2: Water Flashcards

1
Q

How do you calculate density?

A

Density= mass/volume

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2
Q

What are the main/unusual properties of water?

A
  • Expands when frozen
  • Ice has a lower density than liquid water, so icebergs will float. Water at 4 degrees is at the bottom of the lake, with ice at the surface.
  • Unusually large surface tension (property of a fluid to resist external force) due to H bonding
  • Dielectric constant (relative permittivity) : relative amount of electrical energy stored in a material vs vacuum. Very polar solvent & allows salts to dissolve
  • High heat capacity : amount of heat required to raise temp by 1 degree C without changing phase
  • High latent heat of vapourisation : amount of heat energy required to convert liquid to vapour without changing temp (e.g. from liquid to gas = still 100*C)
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3
Q

Explain bonding in water

A

The unpaired electrons on oxygen each pair up with a single electron from hydrogen to form permanent covalent bonds. The unbonded pairs of electrons on oxygen are available to form temporary hydrogen bonds with other molecules.

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4
Q

Water is dipolar. Explain what this means

A

Oxygen is more electronegative (electron-attracting) than hydrogen. Within the water molecule the oxygen is slightly negative and the hydrogens are slightly positive.
Means that:
-It forms H bonds with other dipolar & ionic groups, but not with non-polar molecules, e.g. fats

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5
Q

Explain the process of determination of water content

A
  1. Weigh a dry container (dish) and record weight
  2. Grind/mince foodstuff
  3. Weigh sample in container and record weight
  4. Heat at specified temp for specified time (or freeze dry)
  5. Weigh sample & container and record weight
  6. Repeat heating/weighing cycle to constant mass
  7. Calculate mass loss
    Mass loss varies with heating conditions
    Loss of substances other than water (volatiles)
    Incomplete removal of ‘bound’ water
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6
Q

How do you calculate percentage of water on a fresh weight basis (fwb)?

A

%water = mass loss/original food mass x100

(%water fwb is always less than 100%)

Mass loss = mass of food & dish - mass of dish & contents after drying
Original food mass = mass of food & dish - mass of dish

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7
Q

How do you calculate percentage of water on a dry weight basis (dwb)?

A

%water dry basis = mass loss/food mass after drying x100

Mass loss = mass of food & dish - mass of dish & contents after drying
Food mass after drying = mass of dish & contents after drying - mass of dish

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8
Q

How does water content affect food stability?

A

Foods with high water content spoil more rapidly.
- Can inhibit deterioration by making water unavailable for chemical, enzymatic & microbial reactions

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9
Q

How can water be made unavailable in foods, to inhibit deterioration?

A
  • Remove water e.g. drying or concentrating (milk powder, sultanas)
  • Immobilise water e.g. freezing or adding sugar or salt (jams, cured fish/meat)
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10
Q

Explain strongly bound water, and how this impacts the water activity (aw)

A

Strongly bound water has a lower water activity than weakly bound water.
Strongly bound water:
* Does not move easily within a food
* Does not freeze (cannot move to form ice crystals)
* Does not act as a solvent
* Is not available to take part in spoilage reactions
* Does not escape easily into the atmosphere i.e. has low vapour pressure

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11
Q

Give the formula for water activity

A

aw = p/p0
p = vapour pressure of water in equilibrium with sample
p0 = vapour pressure of pure water at the same temp

aw x 100 = Equilibrium Relative Humidity (ERH %)

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12
Q

Define vapour pressure

A

The tendency of molecules to escape from a liquid

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13
Q

Give the subdivisions of water based on the strength of its binding

A
  • Free/bulk water
  • Entrapped water
  • Bound/multilayer water
  • Vicinal/monolayer water (closest to food surface)
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14
Q

Why might aw increase

A

With increased temperature. Water moves from regions of high to low aw

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15
Q

Describe vicinal/monolayer water

A
  • Most strongly bound, closest to food surface
  • Largest binding energy
  • Removal of heat is difficult and irreversible (as binding surface damaged)
  • Does not freeze (cannot move into crystal lattice)
  • Not a solvent
  • Associated with proteins, polysaccharides, salts, especially insoluble structures
  • aw = 0.25 approx
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16
Q

Describe bound/multilayer water

A
  • Successive layers bound by hydrogen bonding
  • Strength of binding declines progressively
  • Water held in smaller capillaries
  • aw = 0.8 approx
  • Freezing point decreased substantially (doesn’t freeze until below -40 degrees C)
17
Q

Describe entrapped water

A
  • Physically held / entrapped in the food matrix (behind membranes, in capillaries, prevented from flowing freely by gel structure)
  • Up to 96% of total water of a typical high moisture food
  • Solvent capacity, freezing point, water mobility all reduced slightly vs free water. Can move short distances
18
Q

Describe free / bulk water

A
  • Behaves like pure water
  • Up to 96% of total water of a typical high moisture food
  • Held within structure, but readily squeezed out by pressure
  • Solvent capacity and freezing point are normal
19
Q

What is the cause of temporary water hardness, and how can it be removed?

