[12.2] chemical reactions of alkanes Flashcards
why are alkanes unreactive with most common reagents?
- C-C and C-H sigma bonds are strong (so difficult to lose electrons?)
- C-C bonds are non-polar (only have london forces)
- the electronegativity of carbon and hydrogen is so similar that the C-H bond can be considered to be non-polar
what is a combustion reaction?
when alkanes react with a plentiful supply of oxygen to produce carbon dioxide and water
- gives out heat
what is the equation for balancing a complete combustion reaction of any alkane?
CₓHᵧ + (x + y/4)O₂ -> xCO₂ + 0.5yH₂O
what happens during incomplete combustion?
- when oxygen is limited in combustion
- hydrogen is always oxidised to water
- combustion of carbon is incomplete, so forms soot (C) or carbon monoxide (CO) instead
how do alkanes react with halogens?
- in the presence of sunlight, alkanes react with halogens. the high-energy ultraviolet (UV) radiation present in sunlight provides the initial energy for a reaction to take place
- this can only happen with chlorine and bromine, as fluorine is too reactive and iodine is not reactive enough
what is free radical substitution?
when H atoms on alkanes or halogenalkanes are replace by halogen atoms
what are the 3 stages of free radical substitution?
- initiation
- propagation
- termination
what occurs during the initiation stage?
- reaction starts when the covalent bond in a halide molecule is broken by homolytic fission
- two halogen atom free radicals are produced
- energy for this bond fission is provided by UV radiation
- eg. F₂ -> 2F●
what occurs during the propagation stage?
(molecule + radical -> molecule + new radical)
- for every H that is replaced, there is one pair of propagation reactions
1. the alkane / halogenalkane reaction with the halide radical (eg. F●). this removed a H atom from the alkane / halogenalkane, which produces HF (eg.) and a C based free radical
2. the C based radical from step 1 reactions with F₂ (eg.) to put an atom of halide onto the C based radical. this also produces another halogen free radical (eg. F●) to continue the chain reaction in another step 1
what occurs during the termination stage?
(2 radicals -> molecule)
- if two free radicals collide, they will form a molecule and stop the chain reaction
- any two free radicals involved in the mechanism could collide in this way
example overall equation (methane + chlorine)
CH₄ + Cl₂ -> CH₃Cl +HCl
example of propagation reactions (methane + chlorine)
- CH₄ + Cl● -> ●CH₃ + HCl
- ●CH₃ + Cl₂ -> CH₃Cl + Cl●
example of termination reactions (methane + chlorine)
- Cl● + ●Cl -> Cl₂
- ●CH₃ + ●CH₃ -> CH₃-CH₃
- ●CH₃ + ●Cl -> CH₃Cl
limitations of free radical substitution
- further substitution results in a mixture of products eg. mono, di, tri, and tetra substituted products
- if the carbon chain is longer, we will get a mixture of monosubstituted isomers by substitution at different positions in the carbon chain (eg. pentane could form 3 monosubstituted isomers)