3.1.11 electrode potentials and electrochemical cells Flashcards
what type of reaction takes place in electrochemical cells
redox reactions, where therefore e- are transferred from the reducing agent to the oxidising agent indirectly via an external circuit (wire)
potential difference
difference in electrical potential between two electrodes. representing the energy required to move a unit charge, the PD is caused by the ability of electrons to flow from one half cell to the other (so the difference in reductive and oxidising ability allows the electric current to do work)
measured in volts
what is a half cell/electrode
how do you represent a half cell
a basic half cell is a solid metal electrode immersed in a solution of its ions; eg iron metal in FeSO4 solution.
represented with a redox equilbrium. this is because the half cell on its own has an equilibrium. ALWAYS WRITTEN IN DIRECTION OF REDUCTION. so e- on left side of equation and oxidised form is getting reduced
describe the equilibrium occurring at metal half cells
- metal atoms lose e- to become metal cations. they get oxidised
- and metal cations can lose e- to become metal atoms. they get reduced
- when eqm is reached the rate of metal atoms dissolving into metal ions is equal to the rate of ions become atoms. therefore the -ve charge on the metal (due to e- lost and left there) and the +ve charge of solution (cations) is constant
- e- are lost (forming oxidised form: ions) and picked up (forming reduced form, ions become atoms and deposit onto metal) at the solid metal electrode
what is the electrode potential
indicates the tendency of a substance to be oxidised or reduced at an electrode.
it is the difference in charge between the -vely charged solid metal and the +vely charged (bc of metal ions) solution this charge separation is also the electrochemical potential. these charges are constant at eqm so the charge separation is constant
this can only be measured by the voltage between two cells. so it is compared to a reference electrode, the SHE
EMF
voltage
potential difference
V reading under standard conditions
potential difference between two electrodes
aka V; represents energy required to move a unit charge. measured in V
about the SHE’s electrode potential
why can it be used as a reference
the standard hydrogen electrode is the reference electrode used to determine indirectly the electrode potential of a half cell. we take the electrode potential of the SHE to be 0V, it is an arbitrary reference point. by definition, not necessarily reality, the electrode potential of the SHE is 0
because of this, we can form cells by attaching another electrode to the SHE and measuring the voltage reading. this is the E potential of the other electrode. all E potential values are relative to the SHE, therefore consistent and so comparable
about the SHE’s set up
- Pt metal electrode extending from a wire
- H2 gas being bubbled into
- solution of HCl
- always left electrode (in conventional position of __ode)
-
standard hydrogen electrode therefore conditions:
1. standard pressure of H2 gas: 100kPa
2. [H+] = 1moldm3
3. 298K
the same standard conditions must be applied to all electrodes having their standard electrode potential measured.
again, what are they, and what to look out for?
100kPa
1M solutions
298K
—–
the solutions must be 1moldm3 of the ION WE NEED. so if the iron we want is Fe3+ and the given sat is Fe2(SO4)3 (Fe III sulphate) the conc of the salt would be 0.5M because it released two moles Fe3+ for every mole salt
whats the significance of the SHE always being on the left
it allows you to know about a meta electrodes oxidising/reducing tendencies from the sign
because if its positive than the more reactive electrode is on the left, as it should be. so the SHE is more reactive, so losing e-, so getting oxidised and e- are flowing from more negative electrode potential (of 0) to less negative; or more reactive to less reactive
and if its negative THIS HAS NOTHING TO DO WITH THE MAGNITUDE OF THE VOLTAGE. THIS DOES NOT MEAN OH ITS LESS THAN 0 ITS REALLY BAD. the number itself of the voltage is the magnitude of the voltage. the sign indicates direction of e- flow. if the sign is negative it means e- are flowing from, instead of as we would conventionally set it up, the conventional position of __ to that of __. so opposite to how we’d want it. indicating that the other electrode is more reactive than SHE, therefore e- are flowing FROM it TO the SHE; SHE gets reduced
why are the conditions so important when measuring the electrode potential
the potential of a half cell is affect by changes in conc, temp an pressure. all of these aspects affect the ror and therefore the eqm. position of eqm changes if conditions change; and eqm determines the charge separation and therefore the electrode potential
electrode potentials need to be comparable so to make it fair they must all be measured under standard conditions
how would a change in concentration affect an electrode/ cell
shifts to oppose the higher conc. [cation] is always 1moldm^3. if more than that, eqm will shift to decrease [cation] so shifts in direction of reduction (to metal atom). so electrode potential is more positive because less oxidation occuring
if less than that, eqm will shift to increase [cation] so shifts in direction of oxidation so more ngative E because more oxidation occuring
[[eqm positions shift to meet Kc, or more accurately, equilibria at certain temps fall into certain position which is described by Kc and therefore sysytem “adheres” to Kc but really its the opposite way]]
[[a bit about kc thats unnecessary but cute]]
all equilibria at a certain temp are basc governed by their Kc, ofc not because they know to work in accordance with that number but by nature they settle at a certain eqilibrium and Kc describes this natural phenomenon mathematically
It doesn’t control the system — it just mathematically represents the natural balance the system settles into.
when a reversible reaction happens, the rates of the forward and backward reactions naturally adjust as concentrations change.
