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Maths > 2nd Form Terminology > Flashcards

2nd Form Terminology Flashcards

1
Q

How to put a number into standard form (and example - 40,000)

A

40,0. 0. 0
Etc 10^1 10^0

With four 0s, so 4 x 10^4

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2
Q

How do you put 19000 into standard form

A

4 numbers after first non-zero digit so 1.9x10^4

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3
Q

How do you put 0.00065 into standard form

A

4 numbers before first non-zero digit (including number infront of decimal point) so 6.5x10^-4 (going backwards so negative)

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4
Q

How do you take 6x10^6 out of standard form

A

6 zeroes so 6,000,000

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5
Q

How do you multiply 2 standard form numbers together

A

Numbers first, powers of ten second

(4x10^8) x (2 x 10^-3)
8 x 10^5 (index laws a^m x a^n = a^m+n)

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6
Q

How do you do standard form division

A

Write the problem as a fraction, numbers first, powers of 10 second

8x10^5 / 2x10^3

8x10^5
———. = 4x10^2
2x10 ^3

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7
Q

How do you add + subtracts 2 standard forms together

A

Collect like terms, match the bigger power of 10
5 x 10^3 - 3 x 10^3 = 2 x 10^3
8 x 10^7 + 3 x 10^6 = 8x10^7 + 0.3 x 10^7 = 8.3x10^7

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8
Q

Make M the subject of the formula:

2m - 20 = 10 + 7m

A

Collect all the m together: -20 = 10 + 5m
Subtract the 10 from both sides: -30 = 5m
Divide by 5: m = -6

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9
Q

Make x the subject of the formula

5(x+3) = 3(x+9)

A

Expand the brackets: 5x + 15 = 3x + 27
Put the x together: 2x + 15 = 27
Subtract 15 from both sides: 2x = 12
Divide by 2: x = 6

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10
Q

How do you solve simultaneous equations (elimination)?

A

Add or subtract the equations to cancel out one of the unknowns, you might have to scale up one of or both of the equations

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11
Q

Solve the simultaneous equations

3p + 2q = 9
5p - 2q = 31

A

-Add them together to cancel out the 2q
8p = 40
-Divide by 8
P = 5

Substitute into the equation:
3p +2q = 9
15 + 2q = 9
-solve:
2q = -6
Q = -3

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12
Q

Solve the simultaneous equations
X - 3y = -23
5x + 2y = 4

A

Scale the first equation up and subtract them to cancel the x
5x + 2y = 4
5x - 15y = -115

-13y = -119
Y = 7

Substitute into the equation
5x + 2y = 4
5x + 14 = 4

Solve
5x = -10
X = -2

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13
Q

Make b the subject of the formula
A = 3b + 9

A

A - 9 = 3b
(A-9)/3 = b

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14
Q

Make x the subject of the formula
Y = (2x+3)/4

A

4y = 2x+3
4y-3 = 2x
(4y-3)/2 = x

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15
Q

How do you work out one interior angle of the polygon?

A

(N-2) x 180
If n = 5, (5-2) x 180
3 x 180 = 540

540 = sum of interior angles
One interior angle = 540/5 = 108

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16
Q

How do you take a bearing

A

Know where you are working FROM - a FROM b
Put in a north line from there - from b
Measure CLOCKWISE from north
If less than 100 still use 3 figs (047)

17
Q

How do you draw a perpendicular bisector

A

Set your compass to more than half (3/4 ish) the distance to AB
Arc from A, then arc from B
Join the two arc intersections with a straight line

18
Q

How do you draw an angle bisector

A

Set your compass at a sensible distance along line BC
Put the point of your compass at the point of the angle
Arc to intersect BA and BC, label them D and E
Arc from D and E
Join the intersections of the arcs with the point of angle B

19
Q

How do you multiply double and triple brackets

A

Double: (A+b)(c+d) = ac + ab + ad + bd
Triple: multiply 2 into a bracket and then multiply the remaining 2.

20
Q

How do you factorise x^3 + 2x^2

A

Common factor x^2
X^2(x + 2)

21
Q

A linear or arithmetic sequence has a ______ difference

A

Constant

22
Q

The first three terms of a linear sequence are
5, 8, 11
What are the next two terms

A

14, 17

23
Q

Find P if x equals 2
P = 2(2x + 3) + 2(x+5)

A
24
Q

32/40 as a percentage

A

32/40 = 16/20 = 85%

25
Q

How do you find a percentage

A

Convert to a decimal and multiply by amount

26
Q

75% of £20

A

0.75 x 20 = 15

27
Q

How do you increase/decrease by a percentage

A

Work out the new percentage eg (85% or 105%) and multiply

28
Q

CALCULATOR:
decrease 90ml by 7.5%

A

100 + 7.5 = 107.5%
1.075 x 90 = 83.25ml

29
Q

CALCULATOR:
Increase 204 by 98%

A

198% of 204 = 1.98 x 204 = 403.92

30
Q

How do you find the change in percentage?

A

Work out the difference between the two values, write the difference as a fraction of the original value, x100 ( convert to a percentage)

31
Q

What is the percentage change if a coat went from £40 - £56?

A

56 - 40 = 16
16/40 = 40% increase

32
Q

A cars value went from £20,000 to £16,000. What is the percentage change?

A

20,000 - 16,000 = 4000

4000/20,000 = 1/5 = 20% decrease

Maths (1 decks)

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