxide.
- Mg (s) + 2 H₂O (l) -> 2 Mg(OH)₂ (aq) + H₂ (g)
Describe the conditions/observations and the equation for the reaction between Mg and steam.
- Magnesium reacts readily with steam to form the oxide.
- Mg (s) + H₂O (g) -> MgO (s) + H₂ (g)
Describe the conditions/observations and the equation for the reaction between Mg and oxygen.
- Magnesium burns with a white flame to give a white solid.
- 2Mg (s) + O₂ (g) -> 2MgO (s)
Describe the conditions/observations and the equation for the reaction between Al and oxygen.
- Aluminum burns with a white flame to give a white solid.
- 4Al (s) + 3O₂ (g) -> 2Al₂O₃ (s)
Describe the conditions/observations and the equation for the reaction between Si and oxygen.
- Silicone burns with a white flame to give a white solid.
- Si (s) + O₂ (g) -> SiO₂ (s)
Describe the conditions/observations and the equation for the reaction between P and oxygen.
- Phosphorus burns with a white flame to give a white solid.
- 4P (s) + 5O₂ (g) -> P₄O₁₀ (s)
Describe the conditions/observations and the equation for the reaction between S and oxygen.
- Sulfur burns with a blue flame to form an acidic choking gas.
- S (s) + O₂ (g) -> SO₂ (g)
Describe and explain the melting points of the oxides of the elements Na-S.
MACROMOLECULAR OXIDES
- SiO₂ is macromolecular.
- It has many very strong covalent bonds between atoms.
- High energy is needed to break many strong covalent bonds therefore, it has a very high melting and boiling point.
IONIC OXIDES
- The metal oxides (Na₂O, MgO, Al₂O₃) are ionic.
- They have giant ionic lattice structures: strong forces of attraction between oppositely charged ions.
- Therefore, they have high melting points.
- The increased charge on the cation makes the ionic forces stronger going from Na to Al so leading to increasing melting points.
- Therefore, they have high melting points.
SIMPLE MOLECULAR OXIDES
- P₄O₁₀ and SO₂ are simple molecular with weak intermolecular forces between molecules (van der waals + permanent dipoles) so have lower melting points.
- P₄O₁₀ is a molecule containing 4P’s and 10 O’s. As it is a bigger molecule and has more electrons than SO₂, it will have large vdW between molecules and thus a higher melting point.
Explain why although Al₂O₃ is ionic, it displays a covalent character.
- This can be explained by the small aluminium ion with the high charge being able to get close to the oxide ion and distort the oxide charge cloud.
Describe the equation for the reaction between Na₂O and water. What is the pH of the resulting solution?
- Na₂O (s) + H₂O (I) -> 2Na⁺ (aq) + 2OH⁻ (aq).
- pH 13 - this is a vigorous exothermic reaction.
Describe the equation for the reaction between MgO and water. What is the pH of the resulting solution?
- MgO (s) + H₂O (I) -> Mg(OH)₂ (s).
- pH 9 - Mg(OH)₂ is only slightly soluble in water as its lattice is stronger so fewer free OH⁻ ions are produced and so lower pH.
Describe and explain the reaction between Al₂O₃ and water and SiO₂ and water. What is the pH of the resulting solutions?
- Al₂O₃ and SiO₂ do not dissolve in water because of the high strength of the Al₂O₃ ionic lattice and the SiO₂ macromolecular structure.
- Therefore, they give a neutral pH 7.
Describe the equation for the reaction between P₄O₁₀ and water. What is the pH of the resulting solution?
Draw the structure of the acid and describe the ionic equation that shows the formation of the anion when P₄O₁₀ reacts with water.
- P₄O₁₀ (s) + 6H₂O (I) -> 4H₃PO₄ (aq)
- pH 0 - this is a vigorous exothermic reaction.
- P₄O₁₀ + H₂O -> H⁺ + HPO₄⁻