3 - Halide ions Flashcards
State the four halides
Fluoride, chloride, bromide, iodide
Are halides oxidising or reducing agents?
Reducing agents as they lose electrons
What is the trend in reducing ability of the halide ions down group 7?
Reducing ability increases
Why does reducing ability of halide ions down group 7 increase?
The electrostatic forces of attraction between outer electrons and the nucleus are weaker so they are easier to lose
Reaction between solid sodium fluoride and concentrated sulfuric acid
NaF (s) + H2SO4 (aq) → NaHSO4 (aq) + HF (g)
What is observed when solid sodium fluoride reacts with concentrated sulfuric acid?
White misty fumes of HF are given off
Reaction between solid sodium chloride and concentrated sulfuric acid
NaCl (s) + H2SO4 (aq) → NaHSO4 (aq) + HCl (g)
What is observed when solid sodium fluoride reacts with concentrated sulfuric acid?
White misty fumes of HCl are given off
What kind of reaction occurs between fluoride / chloride and sulfuric acid?
Acid-base
Why is there only an acid-base reaction and no further redox reaction when fluoride and chloride react with sulfuric acid?
Fluoride and chloride both have low reducing abilities
Reaction between solid sodium bromide and concentrated sulfuric acid
Misty fumes of HBr gas are produced initially:
- NaBr (s) + H2SO4 (aq) → NaHSO4 (aq) + HBr (g)
Bromide ions then reduce H2SO4 to SO2, orange bromine vapour and choking SO2 gas are observed:
- 2HBr (g) + H2SO4 (aq) → Br2 g + SO2 (g) + 2H2O (l)
Sulfur is reduced as its oxidation number decreases from +6 in H2SO4 to +4 in SO2
Bromine is oxidised as its oxidation number increases from -1 in HBr to 0 in Br2
What were the oxidation number changes in the sulfur during the reaction between bromide and sulfuric acid?
+6 (H2SO4) to +4 (SO2)
What were the oxidation number changes in the bromide during the reaction between bromide and sulfuric acid?
-1 (HBr) to 0 (Br2)
Reaction between solid sodium iodide and concentrated sulfuric acid
Misty fumes of HI gas are produced initially:
- NaI (s) + H2SO4 (aq) → NaHSO4 (aq) + HI (g)
Iodide ions then reduce H2SO4 to SO2, violet iodine vapour and choking SO2 gas are observed:
- 2HI (g) + H2SO4 (aq) → I2 g + SO2 (g) + 2H2O (l)
Iodide ions then reduce SO2 further to prodce H2S gas, violet iodine vapour and the rotten egg smell of H2S gas are observed:
- 6HI (g) + SO2 (g) → H2S (g) + 3I2 (s) + 2H2O (l)
Sulfur is reduced as its oxidation number decreases from +4 in SO2 to -2 in H2S
Iodide is oxidised as its oxidation number
What were the oxidation number changes in the sulfur during the reaction between iodide and sulfuric acid?
2nd reaction: +6 (H2SO4) to +4 (SO2)
3rd reaction: +4 (SO2) to -2 (H2S)