1.7 Simple Equilibria and Acid-Base Reactions Flashcards
What is meant by a ‘reversible reaction’?
A reversible reaction is a reaction in which the products can react together to form the original reactants.
What is meant by ‘dynamic equilibrium’?
Dynamic equilibrium occurs in a reversible reaction when the rate of the forward reaction equals the rate of the backwards reaction. The concentration of the reactants and products are constant.
What is Le Chatelier’s principle?
If a change is made to the conditions of a reversible reaction, the position of equilibrium will move to counteract the change.
How does increasing the temperature affect the equilibrium position?
Increasing the temperature will favour the endothermic reaction, so the equilibrium will shift towards the products of the endothermic reaction.
How does decreasing the temperature affect the equilibrium position?
Decreasing the temperature will favour the exothermic reaction, so the equilibrium will shift towards the products of the exothermic reaction.
How does increasing the pressure affect the equilibrium position?
Increasing the pressure favours the side of the reaction with fewer moles of gas, so the position of the equilibrium will move to that side.
How does increasing the concentration of the reactants affect the position of equilibrium?
Equilibrium will shift to the right to increase the concentration of the products.
What is Kc?
The equilibrium constant.
The magnitude indicates whether there are more reactants or products in an equilibrium system.
How do you calculate Kc?
aA + bB ⇌ cC + dD
Kc = [C]^c[D]^d / [A]^a[B]^b
Deduce an expression for Kc for the equation below
3H(2)(g) + N(2)(g) ⇌ 2NH(3)(g)
Deduce an expression for Kc for the equation below
3H(2)(g) + N(2)(g) ⇌ 2NH(3)(g)
How do you work out the units for Kc from the expression?
What is the effect on Kc if the concentration of the reactants are increased?
Concentration has no effect on Kc.
What is the effect on Kc if the pressure of the system is increased?
Pressure has no effect on Kc.
Why does the addition of a catalyst not affect the value of Kc?
A catalyst does not move the position of equilibrium, it only increases the rate at which equilibrium is reached.