3.1.4 The Vector Nature of Force and Newton's Second Law Flashcards

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1
Q

The Vector Nature of Force and Newton’s Second Law

A
  • Newton’s second law, Fnet = ma , is the fundamental law of dynamics.
  • Objects do not require forces to maintain uniform motion.
  • The only way to change the velocity of an object is by applying an external force to it
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2
Q

An object with a mass of 5 kg is under a constant force (10i + 20j)N. It is located at the origin of a reference frame and its velocity is (-5i + 30j)m/s. What will be its position 10 seconds later?

A

(50i + 500j)m

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3
Q

An object with a mass of 5 kg is under a constant force. Initially it is located at the origin of a reference frame. It is expected to be at (100i + 150j)m after 10 seconds. It is also expected to be at (-100i + 100j)m after 20 seconds. What is the constant force?

A

(-15i - 10j)N

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4
Q

An object with a mass of 5 kg is subject to constant force. Its initial velocity is (-10i + 30j) m/s. It is expected to be (20i + 10j) after 10 seconds. What is the force?

A

(15i - 10j)N

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5
Q

What acceleration does an object with a mass of 5 kg experience under the force (10i + 20j)N?

A

(2i + 4j) m/s^2

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6
Q

An object of mass 5 kg is experiencing an acceleration of (3i + 4j)m/s^2. How much force is applied to it?

A

(15i + 20j)N

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7
Q

An object with a mass of 5 kg is subject to two forces, (10i + 20j)N and (-5i + 10j)N. What acceleration does the object experience?

A

(1i + 6j) m/s^2

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8
Q

Two forces are applied on an object with a mass of 5 kg. The object then experience an acceleration of (-i + 10j)m/s^2. One of the forces is known to be (10i + 20j)N. What is the other force?

A

(-15i + 30j)N

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9
Q

An object with a mass of 5 kg is under a constant force (10i + 20j)N. Its initial velocity is (-5i + 30j) m/s. What will be its velocity 10 seconds later?

A

(15i + 70j) m/s

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10
Q

Three forces are applied on an object with a mass of 5 kg. The object is moving with a constant velocity of (10i + 5j) m.s/ Two of the forces are known to be (10i + 20j)N and (-5i + 30j)N. What is the other force?

A

(-5i - 50j)N

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