1D Kinematics

Question 1

Solve for v_f

v_f² = v_i² + 2aΔx

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Answer 1

v_f = √( v_i² + 2aΔx)

Question 2

What is average speed?

Answer 2

The average speed of an object over the entire course of its journey.

Question 3

What is instantaneous speed?

Answer 3

The speed of an object over a very short interval of time.

Question 4

What does the slope of a straight position vs time graph represent?

Answer 4

The average velocity.

Question 5

How do you find the instantaneous velocity at a certain time from a position vs time graph?

Answer 5

Draw a tangent to the line at that time and find the slope of the tangent.

Question 6

Define acceleration.

Answer 6

• The rate of change in velocity.
• meters/second/second
• m/s²

Question 7

What is the difference between speed and velocity?

Answer 7

Speed is a scalar and velocity is a vector.

Question 8

What is acceleration, a scalar or a vector?

Answer 8

vector (direction matters)

Question 9

What does the slope of a velocity vs time graph represent?

Answer 9

acceleration

Question 10

Δx

answer with as many connecting concepts as possible

Created by Colletti

Answer 10

• displacement, change in position
• symbol in an equation
• x_f - x_i

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Question 11

Solve for Δt

a = Δv/Δt

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Answer 11

Δt = Δv/a

Question 12

Solve for v_i

v_f² = v_i² + 2aΔx

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Answer 12

v_i = √(v_f² - 2aΔx )

Question 13

Solve for Δx

v_f² = v_i² + 2aΔx

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Answer 13

Δx = (v_f² - v_i²) / 2a

Question 14

Solve for Δt

v_f = v_i + aΔt

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Answer 14

Δt = (v_f - v_i) / a

Question 15

What is g?

Answer 15

• the acceleration due to gravity
• 9.8 m/s² downward

Question 16

freefall

Answer 16

• a_y = g = 9.8 m/s² downward
• a_x = 0

Question 17

dropped

Answer 17

• V_iy = 0
• a_y = g = 9.8 m/s² downward (if air resistance is negligable)

Question 18

If an object is dropped, what is it’s speed after 2 seconds?

Answer 18

19.6 m/s

Question 19

What must you always remember when calculating projectile motion?

Answer 19

Horizontal and vertical projectile motions are independent of each other.