15.3 Reactions of alcohols Flashcards
How do alcohols burn in enough oxygen
They completely burn to produce carbon dioxide and water
If it is incomplete combustion, carbon monoxide and carbon may be produced
Give equation for complete combustion of ethanol
C2H5OH + 3O2 —> 2CO2 + 3H2O
What is an elimination reaction
. A small molecule leaves the parent molecule
Describe the elimination reaction in an alcohol
What is it called
. The small molecule leaving is water, which is made from the OH group, and a hydrogen on the carbon next to the carbon with the OH group
Called dehydration
How does dehydration occur in alcohols
What are alcohols reacted with for it to react
What is the product
- Excess hot concentrated sulfuric acid
or - Pass the alcohol vapours over heated aluminium oxide
Product is an alkene
What is the overall reaction mechanism for dehydration of alcohols to produce alkenes and water
Eg in propan-1-ol
What is the specific mechanism for each stage of the reaction
. An OH on one carbon, and a hydrogen on an adjacent carbon will react together, so draw circle around them, and curved arrow pointing to a H2O which shows that they produce that
. Then draw a straight arrow to show the product, propene and then a H2O
The Stages:
. The OH on the propan-1-ol: the O has a lone pair which are attracted to H+ ions from the acid, so a curled arrow will come off it and point to a H+ ion, as a covalent bond is formed
. So this H joins the molecule by the oxygen, so the overall molecule has an O connected to two H at the end of it, so the O has a + charge
. So the bond between the oxygen and the carbon breaks as the lone pair on carbon goes to the oxygen with a curled arrow
. Then a hydrogen from an adjacent carbon sends the lone pair to the C-C bond making it a double bond
So overall propene is formed and a H+ and H2O
What solution is used to oxidise alcohols
What colour is it
A solution of potassium dichromate, K2Cr2O7, is acidified with H2SO4 is often used to oxidise alcohols
The orange dichromate (IV) ions are reduced to green chromium (III) ions
Describe process of oxidation of primary alcohols
Eg ethanol, so the OH is on the end of it
What is the equation
It is oxidised to make ethanal, and water is released
We lose a hydrogen from the carbon and the hydroxyl group (the OH group in alcohols) to make water
And then when it’s oxidised, an oxygen binds to the carbon in a double bond C=O.
This is now an aldehyde
Then, further oxidation occurs which turns the aldehyde into a carboxylic acid.
The carbon that is currently bonded to the O and an H: The oxidation adds an oxygen molecule to the H so it is now OH
So the carbon is bonded to an OH and =O
The equation is ethanol with an arrow pointing to ethanal and then an arrow pointing to ethanoic acid.
over each arrow is an [O] to show it is getting oxidised
How do you end up with a double C=C bond when oxidising alcohols eg in ethene
Before, we have one bond of carbon to oxygen, but in the mechanism we lose a bond of carbon to hydrogen, and we’re going to gain another bond of carbon to oxygen
Because oxygen is being added
So a double C=O bond will form
What would the oxidation state of the C connected to OH in the alcohol be before the oxidation
What about after the reaction when it is now an aldehyde
What about after further oxidation when it is a carboxylic acid
Before the reaction, the carbon is bonded to the OH group, but as oxygen is more electronegative than carbon, the oxygen would take both electrons in the bond.
The carbon is also bonded to two hydrogens, and in both bonds, carbon is more electronegative so would take both pairs of electrons.
The carbon bonded to another carbon will have an even split of the pair of electrons so one electron would go to each carbon.
This means that the carbon has 5 electrons now, despite it only usually having 4 valence electrons.
So oxidation state is 1-
After, when it is now an aldehyde,
In the double C=O bond, oxygen is more electronegative so will attract the two pairs of electrons away from the carbon.
Also, in the C-C bond they are equally electronegative so the electrons will be split evenly so one will go to the C.
In the C-H bond the C is more electronegative so will take the pair of electrons from the H.
So there are 3 valence electrons on the carbon when it usually has 4 so it has oxidation state +1
Carbon is bonded to the double oxygen, but oxygen is more electronegative so those two pairs
of electrons go to the oxygen
Carbon is bonded to another carbon so the electrons split equally and one goes to each carbon.
Carbon is bonded to oxygen again so pair of electrons go to oxygen.
This means there is one electron on the valence shell, compared to 4 usually so it has oxidation state +3.
As you can see, each time the molecule is oxidised, the oxidation state increases
Describe oxidation of alcohols:
What are primary alcohols oxidised into, what can they be further oxidised into
What are secondary alcohols oxidised into, what can they be further oxidised into
What about tertiary alcohols
Primary alcohols are combusted into aldehydes , which can then be further combusted into carboxylic acids
Secondary alcohols can be oxidised into ketones , but can’t be further oxidised
Tertiary alcohols are not easily oxidised
Why can primary alcohols be oxidised further but not secondary
- In order for it to be further oxidised, there has to be a carbon bonded to a H and the =O
- So in secondary alcohols, when they are first oxidised to ketones, the carbon is bonded to =O, and also two other carbons, so there are no hydrogens bonded to be oxidised
Describe oxidation of secondary alcohols
Eg in propan-2-ol
Give equation
. Oxidised to ketones
. So eg in propan-2-ol, the middle carbon is bonded to an OH, an H and two other carbons
. So when it is oxidised, a double carbon oxygen bond will form, so that carbon will only be bonded to the oxygen, and to two other carbons
The reaction is
Propan-2-ol arrow to propanone with an [O] over the arrow to show it has been oxidised
Why aren’t tertiary alcohols oxidised
Their oxidation would require a C-C bond to break, rather than a C-H bond like with primary and secondary alcohols
As there is no C-H bond to break
Describe the conditions and reaction for oxidation of primary alcohol
Eg ethanol to ethanol
NOT TO ETHANOIC ACID
. Potassium dichromate acidified by sulfuric acid, which is the oxidising agent
. If you don’t want it to oxidise completely to ethanoic acid, use dilute acid with slightly less potassium dichromate than is needed for complete oxidation
Ethanal has a lower boiling point than ethanoic acid
. Heat the mixture gently in distillation apparatus, with the receiver cooled in ice so the ethanal evaporates as soon as it is formed and can distill off.
This stops it getting oxidised further to ethanoic acid
The remaining mixture is unreacted ethanol