3.2.1 - PERIODICITY Flashcards
Describe and explain the trend of melting points from Na to Al (period 3)
- increases
- charge of the metal cation increases
- attraction between cation and delocalised electrons increase, requiring more energy to break
Describe and explain the change in melting point from Aluminium to Silicon (period 3)
- increases
- Si is a giant covalent macromolecule
- infinite lattices, where atoms are held together by strong covalent bonds
- these require large amounts of energy to break
Describe and explain how melting points change from phosphorus to argon
- they are simple molecular structures
- change depending on how large the molecule is
- the larger the molecule, the more electrons
- the greater the magnitude of temporary and induced dipoles, increasing the strength of VdW’s
State the molecular formula for Phosphorus
P4
State the molecular formula for sulfur
S8
State the molecular formula for chorine
Cl2
State the molecular formula for argon
Ar
Describe and explain what happens to atomic radius across a period
- decreases
- nuclear charge increases
- shielding stays the same
- attraction between nucleus and electrons increases, pulling the atom closer together
Which element in period 3 has the highest melting point and why
- silicon, Si
- it is macromolecular
- atoms bonded together with strong covalent bonds
- require lots of energy to overcome
Which period 3 oxide is insoluble in water and why
- Al2O3 (aluminium oxide)
- close packing structure
- which period 3 hydroxide is used in medicines
- how/why
- Mg(OH)2
- used in milk of magnesia
- slightly soluble, so can raise pH of stomach acid slightly
- describe and explain the general trend in ionisation energy for period 3
- state which elements deviate from this
- generally increases, more energy required to remove outer electron
- nuclear charge increases
- atomic radius decreases
- Al and S deviate from the trend
Why does Aluminium deviate from the ionisation energy trend along period 3
- has 13 electrons
- outermost electron in 3p sub shell
- higher in energy, so is easier to remove the electron
- requires less energy
Why does Sulfur deviate from the trend in ionisation energy along period 3?
- has 16 electrons
- electrons in the 3p sub shell are paired in an orbital
- experience more repulsion, easier to remove
- requires less energy to remove electron
- What does it mean if ionisation energy for an element greatly increases after a specific number?
- E.g. jump in ionisation energy after the 5th electron is removed
- means that the next electron (e.g. the 6th) is being removed from the 2nd energy level, closer to the nucleus
- suggests that there is 5 electrons in its outer shell
- so is a group 5 element