2 Gas Laws Flashcards
How is P1 and T1 related to P2 and T2?
P1 is pressure before
T1 is temperature before
P2 is pressure after
T2 is temperature after

Explain why a hot balloon expands
As temperature rises, the particles have more energy
Particles have more KE
Particles move faster
More collisions per unit time AND particles collide with more force
Pressure = force / area
Increased pressure on the inside of the balloon, with same pressure on the outside results in greater forces on inside compared to outside of balloon - balloon skin stretches outward

What are the control variables for the Boyles’ Law investigation where the volume of a gas was measured as the pressure was varied?

Moles or mass of gas
Temperature of gas
Use the equation below to calculate the new volume of a gas as its pressure increased from 100kPa to 200kPa.
Its initial volume was 50cm3.

P2V2 = P1 V1
V2 = P1V1/P2
V2 = 100kPa x 50cm3 / 200kPa
V2 = 25cm3
Convert 373K to ºC
ºC = K - 273
373K = 100ºC

How does a gas exert pressure of the inside of a balloon?
- Gas particles are moving fast and freely
- They collide with the walls of the balloon
- They exert a force of the wall of the balloon
- Pressure = force / area
- Particles exerting a force on the area of the balloon creates a pressure.
Convert 100K to ºC
ºC = K - 273
100K = -173ºC

Name the independent and dependent variable for the Joly’s bulb experiment

Independent : temperature gas
Dependent : pressure of gas

What happens to the pressure of a gas if the volume is halved?
Explain why this happens.
As volume is halved, pressure is doubled
There are the same number of particles as the volume is halved
OR double the number of particles per unit volume
Pressure = force / area
Double the number of collision per unit time per unit area.

Name the independent and dependent variable for Boyle’s law experiment

Independent : pressure
Dependent : volume of gas

What happens to the particles of a gas when they are heated?
The particles gain energy
KE of particles increases
Particles move faster

Convert 100ºC to Kelvin
K = ºC + 273
100ºC = 373 K

How would you represent the motion of a smoke particles in air? (Brownian motion)
Uses arrows of different length and directions to show continual random movement.

What is the unit for volume of a gas?
cm3 or dm3
How many Pa is a kPa?
1000 Pa = 1 kPa
From the graph, how is pressure of a gas related to its volume at the same temperature and moles of gas?

Pressure is inversely proportional to volume at same temperature and moles of gas
Convert -273ºC to Kelvin
K = ºC + 273
-273ºC = 0 K

A pupils stated that as the temperature of a gas in degrees celsius is doubles, the kinetic energy of the gas must also double.
Is this statement true or false?

False
At t_emperature of a gas in kelvin doubled,_ the average kinetic energy of the particles doubles
Temperature must be in kelvins!!
How is P1 and V1 related to P2 and V2?
P1 is pressure before
V1 is volume before
P2 is pressure after
V2 is volume is after

Use the pressure-temperature equation to work out the new temperature for a gas where the pressure was decreased from 100kPa to 50kPa
Intial temperature was 40K.

T2/P2 = T1/P1
(write the equation with T2 first- this makes it easier to rearrange!!)
T2= T1P2/P1
T2= 40K x 50kPa / 100kPa
T2 = 20K
How can Brownian motion be observed?
Random jerky movement of smoke particles in a smoke cell through a microscope

What is the unit for pressure
Pascal (Pa)
kilopascal (kPa)
atmospheres (atm)
A pupils stated that as the temperature of a gas in kelvin is doubled, the average speed of the gas must also double.
Is this statement true or false?

False
At t_emperature of a gas in kelvin doubles,_ the average kinetic energy of the particles doubles, NOT the average speed
Why does an air balloon grow bigger when air is heated

As temperature of a gas increases, kinetic energy increases
particles move with greater speed and hit the sides of the balloon more frequently AND with more force
Pressure = force / area
Greater force on walls of balloon increases the pressure of the gas pushing the walls of the balloon outward.
