Eventually, the system reaches a steady state where the forward and backward rates are equal — this is equilibrium.
At that point, the concentrations of the substances fit the ratio defined by Kc.
how would a change in temperature affect an electrode/ cell
ELECTRODE
depending on which way (red or ox) is exo or endo, will shift to oppose change in temp
CELL
depends on how each electrode responds to temp and how that might change the e transfer
how would a change in pressure affect an electrode/ cell
of gas electrodes eg SHE
- h2 formed in red reaction
- so when pressure increased shifts to decrease, so more oxidation, so E becomes more -ve. so no longer 0 by definition. so can’t be standard (why the conditions so important)
- when decreased, shifts to increase so E becomes more positive as moves in direction of reduction.
whats the point of the Pt electrode
characteristics that make it suitable
- inert therefore unreactive and won’t react with any of the species which would change its conc and affect the electrode potential, changing the conditions
- conducts electricity therefore electrons can flow in and out of it, allows flow of electrons and the redox equilibria in the SHE
- acts as an external electrical contact, electron sink and reserve, solid metal allowing e- to be transferred between H+ and H2
- often coated with fine Pt powder, increasing surface area so increased rate of reaction
what happens at the Pt electrode
2H+ + 2e- <=> H2
H+ get reduced at the Pt electrode, gaining e- from it and becoming H2
H2 get oxidised at the Pt electrode, losing e- to it and becoming 2H+
standard electrode potential definition
potential of an electrode measured against the SHE under standard conditions, that is to say: 1M for solutions, 298K and 100kPa
the difference in potential (V reading) between a given electrode and the SHE. measured in V
set up of a cell
each electrode hooked up with leads and crocodile clips to a high resistance voltmeter
more negative E should go on the left
two solutions connected via a salt bridge. this is a piece of filter paper moistened with/ a glass U tube filled with saturated salt solution
point of the high resistance voltmeter
- stops current flowing in the circuit
- current is the rate of flow of charge (negative charge of e- in an electrical circuit)
- as current flows the concs of ions begin to change, so no longer measuring E, which is what we wanted
- so you use this to stop current as much as pissible, so V reading is as representative of E as possible
- so you can measure PD which is what you want when determining standard electrode potentials.
point of the salt bridge
- provides an ionic connection between 2 ionic solutions. ions are free to move in the salt bridge. normally made of KNO3.
- the anion (-ve, NO3-) is attracted to +ve charge. so they move to direction of electrode being oxidised, because e- going through wire and away. so more positive.
- the cation (+ve, K+) goes to electrode being reduced because losing +ve charge because metal cations in solution being reduced.
- this movement keeps each electrode electrically neutral so reaction (flow of e-) can continue
- completes circuit by preventing a buildup of charge. allowing continuous flow of e-
cell notation - shorthand notatio to represent the redox reactions in an electrical cell
II - salt bridge
I - phase boundary, separates species in different phases
, - separates different species in same phase eg aq
- must be a solid at either end of the cell notation, whether this is Pt or another external electrical contact or the reduced form of the metal in a metal electrode
- if know more electrode with more -ve E, they go on left (so what would be the anode, gets oxidised)
- species should be arranged by ROOR; reduced forms further from salt bridge. oxidised forms nearer to the salt bridge
- include H+ AND H2O
- state symbols
what happens to the redox equilibria when a cell is formed from two half cells/electrodes
equilibria collapse
it shifts very far to left or right (so in direction of oxidation (so being oxidised) or reduction (so being reduced))
this causes flow of e, this is caused by difference in potential
so extent of e- flow is then indicative of PD
how does metal reactivity affect: the redox equilibria at its half cell;
the electrode potential of its half cell
- a more reactive metal loses e- more easily, getting oxidised to form ions. so forms ions more readily. so its eqm position is more equal or to the left because of this
- a less reactive metal forms ions less readily and for those that do, they are more likely to gain back electrons and become metal atoms. so its eqm position lies more to the right
- this means the more reactive a metal is, the more likely it will be oxidised and lose electrons. so its standard E potential will be more negative because that means it is more reactive than the SHE and the SHE gets reduced