24.4 Ligand Substitution & Precipitation Flashcards
Appearance of aqueous Cu2+
Blue solution
Appearance of aqueous Fe2+
Pale green solution
Appearance of aqueous Fe3+
Pale yellow solution
Appearance of aqueous Mn2+
Pale pink solution
Appearance of aqueous Cr3+
Violet solution
Observation when NaOH or NH3 is added DROPWISE to Cu2+
Blue precipitate
Observation when NaOH or NH3 is added DROPWISE to Fe2+
Green precipitate (turns orange-brown on standing - oxidises to Fe3+)
Observation when NaOH or NH3 is added DROPWISE to Fe3+
Orange brown precipitate
Observation when NaOH or NH3 is added DROPWISE to Mn2+
Light brown precipitate (darkens on standing)
Observation when NaOH or NH3 is added DROPWISE to Cr3+
Grey-green precipitate
Observation when EXCESS NH3 is added to Cu2+
Precipitate dissolves to form dark blue solution
Observation when EXCESS NH3 is added to Fe2+
Precipitate is insoluble
Observation when EXCESS NH3 is added to Fe3+
Precipitate is insoluble
Observation when EXCESS NH3 is added to Cr3+
Precipitate dissolves to form purple solution
Observation when EXCESS NH3 is added to Mn2+
Precipitate is insoluble
Observation when EXCESS NaOH is added to Cu2+
Precipitate is insoluble
Observation when EXCESS NaOH is added to Fe2+
Precipitate is insoluble
Observation when EXCESS NaOH is added to Fe3+
Precipitate is insoluble
Observation when EXCESS NaOH is added to Mn2+
Precipitate is insoluble
Observation when EXCESS NaOH is added to Cr3+
Precipitate dissolves to form dark green solution
Equation for ligand substitution of [Cr(H2O)6]3+ with NH3, and associated colour changes
[Cr(H2O)6]3+ (aq) + 6NH3 (aq) ⇌ [Cr(NH3)6]3+ (aq) + 6H2O (l)
Octahedral violet solution → octahedral purple solution
Equation for ligand substitution of [Cr(H2O)5 SO4]+ with NH3 and associated colour changes
[Cr(H2O)5 SO4]+ (aq) + 6NH3 (aq) ⇌ [Cr(NH3)6]3+ + 5H2O (l) + (SO4)2- (aq)
Octahedral green → octahedral purple
Equation for ligand substitution of [Cu(H2O)6]2+ with NH3 and associated colour changes
For copper a partial exchange occurs:
[Cu(H2O)6]2+ (aq) + 4NH3 (aq) ⇌ [Cu(NH3)4 (H2O)2]2+ + 4H2O (l)
Pale blue → dark blue
Equation for ligand substitution of [Cu(H2O)6]2+ with Cl- (from conc. HCl)
[Cu(H2O)6]2+ (aq) + 4Cl- (aq) ⇌ [CuCl4]2- + 6H2O (l)
Octahedral pale blue → tetrahedral yellow
Structure of haemoglobin
- 4 protein chains held together by weak intermolecular forces
- Each one contains a haem molecule
- Within this, central metal atom is Fe2+ which can bind to O2
How does haemoglobin transport O2/CO2 around the body?
- O2 forms a weak dative bond with Fe2+ in the lungs
- Releases it at the body cells and binds to CO2
- CO2 carried back to lungs and is exhaled
What happens if CO is breathed in?
- Ligand substitution takes place
- O2 replaced with CO, forming carboxyhaemoglobin
- CO binds very strongly so it prevents O2 from being carried
- Leads to death if [CO] becomes too high