2nd Order ODE Flashcards
p(t) y′′+q(t) y′+r(t)y=0
2nd order linear equation that is homogeneous
given ay’’ + by’ + cy = 0
and b^2 - 4ac > 0
general solution is y(t)=C1e^(r1t)+C2e^(r2t)
given ay’’ + by’ + cy = 0
and b^2 - 4ac = 0
y(t)=C1e^(rt)+C2te^(r*t)
and r = -b/2a
given ay’’ + by’ + cy = 0
and b^2 - 4ac < 0
y(t)=C1e^(λt)cos(μt)+C2e^(λt)sin(μt)
where λ = -b/2a and
μ = √(−(b^2−4ac))/2a
The Wronskian of 2 functions f and g
fg’ - gf’
Assume that y1 and y2 are solutions to some equation y(t) = ay’’ + by’ + cy
When are these solutions fundamental?
when the Wronskian of these solutions ≠ 0
What does it mean for solutions to be fundamental?
What can we do with them if they are fundamental
We can add them together to form all possible solutions for the differential eqn. Ex//
y = C1y1 + C2y2
t^2 y^′′+aty^′+by=0, t>0
What type of equation is this?
This is an Euler equation
How do we solve this equation?
t^2 y^′′+aty^′+by=0, t>0
1) Set x=ln(t)
2) The equation now becomes y’’+(a−1)y’+by=0
the y’s depend on x, NOT t
3) Solve this equation (Via the characteristic equation) and change back to t at the end
what is the reduction of order formula?
(assume y’’ + p(t)y’+q(t)y = 0
and y1 is given)(solve for y2)
y2 = ( ∫ (e^(−∫p(t)dt)) /(y1^2) dt)) y1
The above solution is also fundamental
p(t) y′′+q(t) y′+r(t)y=g(t)
2nd order linear equation that is nonhomogeneous
variation of parameters method of finding the particular solution of nonhomogeneous diff eqs
Y = u1y1 + u2y2 where u1 = - ∫(y2*g(t))/W(y1,y2)dt) u2 = ∫((y1*g(t))/W(y1,y2)dt) where W is the Wronskian
Undetermined coefficients method of finding the particular solution of nonhomogeneous diff eqs
must have constant coefficients. g(t) needs to be
1) a polynomial
2) an exponential
3) a sine/cosine function
4) a combo of the above
Make your guess according to one of the above
(e.g. Y = a0 +a1t +a2t^2 or de^ct or a*cos(bt))
plug in to the original equation (Y -> y, Y’ -> y’ etc)
solve for the undetermined coefficients)
How to tell beforehand whether my guess will work and what to do if it doesn’t. (Used in undetermined coefficients method)
1) Write homogeneous equation and find fundamental solutions y1 and y2.
2) Depending on the form of g, write a guess Y for a particular solution of the homogeneous equation
3) Check whether y1 or y2 (perhaps ,multiplied by an undetermined constant) appears in Y.
i) If So, multiply your entire guess by t to obtain a new guess. Repeat Step 3
ii) If Not, your guess is good
How can you solve this?
p(t)y’’ + q(t)y’ + r(t) = g(t) + f(t)
Them up into two different NH eqns
(e.g. p(t)y’’ + q(t)y’ + r(t) = g(t) and p(t)y’’ + q(t)y’ + r(t) = f(t))
find the particular solution to both of these
(e.g. Y1 and Y2 respectively)
add these two up to find the particular solution of the given eqn
(e.g. Y = Y1 + Y2)