A

Due to bicarbonates. Removed by boiling

20
Q

What is the cause of permanent hardness, and how can it be removed / softened?

A

Caused by sulphates and chlorides.
2 methods: lime softening & ion exchange cartidges

21
Q

Describe the method of lime softening

A

Add slaked lime and soda ash to water. Calcium will precipitate to become calcium carbonate; & magnesium will precipitate to become magnesium hydroxide.
Softened water can be used in heat transfer. Process also kills bacteria

22
Q

Describe the method of using ion exchange cartridges to soften water.

A

Resins in cartridges have sodium ions temporarily associated. Hard water replaces sodium ions with calcium & magnesium ions inside exchanger.
Soft water with sodium ions leaves exchanger. Sodium ions restored by adding NaCl to exchanger

23
Q

Name 5 examples of waterborne pathogens (diseases) caused by faecal bacteria

A
  1. VTEC (verocytotixin E. coli)
  2. Salmonella
  3. Shigella
  4. Vibrio cholera (cholera)
  5. Campylobacter
24
Q

Give 2 examples of enteric viruses caused by waterborne pathogens

A

Hepatitis A
Norovirus

25
Give 2 examples of parasites caused by waterborne pathogens
Cryptosporidium Cyclospora
26
Explain the method of potable water treatment
1. Water from water source screened to remove large particles (e.g. leaves); and is aerated. 2. Put through a flash mixer & mix with aluminium sulphate to help floc formation (sludge) 3. Allow floc to settle in flocculation tank 4. Pass water through sand filtration & inject ozone & activated carbon for pH control 5. Chlorination to kill microorganisms 6. UV disinfection Repeat steps 3-5 to reduce bacterial load
27
How many ppm (parts per million) of chlorine should water used for fruit & salad washing be?
50-200 ppm chlorine Added when pH is 6.0 (as HOCI / hydrochlorous acid is 97% efficient) Short contact time = 1-2mins Results in approx. 99% reduction in total viable count of microorganisms
28
Why is it important that fruit & salad is prewashed before undergoing HOCI/chlorinated water treatment?
To remove as much soil & organic matter as possible as this inactivates HOCI
29
Give 4 common contaminants of produce
1. Norovirus 2. Salmonella 3. Cyclospora 4. Listeria
30
Give examples of sources of contamination of produce
Farm worker hygiene Manure Unsanitary conditions on farm processing Contaminated irrigation water/flooding
31
Explain the process of sewage/effluent treatment
1. Sewage/effluent is screened to remove large particles and is then placed in settlement tanks to sediment organic matter (sludge) - sludge can be used for fertiliser; anaerobic respiration; biogas & burning 2. Aeration occurs : good bacteria consume bad bacteria 3. Sludge forms again in final settlement (also used for fertiliser, etc.) 4. Sand filtration 5. Remaining goes back into river
32
How is water pollution tested?
1. BOD (Biochemical/Biological Oxygen Demand) - amount of dissolved O2 needed for microbial oxidation of biodegradable matter in an aquatic environment 2. COD (Chemical Oxygen Demand) - amount of O2 consumed in a chemical oxidation of organic compounds in an aquatic environment COD>BOD
33
How can you test for BOD? What should properly treated effluent be?
Add waste sample to aerated water, incubate at 20 degrees C for 5 days. Measure O2 used. Properly treated effluent should be <20mg/L (sewage has a BOD of 600mg/L)
34
How can you test for COD?
Add waste sample to boiling dichromate solution. Measure O2 used. Expressed as mg/L or ppm. (treated: 200-1000mg/L)
35
How can BOD value be reduced?
Biological (aerobic oxidation) : Organic compound + oxygen + minerals + biomass -> CO2 + H2O + more biomass + heat Anaerobic digestion : Organic compound + minerals + biomass -> CO2 + CH4 +/- H2O + more biomass + heat (Generally used in gases where there is heavy contamination e.g. farm slurry)
36