12.2 - Chemical reactions of the alkanes Flashcards

1
Q

Why don’t alkanes react with most common reagents?

A

C-C and C-H sigma bonds are strong
- C-C bonds are non-polar (same electronegativity)
Carbon and hydrogen have similar electronegativity so C-H is considered non polar

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2
Q

Describe the general reaction of alkanes with halogens

A

In the presence of sunlight (UV radiation to be precise)
A substitution reaction takes place

e.g. CH4 + Br2 > CH3Br + HBr

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3
Q

What is the mechanism for the reaction of halogens with alkanes called and state the 3 steps?

A

Free radical substitution

  1. Initiation
  2. Propagation 1, Propagation 2
  3. Termination
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4
Q

What occurs during initiation? (for these examples use Cl2)

A

Using UV radiation
The Cl2 covalent bond is broken by homolytic fission.
Forming 2 chlorine radicals - very reactive and have an unpaired electron

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5
Q

What occurs during propagation 1?

A

The Cl. (radical) reacts with the methane C-H bond forming a methyl radical and a HCl molecule.

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6
Q

What occurs during propagation 2?

A

The CH3. (radical) reacts with another Cl2 molecule, it forms another Cl. and CH3Cl

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7
Q

Why are the propagation steps known as chain reactions?

A

New radicals are constantly released which continue to react.

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8
Q

What occurs during the termination step?

A

Where any 2 radicals react
Possible combinations

Cl. + Cl. > Cl2
Cl. + CH3. > CH3Cl
CH3. + CH3. > C2H6

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9
Q

What are the limitations of radical substitution in organic synthesis?

A

Makes the desired haloalkane but also makes other unwanted products

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10
Q

What are the issues with further substitution?

A

CH3Cl may have formed in Propagation 2 but it may react with the Cl., forming CH3Cl2, and this can happen again and again, this means to get your desired product it requires further separation

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11
Q

If the carbon chain is long what could happen?

A

Substitution can occur at any point along the chain, meaning with further substitution you would get even more products

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