3 - Halide ions Flashcards

1
Q

State the four halides

A

Fluoride, chloride, bromide, iodide

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2
Q

Are halides oxidising or reducing agents?

A

Reducing agents as they lose electrons

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3
Q

What is the trend in reducing ability of the halide ions down group 7?

A

Reducing ability increases

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4
Q

Why does reducing ability of halide ions down group 7 increase?

A

The electrostatic forces of attraction between outer electrons and the nucleus are weaker so they are easier to lose

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5
Q

Reaction between solid sodium fluoride and concentrated sulfuric acid

A

NaF (s) + H2SO4 (aq) → NaHSO4 (aq) + HF (g)

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6
Q

What is observed when solid sodium fluoride reacts with concentrated sulfuric acid?

A

White misty fumes of HF are given off

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7
Q

Reaction between solid sodium chloride and concentrated sulfuric acid

A

NaCl (s) + H2SO4 (aq) → NaHSO4 (aq) + HCl (g)

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8
Q

What is observed when solid sodium fluoride reacts with concentrated sulfuric acid?

A

White misty fumes of HCl are given off

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9
Q

What kind of reaction occurs between fluoride / chloride and sulfuric acid?

A

Acid-base

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10
Q

Why is there only an acid-base reaction and no further redox reaction when fluoride and chloride react with sulfuric acid?

A

Fluoride and chloride both have low reducing abilities

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11
Q

Reaction between solid sodium bromide and concentrated sulfuric acid

A

Misty fumes of HBr gas are produced initially:
- NaBr (s) + H2SO4 (aq) → NaHSO4 (aq) + HBr (g)

Bromide ions then reduce H2SO4 to SO2, orange bromine vapour and choking SO2 gas are observed:
- 2HBr (g) + H2SO4 (aq) → Br2 g + SO2 (g) + 2H2O (l)

Sulfur is reduced as its oxidation number decreases from +6 in H2SO4 to +4 in SO2
Bromine is oxidised as its oxidation number increases from -1 in HBr to 0 in Br2

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12
Q

What were the oxidation number changes in the sulfur during the reaction between bromide and sulfuric acid?

A

+6 (H2SO4) to +4 (SO2)

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13
Q

What were the oxidation number changes in the bromide during the reaction between bromide and sulfuric acid?

A

-1 (HBr) to 0 (Br2)

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14
Q

Reaction between solid sodium iodide and concentrated sulfuric acid

A

Misty fumes of HI gas are produced initially:
- NaI (s) + H2SO4 (aq) → NaHSO4 (aq) + HI (g)

Iodide ions then reduce H2SO4 to SO2, violet iodine vapour and choking SO2 gas are observed:
- 2HI (g) + H2SO4 (aq) → I2 g + SO2 (g) + 2H2O (l)

Iodide ions then reduce SO2 further to prodce H2S gas, violet iodine vapour and the rotten egg smell of H2S gas are observed:
- 6HI (g) + SO2 (g) → H2S (g) + 3I2 (s) + 2H2O (l)

Sulfur is reduced as its oxidation number decreases from +4 in SO2 to -2 in H2S
Iodide is oxidised as its oxidation number

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15
Q

What were the oxidation number changes in the sulfur during the reaction between iodide and sulfuric acid?

A

2nd reaction: +6 (H2SO4) to +4 (SO2)

3rd reaction: +4 (SO2) to -2 (H2S)

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16
Q

What were the oxidation number changes in the iodide- during the reaction between iodide and sulfuric acid?

A

-1 (HI) to 0 (I2)

17
Q

What solution can be used to test for the presence of halide ions?

A

Aqueous silver nitrate (AgNO3)

18
Q

Describe how to test for halide ions in 3 steps

A

1) Add dilute nitric acid to the sample to remove any ions like carbonates that may form precipitates with silver nitrate
2) Add the silver nitrate solution where silver ions react with halide ions to form silver halide precipitates
3) Observe the precipitate colour to identify the halide

19
Q

When testing for halide ions, what colour precipitate appears if chloride is present?

A

White

20
Q

When testing for halide ions, what colour precipitate appears if bromide is present?

A

Cream

21
Q

When testing for halide ions, what colour precipitate appears if iodide is present?

A

Pale yellow

22
Q

Some silver halides have similar colours. To confirm the identity of the halide present we can add excess…

A

ammonia solution

23
Q

What is the effect of adding dilute ammonia solution to silver chloride?

A

Silver chloride dissolves in dilute ammonia to form a complex ion
AgCl (s) + 2NH3 (aq) → [Ag(NH3)2]+ (aq) + Cl- (aq)

24
Q

What is the effect of adding concentrated ammonia solution to silver bromide?

A

Silver bromide dissolves in concentrated ammonia to form a complex ion

AgBr (s) + 2NH3 (aq) → [Ag(NH3)2]+ (aq) + Br- (aq)

Does not dissolve in dilute ammonia

25
Q

What is the effect of adding concentrated ammonia solution to silver iodide?

A

Silver iodide does not react with ammonia as it is too insoluble